Problem 40
Question
Find \(y^{\prime \prime}\) $$ \text { For } y=x^{7}-8 x^{2}+2, \text { find } d^{6} y / d x^{6} $$
Step-by-Step Solution
Verified Answer
\( \frac{d^6 y}{dx^6} = 5040x \)
1Step 1: Understand the Function
We are given the function \( y = x^7 - 8x^2 + 2 \) and asked to find the sixth derivative with respect to \( x \), denoted as \( \frac{d^6 y}{dx^6} \).
2Step 2: Simplify the Calculation by Understanding Derivatives
Realize that deriving a polynomial involves decreasing the power of each term by one and multiplying by the original power, and that all polynomial terms of lower degree than the derivative order vanish. This means terms in a polynomial will eventually become zero after enough derivatives.
3Step 3: Calculate the First Derivative
Calculate the first derivative: \( y' = \frac{d}{dx}(x^7) - \frac{d}{dx}(8x^2) + \frac{d}{dx}(2) = 7x^6 - 16x \).
4Step 4: Calculate the Second Derivative
Compute the second derivative: \( y'' = \frac{d}{dx}(7x^6) - \frac{d}{dx}(16x) = 42x^5 - 16 \).
5Step 5: Calculate the Third Derivative
Find the third derivative: \( y''' = \frac{d}{dx}(42x^5) = 210x^4 \).
6Step 6: Calculate the Fourth Derivative
Calculate the fourth derivative: \( y^{(4)} = \frac{d}{dx}(210x^4) = 840x^3 \).
7Step 7: Calculate the Fifth Derivative
Find the fifth derivative: \( y^{(5)} = \frac{d}{dx}(840x^3) = 2520x^2 \).
8Step 8: Calculate the Sixth Derivative
Compute the sixth derivative: \( y^{(6)} = \frac{d}{dx}(2520x^2) = 5040x \).
Key Concepts
Polynomial DerivativesHigher Order DerivativesDifferentiation Techniques
Polynomial Derivatives
Polynomial derivatives involve rules that help us find the rate of change of polynomial functions. This process works by applying the power rule. The power rule states that for a term in the form of \( ax^n \), the derivative is \( n \cdot ax^{n-1} \). This means:
- The exponent \( n \) becomes the coefficient.
- The exponent \( n \) is reduced by one.
- The derivative of \( x^7 \) is \( 7x^6 \).
- The derivative of \( -8x^2 \) is \( -16x \).
- The derivative of a constant like 2 is zero.
Higher Order Derivatives
Higher order derivatives refer to taking the derivative of a function multiple times. In other words, it involves repeatedly applying differentiation processes.
In this exercise, you are asked to determine the sixth derivative \( \frac{d^6 y}{dx^6} \). To do this, begin with the first derivative, then move to the second, and continue this process through to the sixth. The derivatives look like this:
In this exercise, you are asked to determine the sixth derivative \( \frac{d^6 y}{dx^6} \). To do this, begin with the first derivative, then move to the second, and continue this process through to the sixth. The derivatives look like this:
- First derivative: \( y' = 7x^6 - 16x \)
- Second derivative: \( y'' = 42x^5 - 16 \)
- Third derivative: \( y''' = 210x^4 \)
- Fourth derivative: \( y^{(4)} = 840x^3 \)
- Fifth derivative: \( y^{(5)} = 2520x^2 \)
- Sixth derivative: \( y^{(6)} = 5040x \)
Differentiation Techniques
Differentiation techniques vary, but the simplest involves using the power rule, as applied in this exercise. Understanding how each differentiation step works will help in finding higher-order derivatives effectively.
Techniques include:
Techniques include:
- Breaking down functions: Derive each term separately in polynomials.
- Seeing patterns: Recognize how each differentiated term influences the subsequent derivative.
- Applying rules often: Consistent application of the rules ensures no steps are missed.
Other exercises in this chapter
Problem 40
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Differentiate each function. \(y=\frac{\sqrt{x}+4}{\sqrt[3]{x}-5}\)
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Differentiate each function $$ f(x)=\sqrt[3]{\frac{4-x^{3}}{x-x^{2}}} $$
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