Problem 40
Question
Let \(A\) and \(B\) be \(4 \times 4\) matrices such that \(\operatorname{det}(A)=5\) and \(\operatorname{det}(B)=3 .\) Compute the determinant of the given matrix. $$(2 B)^{-1}(A B)^{T}$$
Step-by-Step Solution
Verified Answer
The determinant of the given matrix is \(\frac{5}{16}\).
1Step 1: Compute the determinant of (2B)
First, we need to find the determinant of the matrix (2B). Recall that when multiplying a matrix by a scalar, the determinant of the new matrix is the product of the scalar raised to the power of the matrix size (n) and the determinant of the original matrix:
\[\operatorname{det}(cM) = c^n \operatorname{det}(M)\]
Here, the matrix B has a size of 4x4, and the scalar is 2. So:
\[\operatorname{det}(2B) = 2^4 \operatorname{det}(B) = 2^4 \cdot 3\]
2Step 2: Compute determinant of (2B)^{-1}
Now, we should find the determinant of the inverse of (2B). Recall that the determinant of the inverse matrix is equal to the reciprocal of the determinant of the original matrix:
\[\operatorname{det}(M^{-1}) = \frac{1}{\operatorname{det}(M)}\]
Here, our original matrix is 2B, so:
\[\operatorname{det}((2B)^{-1}) = \frac{1}{\operatorname{det}(2B)} = \frac{1}{2^4 \cdot 3}\]
3Step 3: Compute determinant of (AB)
For the next step, we will find the determinant of the product AB. Recall the product rule for determinants:
\[\operatorname{det}(AB) = \operatorname{det}(A) \cdot \operatorname{det}(B)\]
Here, we were given det(A) = 5 and det(B) = 3. So:
\[\operatorname{det}(AB) = 5 \cdot 3\]
4Step 4: Compute the determinant of (AB)^T
Now, we need to find the determinant of the transpose of AB. Recall that the determinant of a transposed matrix is equal to the determinant of the original matrix:
\[\operatorname{det}(M^T) = \operatorname{det}(M)\]
Here, our original matrix is AB, so:
\[\operatorname{det}((AB)^T) = \operatorname{det}(AB) = 5 \cdot 3\]
5Step 5: Compute determinant of (2B)^{-1}(AB)^T
Finally, we will find the determinant of the product (2B)^{-1}(AB)^T. Using the determinant product rule again,
\[\operatorname{det}((2B)^{-1}(AB)^T) = \operatorname{det}((2B)^{-1}) \cdot \operatorname{det}((AB)^T) = \frac{1}{2^4 \cdot 3} \cdot (5 \cdot 3)\]
Calculating the final product, we have:
\[ \operatorname{det}((2B)^{-1}(AB)^T) = \frac{5}{2^4} \]
So the determinant of the given matrix is \(\frac{5}{16}\).
Key Concepts
Matrix MultiplicationTranspose of a MatrixInverse of a MatrixScalar Multiplication of Matrices
Matrix Multiplication
Matrix multiplication is a fundamental concept in linear algebra and involves combining two matrices to produce another matrix. To multiply two matrices, the number of columns in the first matrix must match the number of rows in the second matrix. Each element of the resulting matrix is calculated by taking the dot product of the corresponding row of the first matrix and the corresponding column of the second matrix.
To illustrate this, let's consider two matrices, A and B:
To illustrate this, let's consider two matrices, A and B:
- A is a matrix with dimensions \(m \times n\).
- B is a matrix with dimensions \(n \times p\).
- The product, AB, will be a matrix with dimensions \(m \times p\).
Transpose of a Matrix
The transpose of a matrix is an operation that flips a matrix over its diagonal, swapping the row and column indices of each element. When you transpose a matrix, the rows become columns and vice versa.
For example, if you have a matrix A:
For example, if you have a matrix A:
- Row 1: [1, 2, 3]
- Row 2: [4, 5, 6]
- Column 1: [1, 4]
- Column 2: [2, 5]
- Column 3: [3, 6]
Inverse of a Matrix
The inverse of a matrix A, denoted as \( A^{-1} \), is a matrix that, when multiplied by A, results in the identity matrix. Only square matrices (those with the same number of rows and columns) can have inverses. For a matrix to have an inverse, its determinant must be non-zero.
Here's how you can think about it:
Here's how you can think about it:
- If \(A \cdot A^{-1} = I\), where I is the identity matrix, then \(A^{-1}\) is the inverse of A.
- The formula for finding an inverse involves the matrix's determinant: \( \operatorname{det}(A^{-1}) = \frac{1}{\operatorname{det}(A)} \).
Scalar Multiplication of Matrices
Scalar multiplication involves multiplying each element of a matrix by a scalar (a single number). When a matrix A is multiplied by a scalar c, each entry of the matrix is scaled by this number.
This operation can be represented as:
This operation can be represented as:
- If A is a matrix, and c is a scalar, then \(cA\) is a new matrix where each element of A is multiplied by c.
- For a 4x4 matrix and a scalar value c: \(\operatorname{det}(cA) = c^4 \cdot \operatorname{det}(A)\).
Other exercises in this chapter
Problem 40
Find (a) \(\operatorname{det}(A),\) (b) the matrix of cofactors \(M_{C},(\mathrm{c})\) adj \((A),\) and, if possible, \((\mathrm{d}) A^{-1}.\) $$A=\left[\begin{
View solution Problem 40
Evaluate the determinant of the given matrix. \(A=\left[\begin{array}{rrrrr}1 & 2 & 3 & 0 & 0 \\ 2 & -1 & 4 & 0 & 0 \\ 6 & 1 & 1 & 0 & 0 \\ 0 & 0 & 0 & 4 & 3 \\
View solution Problem 41
Use Cramer's rule to solve the given linear system. $$\begin{aligned} &2 x_{1}-x_{2}+x_{3}=2,\\\ &\begin{array}{l} 4 x_{1}+5 x_{2}+3 x_{3}=0, \\ 4 x_{1}-3 x_{2}
View solution Problem 41
Find (a) \(\operatorname{det}(A),\) (b) the matrix of cofactors \(M_{C},(\mathrm{c})\) adj \((A),\) and, if possible, \((\mathrm{d}) A^{-1}.\) $$A=\left[\begin{
View solution