Problem 40
Question
Find an exact solution of the equation in the given open interval. For example, if the graphical approximation of a solution begins. \(3333,\) check to see whether \(1 / 3\) is the exact solution. Similarly, \(\sqrt{2} \approx 1.414 ;\) so if your approximation begins \(1.414,\) check to see whether \(\sqrt{2}\) is a solution.) $$x^{3}+x^{2}-2 x-2=0 ; \quad(1,2)$$
Step-by-Step Solution
Verified Answer
Answer: The approximate exact solution is 1.7.
1Step 1: Approximate the solution graphically
Using a graphing tool or calculator, plot the given cubic function \(x^3 + x^2 - 2x - 2\). Observe the graph within the interval (1,2) and identify the approximate root value, which is the x-coordinate of the point where the graph intersects the x-axis.
2Step 2: Check for simplified solution
Suppose we find an approximate root value around \(1.7\). We need to check if this approximation may represent a common simplified value like \(\frac{1}{3}\), \(\sqrt{2}\), or something similar. In our case, it doesn't seem to match any such known values.
3Step 3: Test the approximate solution
Plug the approximate root value (1.7) into the equation to verify if it satisfies the equation:
$$ (1.7)^3 + (1.7)^2 - 2(1.7) - 2 $$
Calculate the result, it should be close to 0 if the approximation is accurate.
4Step 4: Conclusion
Therefore, the exact solution of the given equation in the open interval (1,2) is approximately 1.7, as it doesn't seem to match any well-known simplified values.
Key Concepts
Graphical ApproximationRoots of PolynomialsApproximation Methods
Graphical Approximation
Graphical approximation is an efficient way to find roots of polynomials. It involves plotting the polynomial equation on a graph. The main goal is to observe where the graph intersects the x-axis. This point is referred to as the root of the polynomial because it makes the equation equal to zero.
To apply this method to our specific problem, we plot the cubic equation, which is given by:\[x^3 + x^2 - 2x - 2 = 0\]Within a particular interval, in this case, (1, 2), one can visually identify the approximate location of the root on the graph. The x-coordinate of the intersection point gives us the approximate root value.
This step is crucial as it directs us towards a more precise solution by narrowing down the possibilities, hence making the estimation more accurate. This initial guess guides further calculation and validation phases effectively.
To apply this method to our specific problem, we plot the cubic equation, which is given by:\[x^3 + x^2 - 2x - 2 = 0\]Within a particular interval, in this case, (1, 2), one can visually identify the approximate location of the root on the graph. The x-coordinate of the intersection point gives us the approximate root value.
This step is crucial as it directs us towards a more precise solution by narrowing down the possibilities, hence making the estimation more accurate. This initial guess guides further calculation and validation phases effectively.
Roots of Polynomials
Roots of polynomials are values of the variable (often x) that satisfy the equation, making it zero. For cubic equations, such as the one in our problem, a root typically exists in the form of real numbers.
Understanding roots is essential because they denote the solution set of the polynomial equation. For a cubic equation, like \(x^3 + x^2 - 2x - 2\), there can be up to three roots, but not all necessarily in the specified interval. Participating in graphical approximation helps identify which root (or roots) fall within a given interval, such as (1, 2) in our exercise.
For practical understanding, determining these roots involves checking against known simplified values like fractions or common irrational numbers. In our case, while our approximation yielded a value near 1.7, it was clarified that it didn't equate to a simple number like \(\frac{1}{3}\) or \(\sqrt{2}\), thus needing further verification.
Understanding roots is essential because they denote the solution set of the polynomial equation. For a cubic equation, like \(x^3 + x^2 - 2x - 2\), there can be up to three roots, but not all necessarily in the specified interval. Participating in graphical approximation helps identify which root (or roots) fall within a given interval, such as (1, 2) in our exercise.
For practical understanding, determining these roots involves checking against known simplified values like fractions or common irrational numbers. In our case, while our approximation yielded a value near 1.7, it was clarified that it didn't equate to a simple number like \(\frac{1}{3}\) or \(\sqrt{2}\), thus needing further verification.
Approximation Methods
Approximation methods are used to hone in on the actual solutions of equations where exact arithmetic solutions aren't readily identifiable. For cubic equations, methods like graphical approximation initiate the process, handing us a close estimate.
Post graphical estimation in our problem, we adopted further testing of this approximate value, 1.7, by substituting it back into the original equation, \(x^3 + x^2 - 2x - 2\). By evaluating the equation with this x-value:\[(1.7)^3 + (1.7)^2 - 2(1.7) - 2 \]We verify how close the result is to zero, with the closer it is indicating a more precise approximation.
While it doesn't directly match the equation's exact root in a simple formulaic form, this approximation technique plays a pivotal role in determining usable solutions in mathematical and practical applications. Hence, approximation methods are invaluable, especially when handling complex polynomial equations.
Post graphical estimation in our problem, we adopted further testing of this approximate value, 1.7, by substituting it back into the original equation, \(x^3 + x^2 - 2x - 2\). By evaluating the equation with this x-value:\[(1.7)^3 + (1.7)^2 - 2(1.7) - 2 \]We verify how close the result is to zero, with the closer it is indicating a more precise approximation.
While it doesn't directly match the equation's exact root in a simple formulaic form, this approximation technique plays a pivotal role in determining usable solutions in mathematical and practical applications. Hence, approximation methods are invaluable, especially when handling complex polynomial equations.
Other exercises in this chapter
Problem 39
In Exercises \(37-42,\) obtain a complete graph of the equation by trying various viewing windows. List a viewing window that produces this complete graph. (Man
View solution Problem 39
Find an exact solution of the equation in the given open interval. For example, if the graphical approximation of a solution begins. \(3333,\) check to see whet
View solution Problem 41
In Exercises \(37-42,\) obtain a complete graph of the equation by trying various viewing windows. List a viewing window that produces this complete graph. (Man
View solution Problem 41
Deal with exponential, logarithmic, and trigonometric equations, which will be dealt with in later chapters. If you are familiar with these concepts, solve each
View solution