Problem 40
Question
Find the limit or show that it does not exist. \( \displaystyle \lim_{x \to 0^+} \tan^{-1}(\ln x) \)
Step-by-Step Solution
Verified Answer
The limit is \( -\frac{\pi}{2} \).
1Step 1: Understand the Problem
We need to find the limit of the function \( \tan^{-1}(\ln x) \) as \( x \to 0^+ \). This involves the evaluation as \( x \) approaches 0 from the right.
2Step 2: Analyze the Inner Function \( \ln x \)
Consider \( \ln x \) as \( x \to 0^+ \). As \( x \) gets close to 0 from the right, \( \ln x \) approaches \(-\infty\), because the natural logarithm of a number approaching zero from the positive side tends towards negative infinity.
3Step 3: Evaluate \( \tan^{-1}(y) \) as \( y \to -\infty \)
The function \( \tan^{-1}(y) \) is bounded, with horizontal asymptotes at \( y = -\pi/2 \) and \( y = \pi/2 \). Specifically, as \( y \to -\infty \), \( \tan^{-1}(y) \to -\pi/2 \).
4Step 4: Combine the Results
Substitute \( y = \ln x \) into \( \tan^{-1}(\ln x) \). As \( x \to 0^+ \), \( \ln x \to -\infty \), and therefore \( \tan^{-1}(\ln x) \to -\pi/2 \).
5Step 5: State the Limit
Thus, the limit is \( \lim_{x \to 0^+} \tan^{-1}(\ln x) = -\frac{\pi}{2} \).
Key Concepts
Inverse Trigonometric FunctionsNatural LogarithmAsymptotic Behavior
Inverse Trigonometric Functions
Inverse trigonometric functions allow us to determine angles when the value of a trigonometric function is known. They are the inverse operations of the trigonometric functions like sine, cosine, and tangent. A key aspect of these functions is their range, a set of output values for defined within particular intervals. For example, the function \( \tan^{-1}(x) \), or arctan, maps real numbers to values between \( -\pi/2 \) and \( \pi/2 \).
These functions are continuous and exhibit certain asymptotic properties that are particularly useful when evaluating limits, as seen in the original exercise. Understanding the behavior of \( \tan^{-1}(x) \) at positive and negative infinity helps predict how inversely related expressions behave when reaching extreme values in limit problems.
These functions are continuous and exhibit certain asymptotic properties that are particularly useful when evaluating limits, as seen in the original exercise. Understanding the behavior of \( \tan^{-1}(x) \) at positive and negative infinity helps predict how inversely related expressions behave when reaching extreme values in limit problems.
- For instance, \( \tan^{-1}(x) \to \pi/2 \) as \( x \to \infty \)
- \( \tan^{-1}(x) \to -\pi/2 \) as \( x \to -\infty \)
Natural Logarithm
The natural logarithm function, denoted \( \ln(x) \), is the inverse of the exponential function \( e^x \). It expresses the exponent to which the base \( e \) (approximately 2.718) must be raised to obtain a number \( x \).
The natural logarithm of a number approaching zero from the positive side is particularly special since:
The natural logarithm of a number approaching zero from the positive side is particularly special since:
- \( \ln(x) \to -\infty \) as \( x \to 0^+ \)
Asymptotic Behavior
Asymptotic behavior describes how a function behaves as its input approaches a certain value or infinity. In calculus, this often involves examining the tendencies of a function at the extreme ends of its domain. It provides insights into function limits and potential horizontal or vertical asymptotes.
For the function \( \tan^{-1}(x) \):
By comprehending how functions behave asymptotically, one gains a deeper appreciation for solving calculus problems that examine the limits of tangents and logarithms at or approaching infinity or zero.
For the function \( \tan^{-1}(x) \):
- It approaches \( \pi/2 \) as \( x \to \infty \)
- It approaches \( -\pi/2 \) as \( x \to -\infty \)
By comprehending how functions behave asymptotically, one gains a deeper appreciation for solving calculus problems that examine the limits of tangents and logarithms at or approaching infinity or zero.
Other exercises in this chapter
Problem 40
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