Problem 40
Question
For Problems \(33-44\), determine the slope and \(y\) intercept of the line represented by the given equation, and graph the line. $$ 5 x-2 y=0 $$
Step-by-Step Solution
Verified Answer
The slope is \(\frac{5}{2}\) and the y-intercept is 0. The line passes through (0,0) and (2,5).
1Step 1: Identify the standard form
The given equation is \(5x - 2y = 0\). This is in the standard form of a linear equation, \(Ax + By = C\). Here, \(A = 5\), \(B = -2\), and \(C = 0\).
2Step 2: Convert to slope-intercept form
To find the slope and y-intercept, convert the equation to the slope-intercept form, \(y = mx + b\). Start by isolating \(y\) in the equation: \(5x - 2y = 0\).
3Step 3: Solve for y
Rearrange the equation \(5x - 2y = 0\) to solve for \(y\):\[\begin{align*} 5x - 2y &= 0 \ -2y &= -5x \ y &= \frac{5}{2}x \end{align*}\]Now the equation is in the form \(y = \frac{5}{2}x + 0\).
4Step 4: Identify slope and y-intercept
From the equation \(y = \frac{5}{2}x + 0\), we identify the slope \(m = \frac{5}{2}\) and the y-intercept \(b = 0\).
5Step 5: Graph the line
To graph the line: Start at the y-intercept (0,0). From this point, use the slope \(\frac{5}{2}\) to find another point. The slope tells us to rise 5 units and run 2 units. Plot the point (2,5). Connect these points with a straight line.
Key Concepts
Linear EquationsGraphing LinesSlope-Intercept Form
Linear Equations
Linear equations are the foundation of algebra and are essential for understanding many mathematical concepts. They represent straight lines on a graph and can be expressed in various forms. A linear equation typically has two variables, usually denoted as \(x\) and \(y\), and is written in the standard form \(Ax + By = C\). Here, \(A\), \(B\), and \(C\) are constants. For instance, the equation \(5x - 2y = 0\) is a linear equation in standard form, where \(A = 5\), \(B = -2\), and \(C = 0\).
Linear equations are powerful because:
Linear equations are powerful because:
- They can model real-world situations where relationships are linear.
- They allow us to predict values by understanding the relationship between two variables.
Graphing Lines
Graphing lines is a practical way to visualize linear equations and understand the relationship between \(x\) and \(y\). When you graph a linear equation like \(y = \frac{5}{2}x + 0\), you plot points on a coordinate plane and connect them to form a straight line.
Here's how to simplify the process of graphing:
Here's how to simplify the process of graphing:
- Identify the y-intercept, which is the point where the line crosses the y-axis. For our equation, it is (0,0).
- Use the slope to determine the direction and steepness of the line. A slope of \(\frac{5}{2}\) means that for every 2 units you move horizontally, you move 5 units vertically.
- Start at the y-intercept and apply the slope to find another point, such as (2,5).
- Draw a line through the plotted points to represent the equation visually.
Slope-Intercept Form
The slope-intercept form of a linear equation is incredibly useful for quickly identifying key characteristics of a line. The general form is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
Understanding the components in \(y = nx + b\):
Understanding the components in \(y = nx + b\):
- The slope \(m\) indicates the line's steepness and direction. A positive slope like \(\frac{5}{2}\) means the line rises as it moves from left to right.
- The y-intercept \(b\) informs where the line crosses the y-axis. In our example, it's 0, implying the line passes through the origin.
Other exercises in this chapter
Problem 39
Sketch the line determined by each pair of points and decide whether the slope of the line is positive, negative, or zero. $$(-3,5),(2,-7)$$
View solution Problem 40
Determine the slope and \(y\) intercept of the line represented by the given equation, and graph the line. (Objective 2) $$5 x-2 y=0$$
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$$ \text { For Problems 37-56, graph each linear inequality. (Objective } 3 \text { ) } $$ $$ x+3 y
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Solve each system by using either the substitution or the elimination-by- addition method, whichever seems more appropriate. $$\left(\begin{array}{l}\frac{2}{3}
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