Problem 40
Question
In 2005 astronomers announced the discovery of a large black hole in the galaxy Markarian 766 having clumps of matter orbiting around once every 27 hours and moving at 30,000 km/s. (a) How far are these clumps from the center of the black hole? (b) What is the mass of this black hole, assuming circular orbits? Express your answer in kilograms and as a multiple of our sun's mass. (c) What is the radius of its event horizon?
Step-by-Step Solution
Verified Answer
(a) \( r \approx 5.5 \times 10^{10} \) meters; (b) \( M \approx 1.2 \times 10^{34} \) kg, \( 6000 M_{\odot} \); (c) \( R_s \approx 1.8 \times 10^{7} \) meters.
1Step 1: Define Given Parameters
We have the orbital period \( T = 27 \text{ hours} \ = 27 \times 3600 \text{ seconds} \), and the orbital speed \( v = 30,000 \text{ km/s} \ = 3 \times 10^7 \text{ m/s} \). We are tasked to find the orbit radius \( r \) from the black hole's center, the black hole's mass \( M \), and the radius of its event horizon.
2Step 2: Calculate the Orbital Radius
For an object in orbit, the centripetal force \( F_c = \frac{mv^2}{r} \) is provided by the gravitational force \( F_g = \frac{GmM}{r^2} \), where \( G \) is the gravitational constant, \( 6.674 \times 10^{-11} \text{ m}^3\text{kg}^{-1}\text{s}^{-2} \). Since \( F_c = F_g \), we have:\[\frac{mv^2}{r} = \frac{GmM}{r^2}\]Rearranging, \( r = \frac{GM}{v^2} \).Using the relation between period and radius for circular orbits \( v = \frac{2\pi r}{T} \), we rearrange to solve for \( r \):\[ r = \left(\frac{G M T^2}{4\pi^2} \right)^{1/3} \]Plug values in \( r = \left(\frac{6.674 \times 10^{-11} \times M \times (27 \times 3600)^2}{4\pi^2} \right)^{1/3} \), using trial and error or solving both equations to find \( r \approx 5.5 \times 10^{10} \) meters.
3Step 3: Calculate the Mass of the Black Hole
Calculate \( M \) using the formula derived from Step 2:\[ M = \frac{r v^2}{G} \]With \( r = 5.5 \times 10^{10} \) meters and \( v = 3 \times 10^7 \text{ m/s} \),\[ M = \frac{5.5 \times 10^{10} \times (3 \times 10^7)^2}{6.674 \times 10^{-11}} \]Calculate \( M \approx 1.2 \times 10^{34} \) kilograms. To express as a multiple of the Sun's mass \( M_{\odot} = 1.989 \times 10^{30} \text{ kg} \):\[ \frac{1.2 \times 10^{34}}{1.989 \times 10^{30}} \approx 6000 M_{\odot} \].
4Step 4: Calculate the Radius of the Event Horizon
The radius of the event horizon, or Schwarzschild radius \( R_s \), is given by\[ R_s = \frac{2GM}{c^2} \]Where \( c = 3 \times 10^8 \text{ m/s} \) is the speed of light.Plug in \( M = 1.2 \times 10^{34} \text{ kg} \):\[ R_s = \frac{2 \times 6.674 \times 10^{-11} \times 1.2 \times 10^{34}}{(3 \times 10^8)^2} \]Calculate \( R_s \approx 1.8 \times 10^{7} \) meters.
Key Concepts
Orbital MechanicsGravitational ForceCentripetal ForceSchwarzschild Radius
Orbital Mechanics
Orbital mechanics is the study of how objects move in space due to various forces, primarily gravity. In the context of this exercise, it helps us understand how chunks of matter orbit around a black hole.
These clumps are following paths determined by the interplay of their speed and gravitational pull from the black hole.
Some important points on orbital mechanics include:
These clumps are following paths determined by the interplay of their speed and gravitational pull from the black hole.
Some important points on orbital mechanics include:
- Orbital Period: The time taken for one complete orbit around a black hole, which in this scenario is 27 hours.
- Orbital Speed: This indicates how fast the matter is moving, given as 30,000 km/s.
- Radius of Orbit: Again, it is the distance from the centre of the black hole to the path of the orbiting matter.
Gravitational Force
Gravitational force is the attractive force between two masses. It plays a crucial role in black hole physics and orbital mechanics.
This force keeps the matter in orbit around the black hole, creating the gravitational pull needed for circular motion.
The formula for gravitational force (F_g) is given by:
\[ F_g = \frac{GMm}{r^2} \]
Where:
This force keeps the matter in orbit around the black hole, creating the gravitational pull needed for circular motion.
The formula for gravitational force (F_g) is given by:
\[ F_g = \frac{GMm}{r^2} \]
Where:
- \( G \) is the gravitational constant, \(6.674 \times 10^{-11} \text{ m}^3\text{kg}^{-1}\text{s}^{-2} \).
- \( M \) is the mass of the black hole.
- \( m \) is the mass of the orbiting matter.
- \( r \) is the distance between the center of the black hole and the orbiting object.
Centripetal Force
The centripetal force is what keeps an object moving in a circular path. In the case of objects orbiting a black hole, this force is provided by gravity.
Without this force, the objects would move in straight lines off into space.
The formula for centripetal force (F_c) is:\[ F_c = \frac{mv^2}{r} \]
Where:
This equation allows us to solve for various unknowns such as the mass of the black hole or the radius of the orbit by setting them equal to each other. Understanding centripetal force helps us make sense of why objects remain in orbit and do not drift off course.
Without this force, the objects would move in straight lines off into space.
The formula for centripetal force (F_c) is:\[ F_c = \frac{mv^2}{r} \]
Where:
- \( m \) is the mass of the orbiting object.
- \( v \) is the orbital speed.
- \( r \) is the radius of the orbit.
This equation allows us to solve for various unknowns such as the mass of the black hole or the radius of the orbit by setting them equal to each other. Understanding centripetal force helps us make sense of why objects remain in orbit and do not drift off course.
Schwarzschild Radius
The Schwarzschild radius represents the size of a black hole's event horizon. It is the boundary beyond which nothing, not even light, can escape the black hole's gravitational pull.
Essentially, it denotes how "large" a black hole appears to be from the outside.
The formula for the Schwarzschild radius (R_s) is:
\[ R_s = \frac{2GM}{c^2} \]
Where:
Essentially, it denotes how "large" a black hole appears to be from the outside.
The formula for the Schwarzschild radius (R_s) is:
\[ R_s = \frac{2GM}{c^2} \]
Where:
- \( G \) is the gravitational constant.
- \( M \) is the mass of the black hole.
- \( c \) is the speed of light, \(3 \times 10^8 \text{ m/s} \).
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