Problem 40
Question
Solve each equation for the indicated variable. \(3 x-2 y=-1 \quad\) for \(y\)
Step-by-Step Solution
Verified Answer
The solution for \(y\) is: \(y = \frac{3}{2}x + \frac{1}{2}\).
1Step 1: Isolate terms involving y
Start with the equation: \[ 3x - 2y = -1 \]To isolate the terms involving \(y\), move the \(3x\) term to the right side of the equation by subtracting \(3x\) from both sides of the equation:\[ -2y = -1 - 3x \]
2Step 2: Solve for y
To solve for \(y\), divide every term in the equation by \(-2\) (the coefficient of \(y\)):\[ y = \frac{-1 - 3x}{-2} \]
3Step 3: Simplify the expression
Simplify the expression by dividing each term in the numerator by \(-2\):\[ y = \frac{-1}{-2} + \frac{-3x}{-2} \]This simplifies to:\[ y = \frac{1}{2} + \frac{3}{2}x \]Or, rewritten clearly:\[ y = \frac{3}{2}x + \frac{1}{2} \]
Key Concepts
Isolating VariablesSolving for yLinear Equations
Isolating Variables
The art of isolating variables is an essential skill in algebra, enabling you to solve equations effectively. When you want to isolate a specific variable, you need to move all other terms to the opposite side of the equation. Think of it as rearranging the equation so that the variable stands alone on one side.
This generally involves using inverse operations like addition, subtraction, multiplication, or division. For example:
This generally involves using inverse operations like addition, subtraction, multiplication, or division. For example:
- If a term is added, subtract it from both sides.
- If a term is multiplied, divide every term by that coefficient.
Solving for y
Once you have isolated the variable, the next step is crucial: solving for \(y\). This involves making \(y\) the subject of the formula, i.e., \(y\) should be expressed in terms of other variables or constants. In the exercise, the equation following isolation is \(-2y = -1 - 3x\). To get \(y\) all by itself, divide every term by \(-2\), the coefficient of \(y\): \[ y = \frac{-1 - 3x}{-2} \]After dividing, simplify each term separately:
- \(\frac{-1}{-2} = \frac{1}{2}\)
- \(\frac{-3x}{-2} = \frac{3}{2}x\)
Linear Equations
Linear equations are the foundation of algebra. These equations form straight lines when graphed on the coordinate plane, and they conform to the standard form \(ax + by = c\). They are straightforward yet powerful, representing numerous real-world relationships.In our example, the original equation \(3x - 2y = -1\) is a linear equation. Solving it for \(y\) results in the slope-intercept form \(y = mx + b\), which is quite advantageous:
- The \(m\) value, \(\frac{3}{2}\), is the slope of the line.
- The \(b\) value, \(\frac{1}{2}\), is the y-intercept, showing where the line crosses the y-axis.
Other exercises in this chapter
Problem 40
Solve each compound inequality and graph the solution sets. Express the solution sets in interval notation. \(3 x+2>17 \quad\) and \(\quad x \geq 0\)
View solution Problem 40
Express each interval as an inequalit using the variable \(x\). For example, we can express the inter val \([5, \infty)\) as \(x \geq 5\). \(6 x-4 \leq 5 x-4\)
View solution Problem 40
Solve each equation. A textbook costs a bookstore \(\$ 45\), and the store sells it for \(\$ 60\). Find the rate of profit based on the selling price.
View solution Problem 40
Solve each equation. \(2 x+5+\frac{1}{2}(6 x-1)=-\frac{1}{2}\)
View solution