Problem 40
Question
Determine whether the series converges or diverges. In this set of problems knowledge of all the convergence tests from the chapter is assumed. \(\sum_{k=1}^{\infty}\left(1+\frac{1}{k}\right)^{k}\)
Step-by-Step Solution
Verified Answer
The series \(\sum_{k=1}^{\infty}\left(1+\frac{1}{k}\right)^{k}\) is divergent.
1Step 1: Recognizing the type of problem
The problem gives an infinite series and asks to determine if it converges or diverges. The series belongs to the type \(a_n^n\), which is optimal for application of the Root Test.
2Step 2: Apply the Root Test
The Root Test states that if we have a series \(\sum a_n\) and we can find \(\lim_{{k\to\infty}} |a_k|^{\frac{1}{k}} = L\), then if \(L<1\), the series converges, if \(L>1\), the series diverges, and if \(L=1\), the test is inconclusive. Apply this to our series, we get \(\lim_{{k\to\infty}} \left|\left(1+\frac{1}{k}\right)^{k}\right|^{\frac{1}{k}} = \lim_{{k\to\infty}} \left(1+\frac{1}{k}\right)\). As \(k\) approaches infinity, \(\frac{1}{k}\) approaches 0, so \(\lim_{{k\to\infty}} \left(1+\frac{1}{k}\right) =1\). This makes this test inconclusive here.
3Step 3: Apply the Ratio Test
Since the Root Test did not give a clear result, let's attempt the Ratio Test. The Ratio Test states that if we can find \(\lim_{{k\to\infty}} \frac{|a_{k+1}|}{|a_k|} = L\), if \(L<1\), the series converges, if \(L>1\), the series diverges, and if \(L=1\), the test is inconclusive. Apply the Ratio Test to our series, the limit is also 1. Thus, the Ratio Test is also inconclusive and we don't have a clear determination of the series.
4Step 4: Refer to the Limit of sequence
If all our traditional tests fail, we can look at the limit of the sequence itself. If the limit as n goes to infinity of \(a_n\) is not zero, the series must diverge. Here,\(\lim_{k\to\infty} \left(1+\frac{1}{k}\right)^{k}\) is a well-known limit that equals \(e\) which is approximately 2.7, and is definitely not zero. So by this, we conclude that the series is divergent.
Key Concepts
Root TestRatio TestDivergent SeriesLimit of a Sequence
Root Test
Understanding the Root Test can be vital in determining the behavior of an infinite series. This test is particularly useful for series where each term is raised to a power, like in the provided problem. The Root Test says you calculate the limit of the absolute value of the series' terms raised to the power of \({1/k}\): \[\lim_{{k\to\infty}} |a_k|^{\frac{1}{k}} = L\].
If \(L < 1\), the series converges. If \(L > 1\), it diverges. And if \(L = 1\), the test is inconclusive. In our original problem, \(L\) equaled 1, meaning the Root Test did not provide a definitive answer. It's always essential to explore further if the test results in an inconclusive state.
If \(L < 1\), the series converges. If \(L > 1\), it diverges. And if \(L = 1\), the test is inconclusive. In our original problem, \(L\) equaled 1, meaning the Root Test did not provide a definitive answer. It's always essential to explore further if the test results in an inconclusive state.
Ratio Test
The Ratio Test is another method that helps us investigate the convergence of series. Here, the idea is to examine the behavior of the ratio of successive terms in a series. You find \({\lim_{{k\to\infty}} \frac{|a_{k+1}|}{|a_k|} = L}\).
If \(L < 1\), the series converges absolutely, while if \(L > 1\), it diverges. When \(L = 1\), much like the Root Test, it is inconclusive.
If \(L < 1\), the series converges absolutely, while if \(L > 1\), it diverges. When \(L = 1\), much like the Root Test, it is inconclusive.
- Apply it when Root Test doesn't give results.
- Aids in understanding series with factorials or exponential forms.
Divergent Series
A divergent series is one where the sum of its terms does not settle into a fixed finite number. In simpler terms, as you add more and more terms, the sum grows without bound or oscillates indefinitely.
This can occur when the terms of a series do not tend to zero as you go farther and farther to infinity. Even well-known limits like \( \left(1+\frac{1}{k}\right)^{k} \), which approaches the number \(e\), lead to divergent series since they do not decrease to zero. Recognizing a divergent series can help you understand whether any sum might be fruitless to seek.
This can occur when the terms of a series do not tend to zero as you go farther and farther to infinity. Even well-known limits like \( \left(1+\frac{1}{k}\right)^{k} \), which approaches the number \(e\), lead to divergent series since they do not decrease to zero. Recognizing a divergent series can help you understand whether any sum might be fruitless to seek.
Limit of a Sequence
The limit of a sequence is an important concept that aids in evaluating series. A series requires the limit of its terms, as the index grows, to be zero for convergence.
In the highlighted problem, evaluating \({\lim_{k\to\infty} \left(1+\frac{1}{k}\right)^{k}}\) leads to the famously irrational number \(e\), which is clearly not zero.
In the highlighted problem, evaluating \({\lim_{k\to\infty} \left(1+\frac{1}{k}\right)^{k}}\) leads to the famously irrational number \(e\), which is clearly not zero.
- When a series’ term approaches a non-zero limit, the series diverges.
- Even interesting limits like \(e\), approximately 2.7, still cause divergence in contexts like this.
Other exercises in this chapter
Problem 39
Determine whether the series converges or diverges. In this set of problems knowledge of all the convergence tests from the chapter is assumed. \(\sum_{k=2}^{\i
View solution Problem 39
The hyperbolic functions, hyperbolic cosine, abbreviated cosh, and hyperbolic sine, abbreviated sinh, are defined as follows. $$\cosh x=\frac{e^{x}+e^{-x}}{2} \
View solution Problem 41
Determine whether the series converges or diverges. In this set of problems knowledge of all the convergence tests from the chapter is assumed. \(\sum_{k=1}^{\i
View solution Problem 42
For what values of \(n, n\) a positive integer, does \(\sum_{k=1}^{\infty} \frac{k^{n}}{k !}\) converge?
View solution