Problem 40
Question
Calculate The pH of a tomato is approximately \(4.50 .\) What are \(\left[H^{+}\right]\) and \(\left[0 \mathrm{H}^{-}\right]\) in a tomato?
Step-by-Step Solution
Verified Answer
[H^{+}]=3.16\times 10^{-5} M; [OH^{-}]=3.16\times 10^{-10} M.
1Step 1: Understand pH Definition
The pH of a solution is a measure of how acidic or basic it is. It is determined by the concentration of hydrogen ions (
H^{+}
). The pH scale ranges from 0 to 14. A pH of 7 is neutral, below 7 is acidic, and above 7 is basic.
2Step 2: Find H^{+} Concentration
The formula to find the hydrogen ion concentration from pH is: \[ \left[H^{+}\right] = 10^{-pH} \] In this case, the pH of the tomato is given as 4.50, so: \[ \left[H^{+}\right] = 10^{-4.50} \] Calculate this value to find the resulting concentration of hydrogen ions.
3Step 3: Calculate H^{+} Concentration
Compute 10^{-4.50} using a calculator to find the concentration of hydrogen ions: \[ \left[H^{+}\right] = 3.16 \times 10^{-5} \text{ M} \] This indicates the molarity (M) which is moles per liter of H^{+} ions in the tomato.
4Step 4: Use Water Ion Product
The ion product of water at 25°C (K_w) is: \[ K_w = \left[H^{+}\right] \times \left[OH^{-}\right] = 1.0 \times 10^{-14} \] Use this relationship to determine the OH^{-} concentration.
5Step 5: Calculate OH^{-} Concentration
Rearrange the water ion product to solve for OH^{-} concentration: \[ \left[OH^{-}\right] = \frac{K_w}{\left[H^{+}\right]} = \frac{1.0 \times 10^{-14}}{3.16 \times 10^{-5}} \] Perform the division to find OH^{-} concentration.
6Step 6: Final Calculation of OH^{-}
Calculate the value obtained in the previous step: \[ \left[OH^{-}\right] \approx 3.16 \times 10^{-10} \text{ M} \] This result is the molarity of hydroxide ions in the tomato.
Key Concepts
Acid-Base ChemistryHydrogen Ion ConcentrationWater Ion ProductHydroxide Ion Concentration
Acid-Base Chemistry
Acid-base chemistry is a fundamental area of chemistry that focuses on the properties of acids and bases, and the reactions between them. In simple terms, acids are substances that donate hydrogen ions (\(H^{+}\)) when dissolved in water, while bases accept hydrogen ions. Understanding this concept helps us explain things like why a lemon tastes sour or why soap is slippery.
The pH scale is an easy way to measure how acidic or basic a solution is.
The pH scale is an easy way to measure how acidic or basic a solution is.
- If a substance has a pH less than 7, it is considered acidic.
- A pH of exactly 7 is neutral, like pure water.
- Substances with a pH greater than 7 are basic or alkaline.
Hydrogen Ion Concentration
The concentration of hydrogen ions in a solution is crucial in determining its pH.
For example, with the tomato's pH of 4.50, the hydrogen ion concentration can be calculated as follows:
To find the hydrogen ion concentration (\([H^{+}]\)) from pH, you use the formula: \([H^{+}] = 10^{-pH}\).
For example, with the tomato's pH of 4.50, the hydrogen ion concentration can be calculated as follows:
- Substitute 4.50 into the formula: \([H^{+}] = 10^{-4.50}\).
- Use a calculator to find \([H^{+}] = 3.16 \times 10^{-5} \text{ M}\), indicating the amount of hydrogen ions per liter.
Water Ion Product
The concept of the water ion product, \(K_w\), is essential to understanding the relationship between \(H^{+}\) and \(OH^{-}\) concentrations. At 25°C, \(K_w\) is always \(1.0 \times 10^{-14}\).It is expressed by the formula:
- \(K_w = [H^{+}] \times [OH^{-}]\)
Hydroxide Ion Concentration
To determine the concentration of hydroxide ions (\(OH^{-}\)), you rearrange the ion product of water formula:
- \([OH^{-}] = \frac{K_w}{[H^{+}]}\)
Other exercises in this chapter
Problem 37
Explain the significance of \(K_{w}\) in aqueous solutions.
View solution Problem 38
Explain, using Le Chatelier's principle, what happens to the \([\mathrm{H}+]\) of a 0.10 M solution of acetic acid when a drop of NaOH solution is added.
View solution Problem 42
Calculate the \(\mathrm{pH}\) of the following solutions. \begin{equation} \begin{array}{ll}{\text { a. } 1.0 M \mathrm{Hl}} & {\text { c. } 1.0 M \mathrm{KOH}}
View solution Problem 44
What is the molarity of a nitric acid solution if 43.33 \(\mathrm{mL}\) of 0.1000\(M\) \(\mathrm{KOH}\) solution is needed to neutralize 20.00 \(\mathrm{mL}\) o
View solution