Problem 40
Question
\(\begin{aligned} y=f(x) &=\cos ^{2} x+\sin ^{4} x \\ &=\cos ^{2} x+\sin ^{2} x\left(1-\cos ^{2} x\right) \\ &=\cos ^{2} x+\sin ^{2} x-\sin ^{2} x \cos ^{2} x \\ &=1-\sin ^{2} x \cos ^{2} x \\ &=1-\frac{1}{4} \sin ^{2} 2 x \\\ \therefore \quad & \frac{3}{4} \leq f(x) \leq 1 \\ \therefore \quad f(x) & \in[3 / 4,1] \end{aligned}\)
Step-by-Step Solution
Verified Answer
The range of \( f(x) \) is \([\frac{3}{4}, 1]\).
1Step 1: Simplify Trigonometric Expression
Given the expression \( y = \cos^2 x + \sin^4 x \), first, we'll rewrite \( \sin^4 x \) as \( \sin^2 x (\sin^2 x) \). Substitute \( \sin^2 x = 1 - \cos^2 x \), resulting in \( y = \cos^2 x + \sin^2 x (1 - \cos^2 x) \).
2Step 2: Distribute and Combine Terms
Simplify the expression from step 1: \( y = \cos^2 x + \sin^2 x - \sin^2 x \cos^2 x \). Combine terms to yield \( y = 1 - \sin^2 x \cos^2 x \).
3Step 3: Use Double Angle Identity
Recall and apply the double angle identity \( \sin 2x = 2 \sin x \cos x \). Hence, \( \sin^2 2x = 4 \sin^2 x \cos^2 x \). Substitute in the expression to get \( y = 1 - \frac{1}{4} \sin^2 2x \).
4Step 4: Determine Range of Function
Since \( \sin^2 2x \) ranges between 0 and 1 for all \( x \), \( \frac{1}{4}\sin^2 2x \) ranges between 0 and \( \frac{1}{4} \). This results in the range of \( y = 1 - \frac{1}{4}\sin^2 2x \) being \( \frac{3}{4} \leq y \leq 1 \).
5Step 5: Conclude the Range of \( f(x) \)
From step 4, we determine that the range of \( f(x) \) is \([\frac{3}{4}, 1]\).
Key Concepts
Function RangeDouble Angle IdentityTrigonometric Simplification
Function Range
The function range is a crucial concept in mathematics that tells us the possible output values a function can produce. For any function, the range is the set of y-values that we can obtain by plugging all possible x-values from the domain into the function. For the function \( f(x) = \cos^2 x + \sin^4 x \), we carefully analyze and transform it to find its range.
This function can be rewritten using identities we explore in the subsequent sections. As we simplify to \( y = 1 - \frac{1}{4} \sin^2 2x \), we need to understand the behavior of \( \sin^2 2x \).
This function can be rewritten using identities we explore in the subsequent sections. As we simplify to \( y = 1 - \frac{1}{4} \sin^2 2x \), we need to understand the behavior of \( \sin^2 2x \).
- The expression \( \sin^2 2x \) has the possible value range \([0, 1]\).
- Thus, \( \frac{1}{4} \sin^2 2x \) ranges between \(0\) and \(\frac{1}{4}\).
- This alters our function to have an output range of \( [\frac{3}{4}, 1] \), as \( y = 1 - \) any value from \([0, \frac{1}{4}]\).
Double Angle Identity
The double angle identity is one of the fundamental identities in trigonometry and it greatly simplifies certain trigonometric expressions. The identity for sine is \( \sin 2x = 2 \sin x \cos x \). This provides a link between single angle functions and double angles.
For our function \( y = 1 - \sin^2 x \cos^2 x \), the utilization of this identity paves the way for further simplification.
For our function \( y = 1 - \sin^2 x \cos^2 x \), the utilization of this identity paves the way for further simplification.
- Using the identity, \( \sin^2 2x = (2 \sin x \cos x)^2 = 4 \sin^2 x \cos^2 x \).
- By rearranging, we express \( \sin^2 x \cos^2 x \) as \( \frac{1}{4} \sin^2 2x \).
Trigonometric Simplification
Simplifying trigonometric expressions involves using identities and algebra to make expressions more manageable. For \( y = \cos^2 x + \sin^4 x \), the goal is to rewrite it in simpler or more revealing forms. This often utilizes identities like \( \sin^2 x = 1 - \cos^2 x \) and products like \( \sin^2 x \cos^2 x \).
Breaking down our function step by step:
Breaking down our function step by step:
- Start with rewriting \( \sin^4 x \) as \( \sin^2 x (1 - \cos^2 x) \), making it easier to combine like terms.
- Next, distribute and combine: \( y = \cos^2 x + \sin^2 x - \sin^2 x \cos^2 x \).
- This transformation leads to \( y = 1 - \sin^2 x \cos^2 x \).
Other exercises in this chapter
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