Problem 40
Question
Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Focal diameter 8 and focus on the negative \(y\) -axis
Step-by-Step Solution
Verified Answer
The equation of the parabola is \( x^2 = 8y \).
1Step 1: Understand the Parabola's Orientation
Since the focus is on the negative y-axis, the parabola opens downwards. This means the equation of the parabola is of the form \( x^2 = -4py \).
2Step 2: Calculate the Value of \( p \)
The focal diameter is the absolute value of \( 4p \). We are given that the focal diameter is 8, so\[ |4p| = 8 \].Solving for \( p \), we divide both sides by 4:\[ |p| = 2 \].Since the parabola opens downwards, \( p \) is negative. Thus, \( p = -2 \).
3Step 3: Write the Equation of the Parabola
Now that we know \( p = -2 \), substitute this value into the equation form:\[ x^2 = -4(-2)y \].Simplify the equation:\[ x^2 = 8y \].
Key Concepts
Vertex at OriginFocal DiameterNegative Y-Axis Focus
Vertex at Origin
A parabola can be thought of as a U-shaped curve that has particular points of interest, including the vertex. The vertex is the highest or lowest point of the parabola, depending on whether it opens upwards or downwards. In this case, the parabola in question has its vertex at the origin, which is the point
Having the vertex at the origin simplifies the equation of the parabola because it removes the need for translating the formula. Normally, if the vertex was at a different location, say
- (0,0)
Having the vertex at the origin simplifies the equation of the parabola because it removes the need for translating the formula. Normally, if the vertex was at a different location, say
- (h,k)
Focal Diameter
The focal diameter is a significant concept when working with parabolas. It refers to the total width of the parabola at the focus.
Mathematically, the focal diameter is given by the formula
Mathematically, the focal diameter is given by the formula
- |4p|
- p
- p
- |4p| = 8
- |p| = 2
- p
- p = -2
Negative Y-Axis Focus
The focus of a parabola is a fundamental feature. It is a point from which distances are measured to define the parabola. For a parabola with the vertex at the origin opening downwards, the focus is located on the negative y-axis.
In our example, given that the vertex is
The negative sign in the equation affirms the direction towards the negative y-axis, making all concepts harmoniously tie together.
In our example, given that the vertex is
- (0,0)
- p = -2
- (0,-2)
- x^2 = 8y
The negative sign in the equation affirms the direction towards the negative y-axis, making all concepts harmoniously tie together.
Other exercises in this chapter
Problem 40
A polar equation of a conic is given. (a) Find the eccentricity and the directrix of the conic. (b) If this conic is rotated about the origin through the given
View solution Problem 40
Find an equation for the ellipse that satisfies the given conditions. Endpoints of minor axis: \((0, \pm 3),\) distance between foci: 8
View solution Problem 41
Find an equation for the hyperbola that satisfies the given conditions. Foci: \((\pm 5,0),\) length of transverse axis: 6
View solution Problem 41
Graph the conics \(r=e /(1-e \cos \theta)\) with \(e=0.4,0.6,0.8\) and 1.0 on a common screen. How does the value of \(e\) affect the shape of the curve?
View solution