Problem 40
Question
Make a conjecture about the derivative by calculating the first few derivatives and observing the resulting pattern. $$\frac{d^{100}}{d x^{100}}[\cos x]$$
Step-by-Step Solution
Verified Answer
The 100th derivative of \( \cos x \) is \( \cos x \).
1Step 1: Understand the Function
We have the function \( \cos x \) for which we need to calculate the 100th derivative. Understanding the sequence of derivatives is key to this problem.
2Step 2: Calculate the First Derivative
The first derivative of \( \cos x \) with respect to \( x \) is \( \frac{d}{dx} [\cos x] = -\sin x \).
3Step 3: Calculate the Second Derivative
The second derivative is found by differentiating \(-\sin x\). We have \( \frac{d^2}{dx^2} [\cos x] = -\cos x \).
4Step 4: Calculate the Third Derivative
The third derivative is \( \frac{d^3}{dx^3} [\cos x] = \sin x \), obtained by differentiating \(-\cos x\).
5Step 5: Calculate the Fourth Derivative
The fourth derivative, by differentiating \( \sin x \), is \( \frac{d^4}{dx^4} [\cos x] = \cos x \).
6Step 6: Identify the Pattern
Observe that the derivatives repeat every four steps: \[ \cos x, -\sin x, -\cos x, \sin x, \cos x, \ldots \]
7Step 7: Derive the 100th Derivative
Since the derivatives repeat every four steps, the 100th derivative corresponds to the same cycle position as the fourth derivative, which is \( \cos x \).
Key Concepts
Higher Order DerivativesTrigonometric FunctionsCalculus Problems
Higher Order Derivatives
When dealing with higher order derivatives, we extend the concept of derivatives beyond the first and second derivatives to the nth derivative. This exploration allows us to understand the behavior and patterns in the changes of a function.
Higher order derivatives are crucial because they help us comprehend the deeper properties of a function. For instance, in physics, the second derivative relates to acceleration, while higher derivatives can provide insights into how acceleration itself is changing.
Calculating higher order derivatives often involves identifying patterns in earlier derivatives, as many functions produce cyclical outputs when differentiated multiple times. Such patterns can dramatically simplify our calculations, especially when finding very high order derivatives, like the hundredth derivative.
To compute these efficiently, we focus initially on the first few derivatives to spot any cycle or repetition, which tells us how the derivatives behave over several iterations.
Trigonometric Functions
Trigonometric functions such as sine and cosine are fundamental in calculus, given their periodic properties and derivative patterns. The derivative pattern of trigonometric functions is especially noteworthy for its repetitiveness:
- The derivative of \( \cos x \) is \(-\sin x \).
- The derivative of \(-\sin x\) is \(-\cos x \).
- Continuing, the derivative of \(-\cos x\) is \(\sin x\).
- Finally, the derivative of \(\sin x\) returns to \(\cos x\).
Calculus Problems
Solving calculus problems involves applying various strategies and recognizing patterns within functions. For higher order derivatives, recognizing these patterns allows for solving complex problems efficiently.One common approach is conjecturing based on empirical observations from initial calculations. By evaluating the first few derivatives, we can often identify cyclical behavior. This approach is particularly effective with trigonometric functions due to their repetitive nature. When faced with determining a derivative like the 100th of \(\cos x\), knowing the cyclicality of the derivatives helps streamline the process. Instead of calculating all 100 derivatives, understanding the cycle lets us conclude the 100th derivative is simply \(\cos x\), mirroring the 4th position in the cycle.This method of solving calculus problems showcases the power of recognizing patterns, allowing for efficient solutions and deeper insights into functional behaviors.
Other exercises in this chapter
Problem 40
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