Problem 40
Question
Find all intercepts for the graph of each quadratic function. $$y=x^{2}-x-6$$
Step-by-Step Solution
Verified Answer
The y-intercept is (0, -6). The x-intercepts are (3, 0) and (-2, 0).
1Step 1: Find the y-intercept
To find the y-intercept of the graph, set x to 0 in the equation and solve for y. \[ y = 0^2 - 0 - 6 \] \[ y = -6 \] The y-intercept is (0, -6).
2Step 2: Find the x-intercepts by factoring
To find the x-intercepts, set y to 0 in the equation and solve for x. \[ 0 = x^2 - x - 6 \] Factor the quadratic equation: \[ 0 = (x - 3)(x + 2) \] Set each factor to zero: \[ x - 3 = 0 \text{ or } x + 2 = 0 \] Solve for x: \[ x = 3 \] \[ x = -2 \] The x-intercepts are (3, 0) and (-2, 0).
Key Concepts
y-interceptx-interceptsfactoring quadraticssolving equations
y-intercept
To find the y-intercept of a quadratic function, you simply need to set the x-value to zero and solve for y. This is because the y-intercept is the point where the graph crosses the y-axis, which is always at x = 0.
Let's go through an example with the equation: \( y = x^2 - x - 6 \).
Setting x to 0 gives us: \[ y = 0^2 - 0 - 6 \] \[ y = -6 \]
Therefore, the y-intercept for this quadratic function is \( (0, -6) \). This tells us that the graph will cross the y-axis at the point where y is -6.
Let's go through an example with the equation: \( y = x^2 - x - 6 \).
Setting x to 0 gives us: \[ y = 0^2 - 0 - 6 \] \[ y = -6 \]
Therefore, the y-intercept for this quadratic function is \( (0, -6) \). This tells us that the graph will cross the y-axis at the point where y is -6.
x-intercepts
Finding x-intercepts involves setting y to zero and solving for x, as these are the points where the graph crosses the x-axis (y = 0).
Using the same equation from earlier: \( y = x^2 - x - 6 \), we set y to 0:
\[ 0 = x^2 - x - 6 \]
This equation needs to be solved for x to find the intercepts. The x-intercepts of this function are the points where the graph cuts the x-axis.
Using the same equation from earlier: \( y = x^2 - x - 6 \), we set y to 0:
\[ 0 = x^2 - x - 6 \]
This equation needs to be solved for x to find the intercepts. The x-intercepts of this function are the points where the graph cuts the x-axis.
factoring quadratics
To solve the quadratic equation, we use a method called factoring. Factoring involves breaking down the quadratic equation into simpler expressions (factors) that can be multiplied together to return to the original equation.
For our equation \( x^2 - x - 6 \), we look for two numbers that multiply to -6 (the constant term) but add up to -1 (the coefficient of the middle term).
The pair of numbers -3 and 2 fit these criteria, so we can write:
\[ x^2 - x - 6 = (x - 3)(x + 2) \]
This means our quadratic equation can be rewritten as \( (x - 3)(x + 2) = 0 \).
For our equation \( x^2 - x - 6 \), we look for two numbers that multiply to -6 (the constant term) but add up to -1 (the coefficient of the middle term).
The pair of numbers -3 and 2 fit these criteria, so we can write:
\[ x^2 - x - 6 = (x - 3)(x + 2) \]
This means our quadratic equation can be rewritten as \( (x - 3)(x + 2) = 0 \).
solving equations
Now, we can solve the equation by setting each factor to zero. This is based on the zero-product property, which states that if a product of factors equals zero, at least one of the factors must be zero.
So, we solve the following equations:
\[ x - 3 = 0 \] \[ x + 2 = 0 \]
Solving these, we get:
\[ x = 3 \] \[ x = -2 \]
Therefore, the x-intercepts of the quadratic function \( y = x^2 - x - 6 \) are \( (3, 0) \) and \( (-2, 0) \). These points indicate where the graph crosses the x-axis.
So, we solve the following equations:
\[ x - 3 = 0 \] \[ x + 2 = 0 \]
Solving these, we get:
\[ x = 3 \] \[ x = -2 \]
Therefore, the x-intercepts of the quadratic function \( y = x^2 - x - 6 \) are \( (3, 0) \) and \( (-2, 0) \). These points indicate where the graph crosses the x-axis.
Other exercises in this chapter
Problem 39
Find all intercepts for the graph of each quadratic function. $$y=x^{2}-2 x-8$$
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Find \(b^{2}-4 a c\) and the number of real solutions to each equation. $$\frac{1}{2} w^{2}-\frac{1}{3} w+\frac{1}{4}=0$$
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Find all intercepts for the graph of each quadratic function. $$f(x)=-4 x^{2}+12 x-9$$
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Find \(b^{2}-4 a c\) and the number of real solutions to each equation. $$9-24 z+16 z^{2}=0$$
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