Problem 40
Question
Solve the equation (if possible). $$\frac{2}{x(x-2)}+\frac{5}{x}=\frac{1}{x-2}$$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = 2\). However, substituting \(x = 2\) back into the original equation leads to division by zero in the terms. So, this equation has no solution.
1Step 1 - Find common denominator
Identify the common denominator, which in this case, is \(x(x-2)\). So, we convert all the fractions to have this common denominator.
2Step 2 - Rewrite the equation
Rewrite the original equation by changing each term to the equivalent fraction with the common denominator \(x(x-2)\):\n\( \frac{2}{x(x-2)} + \frac{5(x-2)}{x(x-2)} = \frac{x}{x(x-2)} \).
3Step 3 - Simplify equation
To eliminate the fractions, multiply every term with common denominator \(x(x-2)\), which results in \n\(2 + 5(x - 2) = x\). After simplification, this yields the equation \(5x - 8 = x\).
4Step 4 - Solve the equation
Move x on the right side over to left side to have equation in standard form\(4x - 8 = 0\). Solve the equation for \(x\), we get \(x = 2\).
5Step 5 - Check the solutions
Substitute \(x = 2\) back into the original equation and see if the equation holds, if needed.
Key Concepts
Common DenominatorEquation SimplificationFractions in AlgebraAlgebraic Expressions
Common Denominator
When solving equations with multiple fractions, it's crucial to find a common denominator, which is a shared multiple of the denominators of these fractions. This commonality allows us to combine the fractions and simplify the equation. Think of it as finding a common ground for all fractions involved.
In the provided exercise, the common denominator is identified as the product of the unique factors from each term's denominator, which is \(x(x-2)\). By ensuring each fraction has this common denominator, we facilitate the addition or subtraction of the fractions, setting the stage for the next steps of solving the equation.
In the provided exercise, the common denominator is identified as the product of the unique factors from each term's denominator, which is \(x(x-2)\). By ensuring each fraction has this common denominator, we facilitate the addition or subtraction of the fractions, setting the stage for the next steps of solving the equation.
Equation Simplification
Equation simplification is the process of reducing an equation to a simpler or more efficient form. This often involves combining like terms, eliminating fractions, and clearing out parentheses. Simplifying an equation makes it more approachable and easier to solve.
In our exercise, after finding a common denominator, we multiply each term by that denominator to clear the fractions. This leaves us with a simplified equation: \(5x - 8 = x\). This step is essential, as it transforms a complex fractional equation into a simple linear equation, bringing us closer to finding the value of \(x\).
In our exercise, after finding a common denominator, we multiply each term by that denominator to clear the fractions. This leaves us with a simplified equation: \(5x - 8 = x\). This step is essential, as it transforms a complex fractional equation into a simple linear equation, bringing us closer to finding the value of \(x\).
Fractions in Algebra
Dealing with fractions in algebra can be tricky, but understanding how to manipulate them is a valuable skill. When fractions appear in algebraic equations, it's often helpful to eliminate them early on. This can be done by finding a common denominator and multiplying the entire equation by this common denominator.
By doing so in our example, the problematic fractions are removed, leaving behind an algebraic expression that is easier to manage. Remember, the key in algebra is to simplify whenever possible to reduce the chances of errors in computation.
By doing so in our example, the problematic fractions are removed, leaving behind an algebraic expression that is easier to manage. Remember, the key in algebra is to simplify whenever possible to reduce the chances of errors in computation.
Algebraic Expressions
Algebraic expressions consist of numbers, variables, and arithmetic operations. In the context of solving equations, algebraic expressions can become complex when they involve fractions. Simplifying these expressions, as we do in the elimination of fractions, can reveal a clearer path to the solution.
In the case of the exercise, once the fractions are eliminated, we are left with a linear algebraic expression. We can then use basic algebraic methods, such as isolating the variable, to solve the equation. Understanding how to manipulate these expressions is fundamental to mastering algebra.
In the case of the exercise, once the fractions are eliminated, we are left with a linear algebraic expression. We can then use basic algebraic methods, such as isolating the variable, to solve the equation. Understanding how to manipulate these expressions is fundamental to mastering algebra.
Other exercises in this chapter
Problem 40
Solve the equation algebraically. Then write the equation in the form \(f(x)=0\) and use a graphing utility to verify the algebraic solution. $$(x+1)^{2}+2(x-2)
View solution Problem 40
Perform the operation and write the result in standard form. $$-3 i(6-i)$$
View solution Problem 41
Solving an Equation Involving Rational Exponents Find all solutions of the equation algebraically. Check your solutions. $$(x-9)^{2 / 3}=25$$
View solution Problem 41
Solve the inequality and sketch the solution on the real number line. Use a graphing utility to verify your solutions graphically. $$|x-7| \leq 6$$
View solution