Problem 40
Question
Simplify the expression. $$ \frac{b^{2}+1}{b^{2}-1} \cdot \frac{b-1}{b+1} $$
Step-by-Step Solution
Verified Answer
\(\frac{b^2+1}{(b+1)^2}\).
1Step 1: Identify Factoring Opportunities
We begin by looking for factoring opportunities in the expression. Notice that the denominator of the first fraction, \(b^2-1\), can be factored using the difference of squares identity: \(b^2 - 1 = (b-1)(b+1)\). This will help in simplifying the expression.
2Step 2: Rewrite the Expression
Factor \(b^2-1\) in the first fraction to rewrite the expression:\[\frac{b^{2}+1}{(b-1)(b+1)} \cdot \frac{b-1}{b+1}.\]
3Step 3: Simplify by Multiplying
Multiply the fractions by multiplying the numerators and the denominators:\[\frac{(b^2+1)(b-1)}{((b-1)(b+1))(b+1)}.\]
4Step 4: Eliminate Common Factors
Cancel the common factor \(b-1\) from the numerator and the \(b-1\) term in the denominator, and \(b+1\) (present in the factor) from both numerator and denominator:\[\frac{b^2+1}{(b+1)^2}.\]
5Step 5: Final Simplified Form
The expression is now simplified to:\[\frac{b^2+1}{(b+1)^2}.\] There are no further simplifications possible since no common factors remain.
Key Concepts
Factoring in AlgebraRational ExpressionsDifference of Squares
Factoring in Algebra
Factoring in algebra is an essential skill for simplifying expressions and solving equations. It involves breaking down complex algebraic expressions into a product of simpler factors. Factors are expressions that, when multiplied together, reconstruct the original expression.
- One common method is factoring the difference of squares, where square terms are separated by a subtraction operation, such as in the expression \(b^2 - 1\), which can be simplified using the formula \(a^2 - b^2 = (a-b)(a+b)\).
- Identifying common factors across terms is crucial. Spotting these can make expressions easier to handle and solve.
Rational Expressions
Rational expressions are fractions where the numerator and the denominator are polynomials. Simplifying rational expressions involves making them as simple as possible by factoring and reducing.
- Both the numerator and the denominator should be considered for common factors. If there are any, they can be cancelled, resulting in a simpler fraction.
- Simplifying rational expressions can involve both algebraic manipulations and some arithmetic skills, including recognizing common patterns like factoring opportunities.
Difference of Squares
The difference of squares is an algebraic technique used to simplify expressions or solve equations. It applies when two squared terms are separated by a subtraction sign. The form is \(a^2 - b^2\) and it always factors into \((a - b)(a + b)\).
- This method is a special case of factoring polynomials that allows for quick simplification.
- The recognition of difference of squares is powerful when simplifying rational expressions or finding roots in equations.
Other exercises in this chapter
Problem 40
Factor the expression completely. \(z^{2}+15 z+54\)
View solution Problem 40
If possible, simplify the expression by hand. If you cannot, approximate the answer to the nearest hundredth. Variables represent any real number. $$ \sqrt[4]{6
View solution Problem 41
Subtract the polynomials. $$\left(x^{4}-1\right)-\left(4 x^{4}+3 x+7\right)$$
View solution Problem 41
Exercises 35-44: Use the product rule to simplify. $$ 5^{-2} \cdot 5^{3} \cdot 2^{-4} \cdot 2^{3} $$
View solution