Problem 40
Question
$$ \frac{1}{x-3} ; a=1 $$
Step-by-Step Solution
Verified Answer
The value of the function at a = 1 is -1/2.
1Step 1: Understand the Given Function
We are given the function \( f(x) = \frac{1}{x-3} \) and we need to evaluate or understand this function when \( a = 1 \). This means substituting \( x = 1 \) into the function.
2Step 2: Substitute the Given Value
Substitute \( x = 1 \) into the function: \( f(x) = \frac{1}{x - 3} \). This becomes \( f(1) = \frac{1}{1 - 3} \).
3Step 3: Simplify the Expression
Simplify the expression \( f(1) = \frac{1}{1 - 3} \). Perform the subtraction in the denominator: \( 1 - 3 = -2 \). Therefore, \( f(1) = \frac{1}{-2} \).
4Step 4: Write the Final Answer
The value of the function \( f(x) \) at \( a = 1 \) is \( f(1) = -\frac{1}{2} \). This gives us the function's value at this specific point.
Key Concepts
Evaluating functions at a pointSimplifying expressionsSubstitution in functions
Evaluating functions at a point
When we talk about evaluating functions at a point, we are essentially interested in finding the output value of a function for a particular input. A function, such as \( f(x) = \frac{1}{x-3} \), relies on its input \( x \) to produce an output. By specifying \( a = 1 \), you are instructed to calculate what the function yields when \( x = 1 \).
- First, replace \( x \) with the given number, which is \( a = 1 \). This transforms the function to \( f(1) = \frac{1}{1-3} \).
- The main goal is to compute the result of this transformation to find the particular value at point \( a \).
Simplifying expressions
Simplifying expressions is like cleaning up math to make it more understandable. It means performing all possible arithmetic and reducing fractions when you substitute a number into a function. In this case, after inserting \( x = 1 \) into the function \( f(x) = \frac{1}{x-3} \), the expression becomes \( f(1) = \frac{1}{1-3} \).
- Start with solving the subtraction in the denominator: \( 1 - 3 \).
- Calculate \( 1 - 3 = -2 \).
- The fraction \( \frac{1}{-2} \) simplifies to the consistent and final result of \( -\frac{1}{2} \).
Substitution in functions
Substitution in functions is a method where you replace the variable in a function with a particular value. This technique allows you to pinpoint exactly what the function equals at specific inputs. In this exercise, the function is \( f(x) = \frac{1}{x-3} \), and you're told to substitute \( x = 1 \).
- Switch out the \( x \) with the value you're given, which turns the function into \( f(1) = \frac{1}{1-3} \).
- The substitution is a direct swap inside the expression, facilitating the evaluation of the function at that point.
Other exercises in this chapter
Problem 39
Suppose that Mary rolls a fair die until a "6" occurs. Let \(X\) denote the random variable that is the number of tosses needed for this " 6 " to occur. Find th
View solution Problem 40
Let $$ f(x)= \begin{cases}e^{-1 / x^{2}} & \text { if } x \neq 0 \\ 0 & \text { if } x=0\end{cases} $$ (a) Show that \(f^{\prime}(0)=0\) by using the definition
View solution Problem 40
Prove that if \(\Sigma a_{n}\) is a convergent series of positive terms then \(\Sigma \ln \left(1+a_{n}\right)\) converges.
View solution Problem 40
Discuss the convergence or divergence of $$ \begin{aligned} \frac{1}{\sqrt{2}-1}-\frac{1}{\sqrt{2}+1}+\frac{1}{\sqrt{3}-1}-\frac{1}{\sqrt{3}+1}+\\\ \frac{1}{\sq
View solution