Problem 40
Question
A company has 500 employees among whom 200 are females, 15 are high-level executives, and 7 of the high-level executives are females. If one of the 500 employees is chosen at random, find the probability that the person chosen is female or is a high-level executive. \(0.416\)
Step-by-Step Solution
Verified Answer
The probability is 0.416.
1Step 1: Define the Sets
We define two sets: \( F \), which represents the females, and \( E \), which represents the high-level executives. So, \(|F| = 200\) and \(|E| = 15\).
2Step 2: Identify the Intersection
Identify the employees who are both female and high-level executives. This is the intersection of \( F \) and \( E \), given as \(|F \cap E| = 7\).
3Step 3: Use the Union Formula
Use the formula for the probability of the union of two events: \( P(F \cup E) = P(F) + P(E) - P(F \cap E) \).
4Step 4: Calculate Each Probability
Calculate \( P(F) = \frac{|F|}{500} = \frac{200}{500} = 0.4 \), \( P(E) = \frac{|E|}{500} = \frac{15}{500} = 0.03 \), and \( P(F \cap E) = \frac{|F \cap E|}{500} = \frac{7}{500} = 0.014 \).
5Step 5: Substitute and Solve
Substitute these values into the union formula: \( P(F \cup E) = 0.4 + 0.03 - 0.014 = 0.416 \).
Key Concepts
Union FormulaIntersection of SetsProbability of Events
Union Formula
The Union Formula is a powerful tool in probability that helps us find the probability of either one event happening, or another, or both. In simpler terms, it tells us the likelihood of one event occurring or another.
The formula is expressed as:
Here's how it can be applied:
The formula is expressed as:
- \( P(F \cup E) = P(F) + P(E) - P(F \cap E) \)
Here's how it can be applied:
- If we want to know the probability that an employee is either a female or a high-level executive, or both, we use this formula. We calculate the probability for each event separately and for their combination, then plug these numbers into the union formula.
Intersection of Sets
The Intersection of Sets is a fundamental concept in probability and set theory. It refers to the elements that are common to two or more sets.
If we think of sets as groups of items, the intersection is the group that belongs to more than one collection at the same time.
The intersection of two events \( F \) and \( E \) is noted as \( F \cap E \), which includes all elements present in both \( F \) and \( E \).
This intersection value ensures precision in our probability calculations when we apply the Union Formula.
If we think of sets as groups of items, the intersection is the group that belongs to more than one collection at the same time.
The intersection of two events \( F \) and \( E \) is noted as \( F \cap E \), which includes all elements present in both \( F \) and \( E \).
- In our exercise, the intersection \( |F \cap E| \) consists of the number of female employees who are also high-level executives. This is crucial because these employees are counted when calculating both standalone probabilities \( P(F) \) and \( P(E) \).
This intersection value ensures precision in our probability calculations when we apply the Union Formula.
Probability of Events
Probability of events is the likelihood or chance that a particular outcome will happen. It’s one of the fundamental concepts needed to solve problems related to uncertainty and randomness.
In terms of sets, when we deal with probability,
In this context, \(|F|\) is the number of females, and \(|E|\) is the number of executives, while the entire sample set \(|S|\) is the total number of employees.
In terms of sets, when we deal with probability,
- We examine subsets, like the set of all females \( F \), or high-level executives \( E \) within a larger set, here, the total employees.
- \( P(E) = \frac{|E|}{|S|} \)
In this context, \(|F|\) is the number of females, and \(|E|\) is the number of executives, while the entire sample set \(|S|\) is the total number of employees.
- This approach allows you to calculate the probability of specific groups, like the probability of randomly picking a female employee, a high-level executive, or a combination of both.
Other exercises in this chapter
Problem 40
Expand each binomial and simplify.\((1-\sqrt{2})^{5}\)
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How many five-element subsets containing \(A\) and \(B\) can be formed from the set \(\\{A, B, C, D, E, F, G, H\\}\) ? 20
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Suppose that a box of ten items from a manufacturing company is known to contain two defective and eight nondefective items. A sample of three items is selected
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Expand each binomial and simplify.\((-a+b)^{3}\)
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