Problem 40
Question
The effect of eccentricity on a hyperbola's shape \(\mathrm{What}\) happens to the graph of a hyperbola as its eccentricity increases? To find out, rewrite the equation \(\left(x^{2} / a^{2}\right)-\left(y^{2} / b^{2}\right)=1\) in terms of \(a\) and \(e\) instead of \(a\) and \(b .\) Graph the hyperbola for various values of \(e\) and describe what you find.
Step-by-Step Solution
Verified Answer
As eccentricity increases, the hyperbola becomes wider and more open.
1Step 1: Understanding Hyperbola Eccentricity
The eccentricity of a hyperbola is denoted as \(e\) and is defined by the relationship \(e = \sqrt{1 + \frac{b^2}{a^2}}\). This formula indicates how much the conic section deviates from being a circle. A hyperbola's eccentricity is always greater than 1.
2Step 2: Expressing 'b' in Terms of 'a' and 'e'
Start with the eccentricity formula \(e = \sqrt{1 + \frac{b^2}{a^2}}\). To express \(b^2\) in terms of \(a\) and \(e\), rearrange to get \(b^2 = a^2(e^2 - 1)\). Substitute this expression into the hyperbola equation.
3Step 3: Rewriting Hyperbola Equation
Substitute \(b^2 = a^2(e^2 - 1)\) into the original equation \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\). This gives us: \[ \frac{x^2}{a^2} - \frac{y^2}{a^2(e^2-1)} = 1 \]. Simplify to obtain \[ (e^2 - 1)\frac{x^2}{a^2} - \frac{y^2}{a^2} = e^2 - 1 \].
4Step 4: Exploring Hyperbola Shape
Graph the hyperbola for different values of \(e\). As \(e\) increases, the branches of the hyperbola become steeper or more 'open'. For each graph, notice how increasing \(e\) increases the distance between the vertices and the foci, thus changing the shape of the hyperbola.
5Step 5: Conclusion on Hyperbola Shape
As the eccentricity \(e\) of a hyperbola increases, the branches become wider or more 'open'. This is due to the increasing distance between the vertices and focal points, which alters the curvature and orientation of the hyperbola's branches.
Key Concepts
EccentricityConic SectionsHyperbola EquationGraphing Hyperbolas
Eccentricity
Eccentricity is a crucial aspect of conic sections, particularly hyperbolas. It measures how much the conic deviates from being a perfect circle. For a hyperbola, the eccentricity, denoted as \( e \), is always greater than 1. This is because a hyperbola is an open curve, and the value of \( e \) tells us how 'stretched' or 'flattened' the hyperbola is.
\[ e = \sqrt{1 + \frac{b^2}{a^2}} \]
This formula links the standard parameters of the hyperbola, which are \( a \) and \( b \), to its eccentricity. The larger the value of \( e \), the more elongated the shape becomes. As \( e \) increases, the branches of the hyperbola become more open, with the vertices moving farther apart.
\[ e = \sqrt{1 + \frac{b^2}{a^2}} \]
This formula links the standard parameters of the hyperbola, which are \( a \) and \( b \), to its eccentricity. The larger the value of \( e \), the more elongated the shape becomes. As \( e \) increases, the branches of the hyperbola become more open, with the vertices moving farther apart.
Conic Sections
Conic sections are the curves obtained by cutting a cone with a plane. They include circles, ellipses, parabolas, and hyperbolas. Each has its own unique properties and equations, governed by their particular geometry.
- A hyperbola forms when the plane cuts through both nappes of the cone.
- It consists of two separate branches.
- These branches reflect its distinct geometric properties.
Hyperbola Equation
The standard equation for a hyperbola is expressed as:
\[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \]
Here, \( a \) and \( b \) define the shape and orientation of the hyperbola. When we delve deeper, we see that the relationship between \( a \), \( b \), and the eccentricity \( e \) provides essential insight. By substituting \( b^2 = a^2(e^2 - 1) \) into this equation, we adjust the parameters to represent the same hyperbola differently. This substitution allows us to understand the hyperbola because \( a \) and \( e \) directly control the geometry of its branches. The equation demonstrates how changes in \( b \) (and thus \( e \)) influence the shape and layout of the hyperbola.
\[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \]
Here, \( a \) and \( b \) define the shape and orientation of the hyperbola. When we delve deeper, we see that the relationship between \( a \), \( b \), and the eccentricity \( e \) provides essential insight. By substituting \( b^2 = a^2(e^2 - 1) \) into this equation, we adjust the parameters to represent the same hyperbola differently. This substitution allows us to understand the hyperbola because \( a \) and \( e \) directly control the geometry of its branches. The equation demonstrates how changes in \( b \) (and thus \( e \)) influence the shape and layout of the hyperbola.
Graphing Hyperbolas
Graphing hyperbolas involves plotting these curves based on their algebraic equations. Changes in their parameters, particularly eccentricity, dramatically affect their appearance.
When modifying \( e \):
When modifying \( e \):
- If \( e \) increases, the hyperbola's branches widen.
- The distance between its vertices and foci becomes larger.
- This results in a more open appearance.
Other exercises in this chapter
Problem 40
Find the points of intersection of the pairs of curves in Exercises \(39-42\) $$ r=1+\cos \frac{\theta}{2}, \quad r=1-\sin \frac{\theta}{2} $$
View solution Problem 40
The parabola \(x^{2}=-4 y\) is shifted left 1 unit and up 3 units to generate the parabola \((x+1)^{2}=-4(y-3)\) a. Find the new parabola's vertex, focus, and d
View solution Problem 40
Degenerate conics Does any nondegenerate conic section \(A x^{2}+B x y+C y^{2}+D x+E y+F=0\) have all of the following properties? a. It is symmetric with respe
View solution Problem 41
The ellipse \(\left(x^{2} / 16\right)+\left(y^{2} / 9\right)=1\) is shifted 4 units to the right and 3 units up to generate the ellipse $$\frac{(x-4)^{2}}{16}+\
View solution