Problem 40
Question
Find the probability of tossing a coin \(n\) times and obtaining \(n\) heads. What happens to this probability as \(n\) increases? Does this agree with your intuition? Explain.
Step-by-Step Solution
Verified Answer
The probability is \( \left( \frac{1}{2} \right)^n \), which approaches zero as \( n \) increases. This matches the intuition that all heads are improbable in many tosses.
1Step 1: Define the Probability of a Single Event
When tossing a fair coin, the probability of getting a head (H) on any single toss is \( \frac{1}{2} \). The coin has two possible outcomes: heads or tails, each equally likely.
2Step 2: Probability of Heads for Multiple Tosses
The probability of obtaining heads in each toss when the coin is tossed \( n \) times is the product of the probabilities for each individual toss. Thus, the probability of getting \( n \) heads in \( n \) tosses is \( \left( \frac{1}{2} \right)^n \).
3Step 3: Analyze the Probability as n Increases
As \( n \) increases, \( \left( \frac{1}{2} \right)^n \) gets smaller because \( \frac{1}{2} < 1 \). When you multiply a number less than 1 by itself many times, the resulting product approaches zero.
4Step 4: Align with Intuition
Intuitively, getting all heads in many coin tosses is unlikely because there are exponentially more possible outcomes as \( n \) increases. Thus, the decreasing probability is consistent with the expectation that perfect results become rare in a large number of trials.
Key Concepts
Coin TossBinomial ProbabilityExponential Decay
Coin Toss
Tossing a coin is one of the simplest examples of a random experiment in probability theory. A fair coin has two sides: heads (H) and tails (T).
The chance of getting H or T is equal, known as a probability of 0.5 or \( \frac{1}{2} \). This is because there are two possible outcomes, and neither side is weighted more than the other.
When you toss the coin once, the randomness of outcome represents a central idea in probability. If you were to track numerous individual tosses, you'd expect roughly half to be heads and half tails, aligning with this equal split probability.
The chance of getting H or T is equal, known as a probability of 0.5 or \( \frac{1}{2} \). This is because there are two possible outcomes, and neither side is weighted more than the other.
When you toss the coin once, the randomness of outcome represents a central idea in probability. If you were to track numerous individual tosses, you'd expect roughly half to be heads and half tails, aligning with this equal split probability.
- **Fair Coin**: A coin that has equal probability of landing on heads or tails.
- **Probability**: A number between 0 and 1 showing how likely an event is to occur.
- **Random Experiment**: An experiment that can produce different outcomes, even if repeated in the same manner.
Binomial Probability
When dealing with multiple coin tosses, the concept of binomial probability comes into play. This type of probability distribution is used when you conduct a series of binary (two possible outcomes) experiments like coin tosses.
In this specific exercise, we are interested in calculating the probability of obtaining heads in every single toss when we flip a coin \( n \) times.
For each toss, you have a probability \( \frac{1}{2} \) of getting a head. For \( n \) independent tosses, the probability of getting heads every time is \( \left( \frac{1}{2} \right)^n \).
In this specific exercise, we are interested in calculating the probability of obtaining heads in every single toss when we flip a coin \( n \) times.
For each toss, you have a probability \( \frac{1}{2} \) of getting a head. For \( n \) independent tosses, the probability of getting heads every time is \( \left( \frac{1}{2} \right)^n \).
- **Binary Experiment**: An experiment with two outcomes.
- **Independent Trials**: Trials where the outcome of one does not affect the others.
- **Probability Calculation**: Multiply probabilities of each independent event for combined outcomes.
Exponential Decay
Exponential decay is a concept that describes how quantities decrease rapidly at a consistent rate over time or repetition. In the context of probability, it explains how repeated multiplication of a probability less than 1 results in values approaching zero.
In the exercise with the coin toss, \( \left( \frac{1}{2} \right)^n \) demonstrates exponential decay as the probability of obtaining heads in all tosses decreases quickly with increasing \( n \).
This decay is significant because it aligns with our intuitive understanding that perfect streaks of any kind (like all heads in multiple tosses) become exceptionally rare as the number of trials increases.
In the exercise with the coin toss, \( \left( \frac{1}{2} \right)^n \) demonstrates exponential decay as the probability of obtaining heads in all tosses decreases quickly with increasing \( n \).
This decay is significant because it aligns with our intuitive understanding that perfect streaks of any kind (like all heads in multiple tosses) become exceptionally rare as the number of trials increases.
- **Exponential Decay**: Reducing rapidly by a consistent factor.
- **Implications in Probability**: As experiments increase, chances of perfect repetition shrink to nearly zero.
- **Intuition Alignment**: Matches common sense understanding of decreasing likelihoods in repeated trials.
Other exercises in this chapter
Problem 39
Use a formula to find the sum of the finite geometric series. The first 20 terms of the series defined by \(a_{n}=3(2)^{n-1}\)
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Use Pascal's triangle to help expand the expression. $$ (3-2 x)^{5} $$
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The first five terms of a geometric sequence are given. Find (a) numerical, (b) graphical, and (c) symbolic representations of the sequence. Include at least ei
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Evaluate the expression. \(P(34,2)\)
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