Problem 40
Question
In Exercises 37-54, a point in rectangular coordinates is given. Convert the point to polar coordinates. \(\left(-4, -4\right)\)
Step-by-Step Solution
Verified Answer
The polar coordinates of the point \((-4, -4)\) are \((4\sqrt{2}, 225°)\) or \((4\sqrt{2}, 5\pi/4)\) in radians.
1Step 1: Calculate distance from origin (polar radius)
The polar radius, often denoted as \( r \), can be calculated from rectangular coordinates using the Pythagorean theorem, i.e. \( r = \sqrt{x^2 + y^2} \). Substituting in the given x and y values, we get \( r = \sqrt{(-4)^2 + (-4)^2} = \sqrt{32} = 4\sqrt{2} \).
2Step 2: Calculate polar angle
The angle, often denoted as \( \theta \), is the angle formed by the positive x-axis and the radius. It can be found using the tangent function: \( \theta = tan^{-1}(y/x) \). We begin by substituting the y and x values: \( \theta = tan^{-1}(-4/-4) = tan^{-1}(1) \). The angle corresponding to tan(1) is 45° in the first quadrant. However, our point lies in the third quadrant. Hence, our angle should be 180°+45° = 225°. Note that if we are using radians, the corresponding radian measure of 225° is \( 5\pi/4 \).
3Step 3: Present the final answer
The converted polar coordinates are expressed as \((r, \theta)\), where r is the radius and \(\theta\) is the angle. We substitute the values we've obtained to get the final answer.
Key Concepts
Rectangular CoordinatesPythagorean TheoremPolar RadiusTangent FunctionPolar Angle
Rectangular Coordinates
Rectangular Coordinates are a common way to describe the position of a point in space using two numerical values: \((x, y)\). You can think of these as the point's address on a grid, with \(x\) indicating how far right or left you move from the origin (the center point, \(0, 0\)), and \(y\) indicating how far up or down you move.
These coordinates are very intuitive when working in a Cartesian plane, such as graphing lines or shapes. For example, the point \((-4, -4)\) tells us to move 4 units left and 4 units down from the origin. This is a very precise way to locate a point in two-dimensional space.
These coordinates are very intuitive when working in a Cartesian plane, such as graphing lines or shapes. For example, the point \((-4, -4)\) tells us to move 4 units left and 4 units down from the origin. This is a very precise way to locate a point in two-dimensional space.
- The \(x\)-coordinate tells the horizontal direction (positive means right, negative means left).
- The \(y\)-coordinate tells the vertical direction (positive means up, negative means down).
Pythagorean Theorem
The Pythagorean Theorem is a fundamental principle used to calculate distances in geometry. It provides a simple formula: \(a^2 + b^2 = c^2\), where \(c\) is the hypotenuse of a right triangle, and \(a\) and \(b\) are the other two sides.
In the context of converting coordinates, \(a\) and \(b\) relate directly to the \(x\) and \(y\) axes of a point in rectangular coordinates. The theorem helps us find the polar radius \(r\), which is the distance of the point from the origin.
In the context of converting coordinates, \(a\) and \(b\) relate directly to the \(x\) and \(y\) axes of a point in rectangular coordinates. The theorem helps us find the polar radius \(r\), which is the distance of the point from the origin.
- Use \(x\) and \(y\) as the triangle's legs to find \(r\).
- Calculate \(r\) using \(r = \sqrt{x^2 + y^2}\).
Polar Radius
The Polar Radius, usually denoted by \(r\), represents the distance from the origin to the point in polar coordinates. It is akin to measuring the length of an invisible line drawn directly from the origin to the point.
You calculate the polar radius using the Pythagorean Theorem formula: \(r = \sqrt{x^2 + y^2}\). This converts the initial rectangular coordinates into a fundamental component of polar coordinates.
You calculate the polar radius using the Pythagorean Theorem formula: \(r = \sqrt{x^2 + y^2}\). This converts the initial rectangular coordinates into a fundamental component of polar coordinates.
- The formula \(r = \sqrt{(-4)^2 + (-4)^2}\) evaluates the distance.
- Calculation gives \(r = \sqrt{32} = 4\sqrt{2}\).
Tangent Function
The Tangent Function is an important function in trigonometry used to determine angles. For coordinate conversion, it helps find the polar angle \(\theta\).
By using the inverse tangent formula \(\theta = \tan^{-1}(\frac{y}{x})\), you can determine the angle between the positive x-axis and the line connecting the origin to the point. It gives precise angular measurements for converting rectangular coordinates to polar coordinates.
By using the inverse tangent formula \(\theta = \tan^{-1}(\frac{y}{x})\), you can determine the angle between the positive x-axis and the line connecting the origin to the point. It gives precise angular measurements for converting rectangular coordinates to polar coordinates.
- Substitute values to get \(\theta = \tan^{-1}(\frac{-4}{-4})\).
- This results in \(\theta = \tan^{-1}(1)\), which initially identifies a 45° angle.
Polar Angle
The Polar Angle, denoted as \(\theta\), is the measure of the angle relative to the positive x-axis, displayed counter-clockwise. This angle is crucial for expressing a point's position in polar coordinates.
Calculating the polar angle requires understanding its position in the coordinate plane's quadrants. In our example, the point \((-4, -4)\) lies in the third quadrant. Hence, adjustments are needed after the initial tangent result.
Calculating the polar angle requires understanding its position in the coordinate plane's quadrants. In our example, the point \((-4, -4)\) lies in the third quadrant. Hence, adjustments are needed after the initial tangent result.
- Begin with \(\theta = \tan^{-1}(1)\), resulting in 45°.
- Add 180° for third quadrant placement, so \(\theta = 225°\).
- Alternatively, express the angle in radians, as \(\theta = \frac{5\pi}{4}\).
Other exercises in this chapter
Problem 40
In Exercises 39-54, find a polar equation of the conic with its focus at the pole. \(\textit{Conic}\) Parabola \(\textit{Eccentricity}\) \(e=1\) \(\textit{Direc
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In Exercises 23-48, sketch the graph of the polar equation using symmetry, zeros, maximum \(r\)-values, and any other additional points. \(r= 2\ \cos\ 2\theta\)
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In Exercises 33-40, use the results of Exercises 29-32 to find a set of parametric equations for the line or conic. Hyperbola: vertices: \((\pm2, 0); \quad\) fo
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In Exercises 35-46, find the standard form of the equation of the hyperbola with the given characteristics. Vertices: \((-2, 1), (2, 1); \quad\) passes through
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