Problem 40
Question
Among the following which one does not act as an intermediate in Hoffmann rearrangement? (a) RNCO (b) \(\mathrm{RCO} \mathrm{O}\) (c) \(" \mathrm{R} \mathrm{CONHBr}\) (d) \(\mathrm{RNC}\)
Step-by-Step Solution
Verified Answer
(d) RNC does not act as an intermediate in Hoffmann rearrangement.
1Step 1: Understanding Hoffmann Rearrangement
Hoffmann rearrangement is a reaction where an amide is converted to an amine with the loss of one carbon. It typically involves the formation of isocyanate as an intermediate.
2Step 2: Identifying Possible Intermediates
In Hoffmann rearrangement, the intermediates usually include RNCO (isocyanate), but not RCOO- or RNC. The molecule forms from RCONH2 by reacting with bromine and base to form RNCO.
3Step 3: Finding the Odd One Out
By examining the options, RNCO is a known intermediate, RCONHBr can be an intermediate stage, and RCOO- is not directly involved, nor is RNC (isocyanide) a part of Hoffmann rearrangement.
4Step 4: Conclusion
RNC is the compound that does not act as an intermediate in Hoffmann rearrangement because it is not formed or needed during the rearrangement process.
Key Concepts
Reaction IntermediatesIsocyanate FormationAmide to Amine Conversion
Reaction Intermediates
In the Hoffmann rearrangement, reaction intermediates play a crucial role in the transformation process from amide to amine. Essentially, intermediates are temporary structures formed during the reaction steps that lead to the final product.
As these reactions do not occur in a single step, recognizing these intermediates helps in understanding the entire reaction pathway.
Within the Hoffmann rearrangement, the most prominent intermediate is the isocyanate structure (RNCO).
As these reactions do not occur in a single step, recognizing these intermediates helps in understanding the entire reaction pathway.
Within the Hoffmann rearrangement, the most prominent intermediate is the isocyanate structure (RNCO).
- Intermediates act as a bridge between reactants and products.
- The identification of intermediates helps predict reaction mechanisms.
Isocyanate Formation
Isocyanate formation is a pivotal part of the Hoffmann rearrangement. It begins with the amide reacting with bromine and a base, forming the needed intermediates, and eventually leading to isocyanate.
The key step is the reaction between the amide (RCONH2) and bromine, which halogenates the nitrogen, followed by rearrangement under the influence of the base, yielding the isocyanate (RNCO).
The key step is the reaction between the amide (RCONH2) and bromine, which halogenates the nitrogen, followed by rearrangement under the influence of the base, yielding the isocyanate (RNCO).
- This process includes nitrogen atom migration, crucial for the reaction.
- RNCO is a significant intermediate that then proceeds to further transformation.
Amide to Amine Conversion
The ultimate goal of the Hoffmann rearrangement is to convert an amide into an amine, reducing the carbon chain by one carbon atom. This conversion is achieved through the rearrangement steps involving isocyanate intermediates.
Upon forming the isocyanate, further reaction typically involves hydrolysis or an analogous step, adding water to break down the isocyanate into an amine.
Upon forming the isocyanate, further reaction typically involves hydrolysis or an analogous step, adding water to break down the isocyanate into an amine.
- The carbonyl group in the amide is removed, leading to the formation of an amine.
- The newly formed amine often possesses different physical and chemical properties.
Other exercises in this chapter
Problem 38
When a mixture of secondary amines is heated with diethyl oxalate, it forms (a) solid oxamic ester (b) liquid oxamic ester (c) form of oxamic ester (d) gaseous
View solution Problem 39
Which of the following is formed when ethyl carbonate reacts with ammonia? (a) urea (b) urea oxalate (c) ethyl cyanate (d) ethyl nitrate
View solution Problem 41
Pyridine is less basic than triethylamine because (a) pyridine has aromatic character (b) nitrogen in pyridine is sp \(^{2}\) hybridized (c) pyridine is a cycli
View solution Problem 42
KCN react readily to form a cyanide with (a) chlorobenzene (b) ethyl alcohol (c) ethyl bromide (d) bromobenzene
View solution