Problem 40
Question
Fluctuating Population The differential equation \(d P / d t=\) \((k \cos t) P\), where \(k\) is a positive constant, is a mathematical model for a population \(P(t)\) that undergoes yearly seasonal fluctuations. Solve the equation subject to \(P(0)=P_{0}\). Use a graphing utility to obtain the graph of the solution for different choices of \(P_{0}\).
Step-by-Step Solution
Verified Answer
The solution is \( P(t) = P_0 e^{k \sin t} \).
1Step 1: Understand the Differential Equation
We are given the differential equation \( \frac{dP}{dt} = (k \cos t) P \). This is a first-order linear ordinary differential equation, suggesting that population \( P(t) \) changes over time due to a cosine factor multiplied by \( k \) and the current population \( P \). We need to solve this DE to find \( P(t) \).
2Step 2: Separate Variables
To solve the differential equation, we start by separating variables. We arrange terms so that all \( P \) terms are on one side and all \( t \) terms on the other side: \( \frac{1}{P} dP = k \cos t \, dt \).
3Step 3: Integrate Both Sides
Integrate both sides of the equation: \( \int \frac{1}{P} \, dP = \int k \cos t \, dt \). The left integral becomes \( \ln |P| \), and the right integrates to \( k \sin t + C_1 \), where \( C_1 \) is the integration constant.
4Step 4: Solve for Population Function \( P(t) \)
Exponentiate both sides to solve for \( P \): \( P(t) = C e^{k \sin t} \), where \( C \) is a constant determined by the initial condition \( P(0) = P_0 \).
5Step 5: Apply Initial Condition
Apply the initial condition \( P(0) = P_0 \) to determine \( C \). At \( t = 0 \), \( P(0) = Ce^{k \sin 0} = C \). Thus, \( C = P_0 \), and the solution becomes: \( P(t) = P_0 e^{k \sin t} \).
6Step 6: Graph the Solution
Use a graphing utility to plot \( P(t) = P_0 e^{k \sin t} \) for different values of \( P_0 \). Try values such as \( P_0 = 1, 10,\) and \( 100 \) while keeping \( k \) constant, to observe how the initial population size impacts the population growth and fluctuations over time.
Key Concepts
Population ModelingFirst-order Linear Differential EquationsSeparation of Variables
Population Modeling
Population modeling involves mathematically representing populations to predict their growth or decline over time.
It can take into account various factors like birth rates, death rates, and environmental influences. In the context of our exercise, we're considering a population that fluctuates seasonally.
The differential equation provided, \( \frac{dP}{dt} = (k \cos t) P \), models how a population \( P(t) \) changes over time due to these seasonal variations. Here, \( k \) is a positive constant that scales the impact of these fluctuations.
It can take into account various factors like birth rates, death rates, and environmental influences. In the context of our exercise, we're considering a population that fluctuates seasonally.
The differential equation provided, \( \frac{dP}{dt} = (k \cos t) P \), models how a population \( P(t) \) changes over time due to these seasonal variations. Here, \( k \) is a positive constant that scales the impact of these fluctuations.
- Population changes according to the cosine function, which naturally varies between -1 and 1 over its cycle.
- This implies that the population experiences regular increases and decreases predicting a recurring pattern over time.
- The population will not grow or decline indefinitely but will oscillate around a certain mean.
First-order Linear Differential Equations
A first-order linear differential equation is a type of differential equation that can be expressed in the form \( \frac{dy}{dt} + p(t)y = q(t) \).
In this scenario, the differential equation \( \frac{dP}{dt} = (k \cos t)P \) is already in a separable form.
This provides a straightforward approach to finding an explicit solution for \( P(t) \).Here are key characteristics:
In this scenario, the differential equation \( \frac{dP}{dt} = (k \cos t)P \) is already in a separable form.
This provides a straightforward approach to finding an explicit solution for \( P(t) \).Here are key characteristics:
- Linear nature: The solution involves basic calculus techniques like separation of variables and integration.
- Order of Equation: Being first-order means it involves only the first derivative of the function \( P(t) \).
- Separable: We can easily isolate variables and solve using standard integration techniques.
Separation of Variables
Separation of variables is a technique used to solve differential equations.
It involves rearranging the equation to isolate all terms involving one variable on one side of the equation and all terms involving the other variable on the opposite side.
For first-order linear differential equations like \( \frac{dP}{dt} = (k \cos t)P \), it allows us to break down a complex relationship into parts that can be more easily managed.The process for applying separation of variables involves:
It involves rearranging the equation to isolate all terms involving one variable on one side of the equation and all terms involving the other variable on the opposite side.
For first-order linear differential equations like \( \frac{dP}{dt} = (k \cos t)P \), it allows us to break down a complex relationship into parts that can be more easily managed.The process for applying separation of variables involves:
- Move terms involving \( P \): Place all \( P \) terms on one side to achieve \( \frac{1}{P} dP \).
- Handle \( t \) terms: Rearrange all \( t \) related terms including constants to the other side to get \( k \cos t \, dt \).
- Integrate: Solve the integrals of each side separately, which typically involves basic calculus techniques.
Other exercises in this chapter
Problem 40
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