Problem 40
Question
List, but do not test, all possible rational zeros of $$ f(x)=24 x^{3}-14 x^{2}+36 x+105. $$
Step-by-Step Solution
Verified Answer
Possible rational zeros are combinations of factors of 105 divided by factors of 24.
1Step 1: Understand the Rational Root Theorem
The Rational Root Theorem states that for a polynomial \( f(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_0 \), any rational solution \( \frac{p}{q} \) of the equation is such that \( p \) is a factor of the constant term \( a_0 \) and \( q \) is a factor of the leading coefficient \( a_n \).
2Step 2: Identify Constant and Leading Coefficient
For the polynomial \( f(x) = 24x^3 - 14x^2 + 36x + 105 \), the constant term \( a_0 \) is 105, and the leading coefficient \( a_n \) is 24.
3Step 3: List Factors of the Constant Term
The constant term \( 105 \) has factors: \( \pm 1, \pm 3, \pm 5, \pm 7, \pm 15, \pm 21, \pm 35, \pm 105 \).
4Step 4: List Factors of the Leading Coefficient
The leading coefficient \( 24 \) has factors: \( \pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm 8, \pm 12, \pm 24 \).
5Step 5: Form All Possible Rational Zeros
Using the Rational Root Theorem, form possible rational zeros as \( \frac{p}{q} \), where \( p \) is any factor of 105 and \( q \) is any factor of 24. The set of all possible rational zeros includes fractions like \( \pm \frac{1}{1}, \pm \frac{3}{2}, \pm \frac{5}{3}, ..., \pm \frac{35}{12}, \pm \frac{105}{24} \). List down each possibility.
Key Concepts
Polynomial FunctionsRational ZerosFactors of Coefficients
Polynomial Functions
Polynomial functions are mathematical expressions involving a sum of powers of the variable with constant coefficients. In simpler terms, they are equations that feature variables raised to whole number powers and do not contain division by variables. Common forms of polynomial functions include linear, quadratic, cubic, and higher-degree functions. They can be expressed as: \[ f(x) = a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \] where each \( a_i \) represents a coefficient and \( n \) is the degree of the polynomial, which tells you the highest power of \( x \) in the polynomial.
- The degree of a polynomial determines its general shape and behavior as the variable value increases or decreases.
- Polynomial functions are smooth and continuous, meaning they have no breaks, holes, or sharp corners.
Rational Zeros
The Rational Root Theorem is a fundamental tool to find potential rational zeros (roots) of a polynomial. A rational number is any number that can be expressed as the fraction \( \frac{p}{q} \) where \( p \) and \( q \) are integers and \( q eq 0 \). Using this theorem, we can identify possible rational roots for a polynomial function by examining the factors of the constant term and the leading coefficient.
- The constant term \( a_0 \) provides the list of potential numerators (\( p \)).
- The leading coefficient \( a_n \) provides the list of potential denominators (\( q \)).
Factors of Coefficients
Finding rational zeros using the Rational Root Theorem involves understanding the factors of the constant term and the leading coefficient of the polynomial. To illustrate:
- Let's consider the polynomial \( f(x) = 24x^3 - 14x^2 + 36x + 105 \).
- The constant term \( a_0 = 105 \) has factors \( \pm 1, \pm 3, \pm 5, \pm 7, \pm 15, \pm 21, \pm 35, \pm 105 \).
- The leading coefficient \( a_n = 24 \) has factors \( \pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm 8, \pm 12, \pm 24 \).
Other exercises in this chapter
Problem 40
Use synthetic division and the Remainder Theorem to find \(f(c)\) for the given value of c. $$ f(x)=x^{7}-3 x^{5}+2 x^{3}-x+10 ; c=5 $$
View solution Problem 40
Find a rational function that satisfies the given conditions. There is no unique answer. vertical asymptote: \(x=4\) slant asymptote: \(y=x+2\)
View solution Problem 40
Find the zeros of the given polynomial function \(f .\) State the multiplicity of each zero. $$ f(x)=x^{4}+6 x^{3}+9 x^{2} $$
View solution Problem 41
In Problems 41 and \(42,\) use long division to find a value of \(k\) such that \(f(x)\) is divisible by \(d(x)\). $$ f(x)=x^{4}+x^{3}+3 x^{2}+k x-4 ; d(x)=x^{2
View solution