Problem 40
Question
January \(1,1990,\) was a Monday. What day of the week was January 1 \(1976 ?\) (Hint: Again, look for leap years.)
Step-by-Step Solution
Verified Answer
January 1, 1976, was a \(Saturday\).
1Step 1: Find the number of years between 1976 and 1990
First, we need to calculate the difference in years between 1976 and 1990:
1990 - 1976 = 14 years
2Step 2: Determine the number of leap years between 1976 and 1990
A leap year occurs once every four years, and the extra day is on February 29. To find which years are leap years, we should check if the year is divisible by 4:
1976 is a leap year (1976 % 4 == 0)
1980 is a leap year (1980 % 4 == 0)
1984 is a leap year (1984 % 4 == 0)
1988 is a leap year (1988 % 4 == 0)
There are 4 leap years from 1976 to 1990.
3Step 3: Calculate the number of days between 1976 and 1990, including leap years
Now, let's find out the number of days between 1976 and 1990, considering the leap years:
14 years * 365 days + 4 leap year days = 5110 days
4Step 4: Calculate the days of the week difference
We have 7 days in a week, so to find the days of the week difference, we will perform modulo operation (remainder) with the total number of days and 7:
5110 % 7 = 2
This means that the day of the week in 1976 is 2 days before the day of the week in 1990 (Monday).
5Step 5: Determine the day of the week in 1976 by subtracting the calculated days from 1990
Since January 1, 1990, is a Monday and 1976 is 2 days before 1990:
Monday - 2 days = Saturday
So, January 1, 1976, was a Saturday.
Key Concepts
Leap YearModulo OperationCalendar MathDate Calculation Algorithm
Leap Year
In the world of calendars, not every year is the same. A typical year has 365 days, but every four years, something special happens - a leap year. A leap year helps align our calendar year with the solar year (or how long it takes the Earth to orbit the Sun). This alignment is achieved by adding an extra day, February 29, to the calendar. This extra day ensures that we do not drift away from the seasons over time.
A year is a leap year if it is divisible by 4. However, there are some exceptions:
- If a year is divisible by 100, it is not a leap year unless...
- The year is also divisible by 400, in which case it is a leap year.
Modulo Operation
Calculating days, weeks, and even leap years often involves a handy mathematical operation known as the modulo operation. Think of modulo as finding what's left over after division. When you divide a number and are left with a remainder, that's exactly what modulo gives you.For instance, when we calculate the number of days between two years and want to determine what day of the week it corresponds to, we use modulo with 7, since there are 7 days in a week:\[ 5110 \mod 7 = 2 \]This means when you divide 5110 by 7, you end up with 2 as the remainder. In day calculation, this tells us that the day in 1976 is two days earlier in the week compared to the day in 1990.Using modulo operation simplifies your math when working with cycles, like days of the week. It allows you to focus on what's left over, providing the key insight to calculate time-related problems effectively.
Calendar Math
Calendar math is all about understanding the structure of time and using it to solve problems. When figuring out a particular day of the week for any given date, calendar math becomes your best friend.
Key elements to consider in calendar math include:
- Standard year: 365 days
- Leap year: 366 days
- 7-day week cycle (Sunday to Saturday)
Date Calculation Algorithm
The date calculation algorithm is a structured approach you can follow to find the day of the week for any given date. This algorithm combines all the previous concepts, including leap year determination, modulo operation, and calendar math.
Here's a basic outline of how such an algorithm works:
- Identify the day of the week for a starting date (like January 1, 1990).
- Calculate the number of days you've moved forward or backward to reach your target date (like January 1, 1976).
- Count leap years in between to adjust the total number of days.
- Use the modulo operation with 7 to find out how many days the week advanced or regressed.
- Finally, subtract (or add if moving forward in time) this result from the known starting day to determine the day of the week for the target date.
Other exercises in this chapter
Problem 39
January \(1,2000,\) falls on a Saturday. What day of the week will January \(1,2020,\) be?
View solution Problem 39
Let \(A\) be a square matrix. Prove that \(\left(A^{\mathrm{T}}\right)^{\mathrm{T}}=A\).
View solution Problem 40
Let \(A, B,\) and \(C\) be square matrices of order \(2 .\) Prove each. $$(A+B)^{\mathrm{T}}=A^{\mathrm{T}}+B^{\mathrm{T}}$$
View solution Problem 40
Two sets \(A\) and \(B\) are equivalent, denoted by \(A \sim B,\) if there exists a bijection between them. Prove each. \(\mathbf{Z} \sim \mathbf{O},\) the set
View solution