Problem 40
Question
Find the indicated term(s) of the geometric sequence with the given description. The first term is \(\frac{1}{12}\) and the second term is \(-\frac{1}{2} .\) Find the sixth term.
Step-by-Step Solution
Verified Answer
The sixth term is -648.
1Step 1: Identify the formula
The formula to find any term in a geometric sequence is given by: \[ a_n = a_1 imes r^{(n-1)} \] where \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the term number.
2Step 2: Find the common ratio
Using the information given:\[ a_1 = \frac{1}{12}, \quad a_2 = -\frac{1}{2} \]To find the common ratio \( r \), we use the formula:\[ r = \frac{a_2}{a_1} = \frac{-\frac{1}{2}}{\frac{1}{12}} = -6 \]The common ratio \( r \) is \(-6\).
3Step 3: Use the formula to find the sixth term
Now that we know \( a_1 = \frac{1}{12} \) and \( r = -6 \), we can use the formula for the nth term:\[ a_6 = a_1 imes r^{(6-1)} = \frac{1}{12} imes (-6)^5 \]Calculate \((-6)^5\):\[ (-6)^5 = -7776 \]So the sixth term is:\[ a_6 = \frac{1}{12} imes -7776 = -648 \]
4Step 4: Conclusion
The sixth term of the geometric sequence is \(-648\).
Key Concepts
Understanding the Common RatioApplying the nth Term FormulaSequence Term Calculation in Practice
Understanding the Common Ratio
A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed number called the 'common ratio'.
To find the common ratio, we divide any term by the preceding term.
For the sequence in our exercise, with the first term, \( a_1 = \frac{1}{12} \), and the second term, \( a_2 = -\frac{1}{2} \), the common ratio \( r \) can be calculated as follows:
To find the common ratio, we divide any term by the preceding term.
For the sequence in our exercise, with the first term, \( a_1 = \frac{1}{12} \), and the second term, \( a_2 = -\frac{1}{2} \), the common ratio \( r \) can be calculated as follows:
- Divide the second term by the first term: \( r = \frac{a_2}{a_1} = \frac{-\frac{1}{2}}{\frac{1}{12}} \)
- This simplifies to \( r = -6 \)
Applying the nth Term Formula
The nth term formula is a crucial tool in any geometric sequence. It allows us to find any term in the sequence quickly without having to calculate all the preceding terms.
The formula is:
The formula is:
- \( a_n = a_1 \times r^{(n-1)} \)
- \( a_n \) is the term number we want to find.
- \( a_1 \) is the first term of the sequence.
- \( r \) is the common ratio.
- \( n \) is the position of the term in the sequence.
Sequence Term Calculation in Practice
To determine the sixth term in the example sequence, we must substitute known values into the nth term formula.
We already know:
By using these calculations, we navigate through the geometric sequence efficiently.
We already know:
- First term, \( a_1 = \frac{1}{12} \)
- Common ratio, \( r = -6 \)
- The term position, \( n = 6 \)
- \((-6) \times (-6) \times (-6) \times (-6) \times (-6) = -7776 \)
By using these calculations, we navigate through the geometric sequence efficiently.
Other exercises in this chapter
Problem 39
Find the first six partial sums \(S_{1}, S_{2}, S_{3}\), \(S_{4}, S_{5}, S_{6}\) of the sequence whose \(n\)th term is given. \(1,3,5,7, \dots\)
View solution Problem 40
Determine the common difference, the fifth term, the \(n\) th term, and the 100 th term of the arithmetic sequence. $$\frac{7}{6}, \frac{5}{3}, \frac{13}{6}, \f
View solution Problem 40
Find the indicated terms in the expansion of the given binomial. The term containing \(y^{3}\) in the expansion of \((\sqrt{2}+y)^{12}\).
View solution Problem 40
Find the first six partial sums \(S_{1}, S_{2}, S_{3}\), \(S_{4}, S_{5}, S_{6}\) of the sequence whose \(n\)th term is given. \(1^{2}, 2^{2}, 3^{2}, 4^{2}, \ldo
View solution