Problem 40
Question
Each of the following sets is the solution of an inequality of the form \(|x-c|<\delta\). Find \(c\) and \(\delta\). $$(0,4)$$.
Step-by-Step Solution
Verified Answer
The pair \((c, \delta)\) that satisfies the given inequality with the interval \((0, 4)\) as its solution is \((2, 2)\).
1Step 1: Identifying the center of interval
To find \(c\), we calculate the center of the interval \((0, 4)\) by taking the average of \(0\) and \(4\). This yields \(c=2\).
2Step 2: Identifying delta
To find \(\delta\), we calculate the difference between any one end of the interval and the center from Step 1. Hence \(\delta=2\).
Key Concepts
Absolute Value InequalityInterval NotationSolution SetsCenter of Interval
Absolute Value Inequality
Absolute value inequalities tell us about the distance from a point on the number line. For the inequality \(|x - c| < \delta\), it means that the distance between \(x\) and \(c\) is less than \(\delta\). This creates an interval centered at \(c\) with a radius of \(\delta\).
If we take the inequality \(|x - c| < 2\), this defines all the points within 2 units of \(c\). Whenever you see an absolute value inequality like this, imagine a flexible boundary stretching equally in both directions from the center point \(c\).
If we take the inequality \(|x - c| < 2\), this defines all the points within 2 units of \(c\). Whenever you see an absolute value inequality like this, imagine a flexible boundary stretching equally in both directions from the center point \(c\).
- "Less than" (\(<\)) generates an open interval.
- "Greater than" (\(>\)) creates a different kind of solution, usually involving multiple intervals.
Interval Notation
Interval notation is a shorthand way to describe a set of numbers along the number line. It uses brackets and parentheses to denote closed and open intervals. In our example, the interval \((0, 4)\), the parentheses signify that 0 and 4 are not included in the set.
- Use \((a, b)\) for open intervals where endpoints \(a\) and \(b\) are not included.- Use \([a, b]\) for closed intervals where both endpoints are included.
In inequalities, switching between expressions like \(|x - c| < \delta\) and interval notation \((c - \delta, c + \delta)\) helps visualize solutions.
- Use \((a, b)\) for open intervals where endpoints \(a\) and \(b\) are not included.- Use \([a, b]\) for closed intervals where both endpoints are included.
In inequalities, switching between expressions like \(|x - c| < \delta\) and interval notation \((c - \delta, c + \delta)\) helps visualize solutions.
Solution Sets
A solution set indicates all the possible values of \(x\) that satisfy the inequality. From the original problem, the solution set is \((0, 4)\), meaning any \(x\) between these numbers satisfies the inequality.
The concept of solution sets:
The concept of solution sets:
- Helps understand what values work for your inequality.
- Describes these values using interval notation.
- Visualizes them on a number line, providing a clear picture of inclusivity or exclusivity.
Center of Interval
To find the center \(c\) of an interval, you calculate the average of its endpoints. In our exercise, the interval is \((0, 4)\), so the center is determined by the formula \(c = \frac{0 + 4}{2}\), yielding \(c = 2\).
The center is crucial in absolute value inequalities as it represents the midpoint around which the distance (\(\delta\)) is measured. Hence, finding this center correctly informs the rest of the problem:
The center is crucial in absolute value inequalities as it represents the midpoint around which the distance (\(\delta\)) is measured. Hence, finding this center correctly informs the rest of the problem:
- It tells us where the "heart" of the interval lies.
- It provides a reference point for calculating \(\delta\).
Other exercises in this chapter
Problem 40
Evaluate to four decimal place accuracy. $$\cos 17^{\circ}$$.
View solution Problem 40
Find the point where the lines intersect. $$l_{1}: 3 x \cdot y-5=0, \quad l_{2}: 7 x-10 y+27=0$$
View solution Problem 41
Find \(g\) such that \(f \circ g=F\) given that $$f(x)=x^{2}+1 , F(x)=\left(2 x^{3}-1\right)^{2}+1$$
View solution Problem 41
Find the number \((s) x\) in the interval \([0,2 \pi j]\) which satisfy the equation. $$\sin x=-\frac{1}{2}$$
View solution