Problem 40
Question
a. Dertive a formula for \(\cos 3 \theta\) in terms of \(\sin \theta\) and \(\cos \theta\) using Euler's formula. b. Derive the formula \(\cos 3 \theta=4 \cos ^{3} \theta-3 \cos \theta\) from part (a) and the identity \(\sin ^{2} \theta+\cos ^{2} \theta=1\). (We will have use for this identity in Section 32.)
Step-by-Step Solution
Verified Answer
The formula is \(\cos 3\theta = 4\cos^3\theta - 3\cos\theta\).
1Step 1: Represent \\(\cos 3\theta\\) using Euler's Formula
Start with Euler's formula: \(e^{i\theta} = \cos \theta + i\sin \theta\). Therefore, \(e^{i3\theta} = (e^{i\theta})^3.\)Expanding the right side using the cube identity gives: \[e^{i3\theta} = (\cos \theta + i \sin \theta)^3.\]Use binomial expansion: \[= \cos^3 \theta + 3i \cos^2 \theta \sin \theta - 3 \cos \theta \sin^2 \theta - i \sin^3 \theta.\]
2Step 2: Simplify to Real and Imaginary Parts
Separate the real and imaginary parts of the expression to isolate \(\cos 3\theta\) and \(\sin 3\theta\):\[\cos 3\theta + i \sin 3\theta = \cos^3 \theta - 3 \cos \theta \sin^2 \theta + i(3 \cos^2 \theta \sin \theta - \sin^3 \theta).\]Thus, the real part equates to \(\cos 3\theta\):\[\cos 3\theta = \cos^3 \theta - 3 \cos \theta \sin^2 \theta.\]
3Step 3: Use \\(\sin^2 \theta + \cos^2 \theta = 1\\) to Simplify
Use the identity \(\sin^2 \theta + \cos^2 \theta = 1\) to replace \(\sin^2 \theta\) with \(1 - \cos^2 \theta\):\[\cos 3\theta = \cos^3 \theta - 3 \cos \theta (1 - \cos^2 \theta).\]
4Step 4: Distribute and Simplify Further
Distribute \(-3\cos\theta\):\[\cos 3\theta = \cos^3 \theta - 3 \cos \theta + 3 \cos^3 \theta\]Combine like terms:\[\cos 3\theta = 4\cos^3 \theta - 3\cos \theta.\]
5Step 5: Final Step: Verify the Derived Expression with Known Formula
Verify that this expression matches the standard identity for triple angle:\[\cos 3\theta = 4 \cos^3 \theta - 3 \cos \theta.\]This confirms the derivation using Euler's Formula and trigonometric identities is correct.
Key Concepts
Trigonometric IdentitiesTriple Angle FormulaBinomial ExpansionReal and Imaginary Parts Separation
Trigonometric Identities
In mathematics, trigonometric identities are equations involving trigonometric functions that are true for all value inputs to those functions. The most fundamental trigonometric identities are those that relate the sine and cosine of any angle \( \theta \). A classic and deeply important one is the Pythagorean identity:
In the context of deriving \( \cos 3\theta \), this identity helps to substitute and eliminate \( \sin^2 \theta \), turning it into something more manageable like \( 1 - \cos^2 \theta \). Doing so simplifies the calculation and provides a clearer path to the solution.
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
In the context of deriving \( \cos 3\theta \), this identity helps to substitute and eliminate \( \sin^2 \theta \), turning it into something more manageable like \( 1 - \cos^2 \theta \). Doing so simplifies the calculation and provides a clearer path to the solution.
Triple Angle Formula
The triple angle formulas are specific cases of angle identities used in trigonometry, especially to express a trigonometric function of an angle in terms of functions of multiple angles. One such formula for cosine is:
In exercises like deriving \( \cos 3\theta \) in terms of \( \cos \theta \) and \( \sin \theta \), the triple angle formula can reaffirm consistency between calculated expressions and known trigonometric identities.
- \( \cos 3\theta = 4 \cos^3 \theta - 3 \cos \theta \)
In exercises like deriving \( \cos 3\theta \) in terms of \( \cos \theta \) and \( \sin \theta \), the triple angle formula can reaffirm consistency between calculated expressions and known trigonometric identities.
Binomial Expansion
The binomial expansion is a formula used to expand expressions that are raised to a power, in the format \( (x + y)^n \). In relation to Euler's formula and solving trigonometric expressions:
This allows expression of complex angles in terms of easier-to-manage base trigonometric functions, facilitating further simplification using known identities. Binomial expansion is particularly potent for expressions involving powers of sums in algebra and complex numbers.
- When \((\cos \theta + i\sin \theta)^3\) expands, each term follows from the binomial theorem, leading to terms like \( \cos^3 \theta + 3i \cos^2 \theta \sin \theta - 3 \cos \theta \sin^2 \theta - i \sin^3 \theta \).
This allows expression of complex angles in terms of easier-to-manage base trigonometric functions, facilitating further simplification using known identities. Binomial expansion is particularly potent for expressions involving powers of sums in algebra and complex numbers.
Real and Imaginary Parts Separation
When dealing with Euler's formula and complex expressions, separating the real and imaginary parts is a key step to finding solutions. This technique separates the terms into components that contain \(i\) (imaginary parts) and those that don't (real parts).
By isolating these parts, one can apply identities and resolve terms separately, ensuring accuracy in outcomes when handling complex trigonometric equations.
- For instance, from \(e^{i3\theta} = \cos^3 \theta - 3 \cos \theta \sin^2 \theta + i(3 \cos^2 \theta \sin \theta - \sin^3 \theta)\), the real part, \( \cos 3\theta \), is distinctly separated from the imaginary part, \( \sin 3\theta \).
By isolating these parts, one can apply identities and resolve terms separately, ensuring accuracy in outcomes when handling complex trigonometric equations.
Other exercises in this chapter
Problem 38
Derive the formulas $$ \sin (a+b)=\sin a \cos b+\cos a \sin b $$ and $$ \cos (a+b)=\cos a \cos b-\sin a \sin b $$ by using Euler's formula and computing \(e^{i
View solution Problem 38
Derive the fornulas $$ \sin (a+b)=\sin a \cos b+\cos a \sin b $$ and $$ \cos (a+b)=\cos a \cos b-\sin a \sin b $$ by using Euler's formula and computing \(e^{j
View solution Problem 40
a. Dertve a formula for \(\cos 3 \theta\) in terms of \(\sin \theta\) and \(\cos \theta\) using Euler's formula. b. Derive the formula \(\cos 3 \theta=4 \cos ^{
View solution Problem 37
Why can there be no isomorphism of \(U_{6}\) with \(Z_{6}\) in which \(\zeta=e^{i(a / 3)}\) corresponds to \(4 ?\)
View solution