Problem 40
Question
Solve each equation. See Example 3. $$ \left|\frac{1}{9} x+4\right|+25=25 $$
Step-by-Step Solution
Verified Answer
The solution is \( x = -36 \).
1Step 1: Simplify the Equation
The given equation is \( \left| \frac{1}{9}x + 4 \right| + 25 = 25 \). Begin by subtracting 25 from both sides to isolate the absolute value expression. \[ \left| \frac{1}{9}x + 4 \right| + 25 - 25 = 25 - 25 \]This simplifies to: \[ \left| \frac{1}{9}x + 4 \right| = 0 \]
2Step 2: Solve for the Absolute Value
The equation \( \left| \frac{1}{9}x + 4 \right| = 0 \) means that the expression inside the absolute value must also be zero. Therefore, we set the expression equal to zero: \[ \frac{1}{9}x + 4 = 0 \]
3Step 3: Isolate x in the Equation
Subtract 4 from both sides to isolate the term with x:\[ \frac{1}{9}x = -4 \]Next, multiply both sides by 9 to solve for \( x \): \[ x = -4 \times 9 \]\[ x = -36 \]
4Step 4: Verify the Solution
Substitute \( x = -36 \) back into the original absolute value equation to verify the solution.Calculate \( \frac{1}{9}(-36) + 4 \):\[ \frac{1}{9}(-36) + 4 = -4 + 4 = 0 \]Since the absolute value of 0 is 0, the original equation holds:\[ \left| 0 \right| + 25 = 25 \] So, the solution \( x = -36 \) is correct.
Key Concepts
Solving EquationsIsolation of VariablesVerification of Solutions
Solving Equations
In the realm of mathematics, solving equations is a fundamental skill, especially when it comes to dealing with absolute value equations. An equation's solution involves finding the value of the unknown variable that makes the equation true. In our exercise, we started with an absolute value equation:
- \( \left| \frac{1}{9}x + 4 \right| + 25 = 25 \)
- \( \left| \frac{1}{9}x + 4 \right| = 0 \)
- The result is the simple statement \( \frac{1}{9}x + 4 = 0 \).
Isolation of Variables
The isolation of variables is a powerful technique in solving equations. It involves manipulating the equation in such a way that we progressively "isolate" the variable we want to solve for. Moving forward from the simplified equation \( \frac{1}{9}x + 4 = 0 \), we need to zero in on \( x \). First, we remove the constant term:
- Subtract 4 from both sides to yield \( \frac{1}{9}x = -4 \).
- Multiply both sides by 9 to counteract the \( \frac{1}{9} \).
- This results in \( x = -36 \).
Verification of Solutions
Verification of solutions is an essential final step in solving equations. It ensures the accuracy of the solution by substituting it back into the original equation to check consistency.
In our example, the solution obtained was \( x = -36 \). Now, verify by substituting back into the original setup:
In our example, the solution obtained was \( x = -36 \). Now, verify by substituting back into the original setup:
- Calculate \( \frac{1}{9}(-36) + 4 \) to confirm the solution.
- This simplifies to \( -4 + 4 = 0 \).
- \( \left| 0 \right| + 25 = 25 \), which proves correct.
Other exercises in this chapter
Problem 39
Solve each compound inequality. Graph the solution set and write it using interval notation. \(x-3
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Graph each inequality. $$ x
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Graph the solution set of each system of inequalities on a rectangular coordinate system. $$\left\\{\begin{array}{l}x \leq 3 \\\x \geq 3\end{array}\right.$$
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Solve each compound inequality. Graph the solution set and write it using interval notation. \(4 x4\)
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