Problem 40
Question
Express the first trigonometric function in terms of the second. $$ \tan \theta, \cos \theta $$
Step-by-Step Solution
Verified Answer
The first trigonometric function \( \tan \theta \) can be expressed in terms of the second \( \cos \theta \) as \( \tan \theta = \frac{\sqrt{1 - \cos^2 \theta}}{\cos \theta} \).
1Step 1: Write \( \tan \theta \) using sin and cos
The trigonometric identity of \( \tan \theta \) is \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
2Step 2: Express \( \sin \theta \) in terms of \( \cos \theta \)
The Pythagorean identity \( \sin^2 \theta + \cos^2 \theta =1 \) can be rearranged to solve for \( \sin \theta \) as \( \sin \theta= \sqrt{1 - \cos^2 \theta} \)
3Step 3: Substitute \( \sin \theta \) in the equation
Step 1 and 2 are substituted into the original equation of \( \tan \theta \) in terms of \( \sin \theta \) and \( \cos \theta \) yielding \( \tan \theta = \frac{\sqrt{1 - \cos^2 \theta}}{\cos \theta} \).
Key Concepts
Trigonometric IdentitiesPythagorean IdentityTrigonometric Expressions
Trigonometric Identities
Trigonometric identities are key equations that involve trigonometric functions, such as sine, cosine, and tangent. They are fundamental tools for simplifying trigonometric expressions and proving other mathematical statements. One of the most frequently encountered identities is the identity for tangent:
- \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
Pythagorean Identity
The Pythagorean identity is an essential trigonometric identity that relates the square of the sine and cosine functions. It is named for its resemblance to the Pythagorean theorem in geometry. The Pythagorean identity is given as:
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
- \( \sin \theta = \sqrt{1 - \cos^2 \theta} \)
Trigonometric Expressions
Trigonometric expressions are combinations of trigonometric functions that represent angles in various mathematical problems. These expressions can often be simplified or re-expressed using known trigonometric identities. For instance, to express \( \tan \theta \) in terms of \( \cos \theta \), you begin with the identity:
- \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
- \( \sin \theta = \sqrt{1 - \cos^2 \theta} \)
- \( \tan \theta = \frac{\sqrt{1 - \cos^2 \theta}}{\cos \theta} \)
Other exercises in this chapter
Problem 40
Verify each identity. $$ \tan (A+B)=\frac{\tan A+\tan B}{1-\tan A \tan B} $$
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In \(\triangle A B C, m \angle A=40^{\circ}\) and \(m \angle B=30^{\circ} .\) Find each value to the nearest tenth. Find \(A C\) for \(A B=81.2\) yd.
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In \(\triangle A B C, \angle C\) is a right angle. Two measures are given. Find the remaining sides and angles. Round your answers to the nearest tenth. \(m \an
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Given \(\cos \theta=\frac{3}{5} \operatorname{and} 270^{\circ}
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