Problem 40
Question
Factor out the greatest common factor. Be sure to check your answer. $$a(9 c+4)-b(9 c+4)$$
Step-by-Step Solution
Verified Answer
The short answer is: \((9c+4)(a - b)\)
1Step 1: Identify the greatest common factor
The given expression is \(a(9c+4) - b(9c+4)\). Observe that both terms have the common factor \((9c+4)\).
2Step 2: Factor out the common factor
Now that we have identified the common factor \((9c+4)\), we can factor it out from the expression. This is done by rewriting the expression as a product of the common factor and another expression:
\((9c+4)(a - b)\)
3Step 3: Check the answer
To make sure our solution is correct, we can expand the factored expression to see if it matches the original one:
\((9c+4)(a-b) = (9c+4)a - (9c+4)b = a(9c+4) - b(9c+4)\)
Since the factored form and the original expression match, we can be confident that our solution is correct. So, the factored expression is:
\((9c+4)(a - b)\)
Key Concepts
Understanding the Greatest Common Factor (GCF)Algebra and Expression ManipulationMastering Expanding Expressions
Understanding the Greatest Common Factor (GCF)
When faced with expressions or numbers, one useful technique is to find the Greatest Common Factor (GCF). The GCF is the largest factor that two or more numbers or terms have in common. For expressions, it involves identifying the common divisors of the terms within the expression.
Imagine you have two numbers, like 8 and 12. Their factors are:
For algebraic expressions, finding the GCF is similar but involves variables and coefficients. In the exercise expression \(a(9c+4) - b(9c+4)\), \((9c+4)\) is the common factor for both terms. By factoring it out, calculations and simplifications become easier.
Imagine you have two numbers, like 8 and 12. Their factors are:
- 8: 1, 2, 4, 8
- 12: 1, 2, 3, 4, 6, 12
For algebraic expressions, finding the GCF is similar but involves variables and coefficients. In the exercise expression \(a(9c+4) - b(9c+4)\), \((9c+4)\) is the common factor for both terms. By factoring it out, calculations and simplifications become easier.
Algebra and Expression Manipulation
Algebra is a branch of mathematics dealing with symbols and the rules for manipulating these symbols. It's the language of mathematics that allows us to express general mathematical ideas on how different objects relate.
Algebraic expressions are key components, composed of numbers, variables (letters), and operations (like addition and subtraction). In the given expression \(a(9c+4) - b(9c+4)\), we deal with two terms involving multiplication and subtraction.
The ability to manipulate and simplify these expressions is crucial. For example, recognizing common factors can lead to simplified expressions, which are easier to evaluate and solve. In fact, utilizing the concept of factoring, we efficiently reformulate our expression into \((9c+4)(a - b)\) by recognizing the shared part of both terms.
Algebraic expressions are key components, composed of numbers, variables (letters), and operations (like addition and subtraction). In the given expression \(a(9c+4) - b(9c+4)\), we deal with two terms involving multiplication and subtraction.
The ability to manipulate and simplify these expressions is crucial. For example, recognizing common factors can lead to simplified expressions, which are easier to evaluate and solve. In fact, utilizing the concept of factoring, we efficiently reformulate our expression into \((9c+4)(a - b)\) by recognizing the shared part of both terms.
Mastering Expanding Expressions
Expanding expressions is essentially the opposite of factoring them. It involves taking a factored expression and distributing the factors across the terms to reach the original state. This step is key when checking your work in algebra.
In our problem, once the expression is factored as \((9c+4)(a-b)\), we expand it to verify correctness by distributing:
In our problem, once the expression is factored as \((9c+4)(a-b)\), we expand it to verify correctness by distributing:
- \((9c+4) \times a\) becomes \(a(9c+4)\)
- \((9c+4) \times -b\) becomes \(-b(9c+4)\)
Other exercises in this chapter
Problem 40
Factor completely. $$q^{2}+9$$
View solution Problem 40
Solve each equation. $$104 r+36=12 r^{2}$$
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Factor by trial and error. $$10 m^{2}+47 m-15$$
View solution Problem 40
Factor completely by first taking out \(-1\) and then by factoring the trinomial, if possible. Check your answer. $$-b^{2}+17 b-66$$
View solution