Problem 40
Question
Find a polar equation that is equivalent to the given rectangular equation. $$y=x-2$$
Step-by-Step Solution
Verified Answer
Question: Given the rectangular equation y=x-2, find the equivalent polar equation.
Answer: The equivalent polar equation is $$r=\frac{-2}{sin(\theta)-cos(\theta)}$$.
1Step 1: Write down the given rectangular equation
We are given the rectangular equation:
$$y=x-2$$
2Step 2: Substitute the expressions for x and y in polar coordinates
Replace x with $$rcos(\theta)$$ and y with $$rsin(\theta)$$ in the given equation:
$$rsin(\theta)=rcos(\theta)-2$$
3Step 3: Simplify the equation
Factor out r from the equation:
$$r(sin(\theta)-cos(\theta))=-2$$
4Step 4: Isolate r
Divide both sides of the equation by $$(sin(\theta)-cos(\theta))$$ to isolate r:
$$r=\frac{-2}{sin(\theta)-cos(\theta)}$$
So, the equivalent polar equation is:
$$r=\frac{-2}{sin(\theta)-cos(\theta)}$$.
Key Concepts
Rectangular to Polar ConversionTrigonometric SubstitutionEquation Simplification
Rectangular to Polar Conversion
Converting rectangular equations to polar form involves translating a system based on Cartesian coordinates into one using polar coordinates. In rectangular coordinates, a point in the plane is described by \(x, y\). In polar coordinates, a point is described using \(r\) (the distance from the origin) and \(\theta\) (the angle from the positive x-axis). This conversion is essential for solving problems involving circular and rotational symmetries, which are inherently simpler in polar terms.
### Common Substitutions
To perform a rectangular to polar conversion, you should know these key substitutions:
Substitute \(x\) with \(r\cos(\theta)\) and \(y\) with \(r\sin(\theta)\), resulting in:
### Common Substitutions
To perform a rectangular to polar conversion, you should know these key substitutions:
- \(x = r\cos(\theta)\)
- \(y = r\sin(\theta)\)
- \(r^2 = x^2 + y^2\) (although not used in this problem, it's useful for others)
Substitute \(x\) with \(r\cos(\theta)\) and \(y\) with \(r\sin(\theta)\), resulting in:
- \(r\sin(\theta) = r\cos(\theta) - 2\)
Trigonometric Substitution
Trigonometric substitution plays a vital role in converting and simplifying trigonometric equations. Once we've substituted the polar relations into the rectangular equation, using trigonometric identities and algebra helps manipulate the equation into a more recognizable form.
### Understanding the EquationGiven the equation after substitution: \(r\sin(\theta) = r\cos(\theta) - 2\), it's important to manage the terms efficiently. This involves grouping them to isolate specific components.
### FactorizationIn step 3 of the solution, factor out \(r\) such that:
### Understanding the EquationGiven the equation after substitution: \(r\sin(\theta) = r\cos(\theta) - 2\), it's important to manage the terms efficiently. This involves grouping them to isolate specific components.
### FactorizationIn step 3 of the solution, factor out \(r\) such that:
- \(r(sin(\theta) - cos(\theta)) = -2\)
Equation Simplification
Simplification of equations, especially in polar form, is essential for making the relationship between variables clear and concise. In polar coordinates, variables are often intertwined through trigonometric functions.
### Isolating rIn the final step, isolate \(r\) by dividing both sides of the equation by the combined trigonometric function \(sin(\theta) - cos(\theta)\):
### Importance of SimplificationSimplification helps not only for clarity but also for computational purposes, especially when analyzing the behavior of polar plots. In our example, it moves from a linear Cartesian relationship to one involving division by a trigonometric function, opening new methods of analysis and visualization.
### Isolating rIn the final step, isolate \(r\) by dividing both sides of the equation by the combined trigonometric function \(sin(\theta) - cos(\theta)\):
- \(r = \frac{-2}{sin(\theta) - cos(\theta)}\)
### Importance of SimplificationSimplification helps not only for clarity but also for computational purposes, especially when analyzing the behavior of polar plots. In our example, it moves from a linear Cartesian relationship to one involving division by a trigonometric function, opening new methods of analysis and visualization.
Other exercises in this chapter
Problem 40
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