Problem 40
Question
Solve each equation, and check the solution. If applicable, tell whether the equation is an identity or a contradiction. \(-2 x-3(4-2 x)=2(x-3)+2\)
Step-by-Step Solution
Verified Answer
The solution is x = 4, and the equation is neither an identity nor a contradiction.
1Step 1: Distribute and Simplify
Distribute -3 into the parenthesis: -2x - 3(4 - 2x) = -2x - 12 + 6x On the right-hand side: 2(x-3) + 2 = 2x - 6 + 2
2Step 2: Combine like terms
Combine like terms on both sides of the equation: 4x - 12 = 2x - 4
3Step 3: Move variable terms to one side
Subtract 2x from both sides to isolate the x-term: 4x - 2x - 12 = 2x - 2x - 4 2x - 12 = -4
4Step 4: Isolate the variable
Add 12 to both sides to isolate x: 2x - 12 + 12 = -4 + 12 2x = 8
5Step 5: Solve for x
Divide both sides by 2 to solve for x: x = 4
6Step 6: Check the solution
Substitute x = 4 back into the original equation to verify the solution: -2(4) - 3(4-2(4)) = 2(4-3) + 2 -8 - 3(4 - 8) = 2 + 2 -8 - 3(-4) = 4 -8 + 12 = 4 4 = 4. The original equation holds true, so x = 4 is a solution.
7Step 7: Identify the type of equation
Since there is one solution, the equation is neither an identity nor a contradiction.
Key Concepts
The Distributive Property in AlgebraCombining Like TermsIsolation of Variables
The Distributive Property in Algebra
One foundational concept in algebra is the distributive property, which helps you simplify expressions and equations. It states that multiplying a sum by a number is the same as multiplying each addend by the number and then adding the products.
In mathematical terms, the distributive property is: \[ a(b + c) = ab + ac \].
For example, in the exercise, we are dealing with distribution on the left-hand side:
-\(2 x-3(4-2 x)\).
To apply the distributive property here, we multiply -3 by both 4 and -2x:
\[ -3(4) + (-3)(-2x) = -12 + 6x \].
This helps to open up the parentheses and simplify the equation, making it easier to combine like terms, which is our next step.
Remember:
- Use the distributive property to eliminate parentheses in your equations.
- Carefully multiply each term inside the parentheses by the factor outside.
In mathematical terms, the distributive property is: \[ a(b + c) = ab + ac \].
For example, in the exercise, we are dealing with distribution on the left-hand side:
-\(2 x-3(4-2 x)\).
To apply the distributive property here, we multiply -3 by both 4 and -2x:
\[ -3(4) + (-3)(-2x) = -12 + 6x \].
This helps to open up the parentheses and simplify the equation, making it easier to combine like terms, which is our next step.
Remember:
- Use the distributive property to eliminate parentheses in your equations.
- Carefully multiply each term inside the parentheses by the factor outside.
Combining Like Terms
Once you've applied the distributive property, your next step usually involves combining like terms. In algebra, 'like terms' are terms that have the same variable raised to the same power. For example, 3x and 5x are like terms because both terms contain the variable x raised to the first power.
In our exercise: \[-2x - 12 + 6x = 2x - 6 + 2\],
we can combine -2x with 6x and -12 with -6 and 2:
\[-2x + 6x - 12 = 4x - 12\]
and,
\[2x - 6 + 2 = 2x - 4\].
So after combining like terms on both the left-hand side and the right-hand side, our expression looks simpler:
\[4x - 12 = 2x - 4\].
Combining like terms streamlines our equations and makes it easier to isolate the variable.
In our exercise: \[-2x - 12 + 6x = 2x - 6 + 2\],
we can combine -2x with 6x and -12 with -6 and 2:
\[-2x + 6x - 12 = 4x - 12\]
and,
\[2x - 6 + 2 = 2x - 4\].
So after combining like terms on both the left-hand side and the right-hand side, our expression looks simpler:
\[4x - 12 = 2x - 4\].
Combining like terms streamlines our equations and makes it easier to isolate the variable.
Isolation of Variables
The final core concept in solving linear equations is the isolation of variables. This means getting the variable you are solving for all by itself on one side of the equation. This typically involves a few steps:
1. Move variable terms to one side of the equation.
2. Move constant terms to the other side.
3. Simplify the equation to solve for the variable.
Using our example, after combining like terms, we have:
\[4x - 12 = 2x - 4\].
Let's isolate x by moving all x terms to one side and constants to the other:
Subtract 2x from both sides:
\[4x - 2x - 12 = 2x - 2x - 4\],
which simplifies to:
\[2x - 12 = -4\].
Next, add 12 to both sides to isolate 2x:
\[2x - 12 + 12 = -4 + 12\],
which simplifies to:
\[2x = 8\].
Finally, divide both sides by 2:
\[x = 4\].
By isolating the variable, you achieve the simplest form of the problem, making it easy to find the solution.
1. Move variable terms to one side of the equation.
2. Move constant terms to the other side.
3. Simplify the equation to solve for the variable.
Using our example, after combining like terms, we have:
\[4x - 12 = 2x - 4\].
Let's isolate x by moving all x terms to one side and constants to the other:
Subtract 2x from both sides:
\[4x - 2x - 12 = 2x - 2x - 4\],
which simplifies to:
\[2x - 12 = -4\].
Next, add 12 to both sides to isolate 2x:
\[2x - 12 + 12 = -4 + 12\],
which simplifies to:
\[2x = 8\].
Finally, divide both sides by 2:
\[x = 4\].
By isolating the variable, you achieve the simplest form of the problem, making it easy to find the solution.
Other exercises in this chapter
Problem 40
The distance from Melbourne to London is \(10,500 \mathrm{mi}\). If a jet averages 500 mph between the two cities, what is its travel time in hours?
View solution Problem 40
Solve each inequality. Graph the solution set, and write it using interval notation. $$ |-2 x-4| \geq 5 $$
View solution Problem 41
Solve each problem. In \(2015,\) the number of graduating seniors taking the ACT exam was \(1,924,436 .\) In 2011 . a total of 1,617,173 graduating seniors took
View solution Problem 41
As of 2017 , the highest temperature ever recorded in the state of Washington was \(42^{\circ} \mathrm{C}\). Find the corresponding Fahrenheit temperature to th
View solution