Problem 40
Question
Draw by hand a rough sketch of the graph of each function. (You may wish to support your answer with a calculator graph.) $$\begin{aligned}P(x) &=3 x^{4}-4 x^{3}-22 x^{2}+15 x+18 \\\&=(3 x+2)(x-3)\left(x^{2}+x-3\right)\end{aligned}$$
Step-by-Step Solution
Verified Answer
Graph shows quartic curve with zeros at \(x = -\frac{2}{3}, 3, \frac{-1 \pm \sqrt{13}}{2}\), and turning points.
1Step 1: Identify the degree of the polynomial
The polynomial given is of degree 4 because the highest power of \(x\) is 4. Thus, the graph will resemble a quartic function, which typically can have up to 3 turning points and begins and ends in the same direction (upward if the leading coefficient is positive).
2Step 2: Identify the zeros of the polynomial
Look for the roots of the factors of the polynomial. From \((3x+2)=0\), we find \(x=-\frac{2}{3}\). From \(x-3=0\), we have \(x=3\). Solving \(x^2 + x - 3 = 0\) using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\), which results in \(x = \frac{-1 \pm \sqrt{13}}{2}\). Hence, the zeros are \(x = -\frac{2}{3}\), \(x = 3\), \(x = \frac{-1 + \sqrt{13}}{2}\), and \(x = \frac{-1 - \sqrt{13}}{2}\).
3Step 3: Determine the end behavior
Since the leading term is \(3x^4\) and its coefficient is positive, both the left and right ends of the graph will point upwards.
4Step 4: Sketch the graph using zeros and end behavior
Plot the x-axis and mark the zeros found: \(x = -\frac{2}{3}\), \(x = 3\), \(x = \frac{-1 + \sqrt{13}}{2}\), and \(x = \frac{-1 - \sqrt{13}}{2}\). The graph starts from above the x-axis (because the end behavior is upwards), goes through each zero, and ends upwards again after \(x = 3\). Make sure the graph has turns between these points to represent up to 3 turns typical of a quartic polynomial.
Key Concepts
Polynomial DegreeRoots of a PolynomialEnd BehaviorGraph Sketching
Polynomial Degree
The degree of a polynomial is determined by its highest power of the variable. In our exercise, the polynomial is given by \(P(x) = 3x^4 - 4x^3 - 22x^2 + 15x + 18\). The highest power of \(x\) here is 4, which means we are working with a quartic polynomial.
This defines several important characteristics of the graph:
This defines several important characteristics of the graph:
- A quartic function can have up to 4 roots, or zeros, where it intersects the x-axis.
- Typically, this function will also have up to 3 turning points, where the direction of the graph changes.
Roots of a Polynomial
The roots or zeros of a polynomial are the x-values for which the polynomial equals zero. Finding these roots is crucial for sketching the graph because each root corresponds to an x-intercept.
For our polynomial \((3x+2)(x-3)(x^{2}+x-3)\):
For our polynomial \((3x+2)(x-3)(x^{2}+x-3)\):
- The factor \((3x+2)\) gives the root \(x = -\frac{2}{3}\).
- The factor \((x-3)\) gives the root \(x = 3\).
- Using the quadratic formula on \(x^2 + x - 3\), we find two additional roots: \(x = \frac{-1 + \sqrt{13}}{2}\) and \(x = \frac{-1 - \sqrt{13}}{2}\).
End Behavior
End behavior describes how the polynomial behaves as \(x\) approaches infinity or negative infinity. This gives us an understanding of how the graph extends beyond the identifiable roots and turning points.
For our quartic polynomial, the term \(3x^4\) governs the end behavior. Since the leading coefficient (3) is positive, both ends of the graph will point upwards.
For our quartic polynomial, the term \(3x^4\) governs the end behavior. Since the leading coefficient (3) is positive, both ends of the graph will point upwards.
- As \(x\) approaches \(+\infty\), \(3x^4\) becomes larger and moves the graph upwards.
- As \(x\) approaches \(-\infty\), \(3x^4\) still dominates and the graph goes upward here as well.
Graph Sketching
Graph sketching involves combining all the information we've gathered regarding the degree, roots, and end behavior to create a visual representation of the polynomial.
To sketch the polynomial from our exercise:
To sketch the polynomial from our exercise:
- Begin by plotting the x-axis and marking the roots \((-\frac{2}{3}, 0)\), \((3, 0)\), \((\frac{-1+\sqrt{13}}{2}, 0)\), and \((\frac{-1-\sqrt{13}}{2}, 0)\).
- Since the end behavior points both ends upward, sketch the graph entering from the top-left quadrant and exiting through the top-right quadrant.
- Ensure the graph has up to 3 turning points where the direction changes, consistent with the properties of a quartic function.
Other exercises in this chapter
Problem 39
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