Problem 40
Question
Many areas of Northern California depend on the snowpack of the Sierra Nevada Mountains for their water supply. If 250 cubic centimeters of snow will melt to 28 cubic centimeters of water, how much water does 900 cubic centimeters of snow produce?
Step-by-Step Solution
Verified Answer
900 cc of snow produces 100.8 cc of water.
1Step 1: Understanding the Problem
The problem involves finding out how much water can be produced from a given volume of snow. We know that 250 cubic centimeters (cc) of snow melts into 28 cc of water.
2Step 2: Setting Up a Proportion
We need to figure out the relationship between snow and water for the given amounts. The proportion can be set as \( \frac{250}{28} = \frac{900}{x} \), where \(x\) is the amount of water from 900 cc of snow.
3Step 3: Cross-multiplication
To solve the proportion \( \frac{250}{28} = \frac{900}{x} \), we cross-multiply: \( 250 \times x = 28 \times 900 \).
4Step 4: Solving for Unknown
Calculate the product of the numbers on the right side: \( 28 \times 900 = 25200 \). Now solve for \(x\): divide by 250, \( x = \frac{25200}{250} \).
5Step 5: Calculating Final Value
Performing the division, \( x = 100.8 \). Therefore, 900 cubic centimeters of snow will produce 100.8 cubic centimeters of water.
Key Concepts
Cross-MultiplicationRatiosSnowpack Water Conversion
Cross-Multiplication
Cross-multiplication is a valuable technique used primarily to solve proportions. A proportion is an equation that states two ratios are equivalent. To apply cross-multiplication, you multiply across the equal sign in an 'X' pattern. Consider a proportion set up as \( \frac{a}{b} = \frac{c}{d} \). Cross-multiplication helps to eliminate fractions: you multiply \( a \) by \( d \) and \( b \) by \( c \), resulting in \( a \cdot d = b \cdot c \). This method is efficient and easy to use, making it popular in finding unknown values in a proportion.
- Simplifies solving proportions
- Eliminates fraction operations
- Directly compares related quantities
Ratios
Ratios express the relationship between two quantities, demonstrating how many times one value contains or is contained within the other. They are typically written as \( \frac{a}{b} \) or using colon notation as \( a:b \). Ratios are fundamental in solving problems involving proportions, as they allow comparisons and scaling between different items or scenarios.In our context, the problem states that 250 cubic centimeters of snow correlates to 28 cubic centimeters of water. This is a ratio of the volume of snow to water, 250:28. When solving real-world problems like snowpack conversion, such ratios help us understand the quantities involved.
- Helps compare related items
- Used to solve proportion problems
- Crucial for understanding scaling and conversion
Snowpack Water Conversion
Snowpack water conversion refers to calculating the amount of water obtained from melting a specific volume of snow. This process involves understanding the relationship between snow and water, which naturally involves the concept of proportions and ratios. In areas like Northern California, knowing how much water is derived from snowpacks is vital, often influencing water resource management and planning.
Why is this important? As snow is less dense than water, it takes a larger volume of snow to yield a small amount of water. Thus, converting snow volume to water volume gives practical insights into water supply.
- Essential for water resource planning
- Engages scientific and mathematical concepts
- Relevant in climate and environmental studies
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Problem 40
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