Problem 40
Question
In each part, explain what happens if you apply Newton's Method to a function \(f\) when the given condition is satisfied for some value of \(n .\) (a) \(f\left(x_{n}\right)=0\) (b) \(x_{n+1}=x_{n}\) (c) \(x_{n+2}=x_{n} \neq x_{n+1}\)
Step-by-Step Solution
Verified Answer
(a) Newton's Method stops; (b) It converges or stalls; (c) Enters a 2-cycle without converging.
1Step 1: Understanding Newton's Method
Newton's Method is an iterative approach to approximate the roots of a real-valued function. The formula to reach the next approximation \(x_{n+1}\) from \(x_{n}\) is given by the formula \(x_{n+1} = x_{n} - \frac{f(x_{n})}{f'(x_{n})}\). This method uses both the function and its derivative.
2Step 2: Analyze Condition (a)
For part (a), if \(f(x_{n}) = 0\), it implies that \(x_{n}\) is already a root of the function \(f\). Consequently, when you attempt to apply Newton's Method with this \(x_{n}\), \(x_{n+1}\) remains \(x_{n}\) since no adjustments are needed (the formula effectively becomes \(x_{n+1} = x_{n}\)).
3Step 3: Analyze Condition (b)
For part (b), if \(x_{n+1} = x_{n}\), this means that applying Newton's Method does not change the approximation, suggesting convergence. This implies that \(x_{n}\) is a fixed point and very likely an approximation of the root (though could also be a point where the derivative is zero).
4Step 4: Analyze Condition (c)
For part (c), if \(x_{n+2} = x_{n} eq x_{n+1}\), it suggests a cyclic behavior with period 2. This implies that the method alternates between two points, and does not converge to a root. This typically occurs when the function in consideration has specific behaviors, leading to an unstable fixed cycle.
Key Concepts
Iterative Approach in Newton's MethodApproximate Roots and Their ImportanceCyclic Behavior in Iterative Methods
Iterative Approach in Newton's Method
Newton's Method is a fascinating mathematical technique that employs an iterative approach to finding approximate roots of functions. To iterate means to repeat a process, and in the context of Newton's Method, this involves repeatedly applying a specific formula to hone in on a solution. The formula used is \(x_{n+1} = x_{n} - \frac{f(x_{n})}{f'(x_{n})}\). Here, \(x_n\) is our current approximation, \(f(x_n)\) is the function evaluated at this point, and \(f'(x_n)\) is the derivative at this point. By continually applying this formula, we inch closer and closer to the actual root.
- Iterations refine the approximation progressively.
- This method leverages both the function and its slope to adjust each approximation.
- It starts with an initial guess and continuously improves it.
Approximate Roots and Their Importance
Understanding approximate roots is crucial when using methods like Newton's. Real-world problems seldom offer exact solutions easily. Here, approximations come to the rescue by providing values that are close enough to the real solution for practical purposes.
- Newton's Method uses trial and error through iterations to zero in on these approximate roots.
- If a point \(x_n\) results in \(f(x_n) = 0\), it means an exact root is found.
- If \(x_{n+1} = x_{n}\), it suggests the solution has stopped changing, likely indicating an approximate root is reached.
Cyclic Behavior in Iterative Methods
Cyclic behavior is an interesting phenomenon that can arise in iterative methods. In the context of Newton's Method, it's typically undesirable because it indicates that the method is not converging to a single value. Instead, the approximations are hopping back and forth between values without settling on one.
- This occurs when \(x_{n+2} = x_{n} eq x_{n+1}\), meaning the process alternates between two points.
- Such cycles suggest that the method is caught in a loop and won’t likely reach a true root unless adjusted.
- Understanding the function behavior can often help diagnose and resolve such cycles.
Other exercises in this chapter
Problem 39
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