Problem 40
Question
Convert the point given in rectangular cocrdinates to cylindrical coondinates. $$ (2 \sqrt{3}, 2,17) $$
Step-by-Step Solution
Verified Answer
The cylindrical coordinates are \((4, \frac{\pi}{6}, 17)\).
1Step 1: Identify Rectangular Coordinates
The given rectangular coordinates are \((x,y,z) = (2\sqrt{3}, 2, 17)\). We will convert these to cylindrical coordinates \((r, \theta, z)\).
2Step 2: Find Radius r
Calculate the radius \(r\) using the formula \(r = \sqrt{x^2 + y^2}\). Substitute the given values: \(r = \sqrt{(2\sqrt{3})^2 + 2^2} = \sqrt{12 + 4} = \sqrt{16} = 4\).
3Step 3: Determine Angle θ
Calculate the angle \(\theta\) using \(\theta = \tan^{-1}(\frac{y}{x})\). For \((x,y)=(2\sqrt{3},2)\), find \(\theta = \tan^{-1}(\frac{2}{2\sqrt{3}}) = \tan^{-1}(\frac{1}{\sqrt{3}}) = \frac{\pi}{6}\) radians.
4Step 4: Use Given z Coordinate
In cylindrical coordinates, the \(z\) value remains the same as in rectangular coordinates. Thus, \(z = 17\).
5Step 5: Compile Cylindrical Coordinates
Now that we have \(r = 4\), \(\theta = \frac{\pi}{6}\), and \(z = 17\), the cylindrical coordinates are \((4, \frac{\pi}{6}, 17)\).
Key Concepts
Rectangular to Cylindrical ConversionCoordinate SystemsTrigonometry in Coordinate Conversion
Rectangular to Cylindrical Conversion
Understanding how to convert from rectangular (also known as Cartesian) to cylindrical coordinates is an essential skill when dealing with 3D space in mathematics and physics. Rectangular coordinates are expressed as
- \((x, y, z)\)
- \((r, \theta, z)\)
- \(r\) is the radial distance from the z-axis,
- \(\theta\) (theta) is the angle in the xy-plane measured from the positive x-axis,
- \(z\) remains the same as it is the height in both systems.
- \( r = \sqrt{x^2 + y^2} \)
- \( \theta = \tan^{-1}(\frac{y}{x}) \)
Coordinate Systems
Coordinate systems are frameworks that enable us to specify points in space in a clear and mathematical way. In 3D space, some of the most common coordinate systems include
- rectangular coordinates,
- cylindrical coordinates,
- and spherical coordinates.
- Rectangular coordinates are ideal for problems involving straight lines or when analyzing planar surfaces.
- Cylindrical coordinates are extremely useful in scenarios involving circular or symmetrical features, like tubes or cylindrical objects.
- Spherical coordinates are beneficial when dealing with objects that have a circular symmetry, like spheres.
Trigonometry in Coordinate Conversion
Trigonometry plays a key role in converting between different coordinate systems, especially when moving from rectangular to cylindrical coordinates. The angle \(\theta\) in cylindrical coordinates, found using trigonometric functions, determines the point's direction in the xy-plane.
When converting coordinates, use the tangent function to find \(\theta\) because it relates the y and x values of a point. The formula
Using trigonometry, especially inverse trigonometric functions for angles, ensures precision in conversion steps. This validates the calculated cylindrical coordinates by making sure that any angle-specific calculations are accurate and align correctly with the expected geometrical representation. Learning how to seamlessly use trigonometry for these conversions boosts your ability to tackle a wide array of mathematical and physical challenges.
When converting coordinates, use the tangent function to find \(\theta\) because it relates the y and x values of a point. The formula
- \( \theta = \tan^{-1}(\frac{y}{x}) \)
Using trigonometry, especially inverse trigonometric functions for angles, ensures precision in conversion steps. This validates the calculated cylindrical coordinates by making sure that any angle-specific calculations are accurate and align correctly with the expected geometrical representation. Learning how to seamlessly use trigonometry for these conversions boosts your ability to tackle a wide array of mathematical and physical challenges.
Other exercises in this chapter
Problem 40
In Problems, find a vector function \(\mathbf{r}\) that satisfies the indicated conditions. $$ \begin{aligned} &\mathbf{r}^{\prime \prime}(t)=\sec ^{2} t \mathb
View solution Problem 40
Use the Chain Rule to find the indicated partial derivatives. $$ z=u^{2} \cos 4 v ; u=x^{2} y^{3}, v=x^{3}+y^{3} ; \frac{\partial z}{\partial x}, \frac{\partial
View solution Problem 40
If \(\rho(x, y)\) is the density of a wire (mass per unit length), then \(m=\int_{C} \rho(x, y) d s\) is the mass of the wire. Find the mass of a wire having th
View solution Problem 40
Find a vector function \(\mathbf{r}\) that satisfies the indicated conditions. $$ \begin{aligned} &\mathbf{r}^{\prime \prime}(t)=\sec ^{2} t \mathbf{i}+\cos t \
View solution