Problem 40
Question
\(23-44=\) Find the exact value of the expression, if it is defined. \(\cos \left(\sin ^{-1} 0\right)\)
Step-by-Step Solution
Verified Answer
The exact value is 1.
1Step 1: Understand the Inner Function
The expression inside the cosine function is \( \sin^{-1}(0) \). The inverse sine function, denoted as \( \sin^{-1}(x) \) or \( \arcsin(x) \), gives us the angle \( \theta \) whose sine value is \( x \).
2Step 2: Solve the Inner Function
Find the angle \( \theta \) such that \( \sin(\theta) = 0 \). The basic angle that satisfies this equation is \( \theta = 0 \) because \( \sin(0) = 0 \). Thus, \( \sin^{-1}(0) = 0 \).
3Step 3: Compute the Outer Function
Now, substitute \( \theta = 0 \) into the cosine function, which gives us \( \cos(0) \).
4Step 4: Evaluate the Cosine Function
Use the known value \( \cos(0) = 1 \). Hence, \( \cos(\sin^{-1}(0)) = 1 \).
Key Concepts
Inverse Trigonometric FunctionsCosine FunctionSine Function
Inverse Trigonometric Functions
Inverse trigonometric functions are a way to find the angle when you know the value of a trigonometric function. They are the 'reverse' functions of the standard trigonometric functions like sine, cosine, and tangent.
When we use the inverse sine function, denoted as \( \sin^{-1}(x) \) or \( \arcsin(x) \), we look for an angle \( \theta \) such that \( \sin(\theta) = x \). The range of \( \sin^{-1}(x) \) is between \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\), meaning it only gives angles within this interval.
When we use the inverse sine function, denoted as \( \sin^{-1}(x) \) or \( \arcsin(x) \), we look for an angle \( \theta \) such that \( \sin(\theta) = x \). The range of \( \sin^{-1}(x) \) is between \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\), meaning it only gives angles within this interval.
- For example: \( \sin^{-1}(0) = 0 \) because \( \sin(0) = 0 \).
- In this problem, solving the inner expression \( \sin^{-1}(0) \) gives \( \theta = 0 \).
Cosine Function
The cosine function is one of the fundamental trigonometric functions, often used in mathematics to measure angles and lengths in right triangles and unit circles. It is commonly denoted by \( \cos(x) \).
The cosine of an angle is the x-coordinate of a point on the unit circle. For an angle \( \theta \), the cosine value represents the horizontal distance from the origin to the circle's perimeter.
The cosine of an angle is the x-coordinate of a point on the unit circle. For an angle \( \theta \), the cosine value represents the horizontal distance from the origin to the circle's perimeter.
- Especially in this exercise, after determining \( \theta = 0 \) from \( \sin^{-1}(0) \), we use \( \cos(0) \) as the final step.
- We know \( \cos(0) = 1 \).
Sine Function
The sine function is another essential trigonometric function, represented as \( \sin(x) \). Just like cosine, it plays a crucial role in the study of triangles and circles.
For a given angle \( \theta \), the sine function equals the y-coordinate on the unit circle. It gives the vertical distance from the origin to the point on the circle.
For a given angle \( \theta \), the sine function equals the y-coordinate on the unit circle. It gives the vertical distance from the origin to the point on the circle.
- In this problem, \( \sin(\theta) \) was set to 0, meaning we found the angle for \( \sin^{-1}(0) \).
- The basic angle where \( \sin(\theta) = 0 \) is \( \theta = 0 \), confirming that \( \sin^{-1}(0) = 0 \).
Other exercises in this chapter
Problem 39
\(29-42\) . Find the amplitude, period, and phase shift of the function, and graph one complete period. $$ y=3 \cos \pi\left(x+\frac{1}{2}\right) $$
View solution Problem 39
Find the period and graph the function. $$ y=\tan 2\left(x+\frac{\pi}{2}\right) $$
View solution Problem 40
\(29-42\) . Find the amplitude, period, and phase shift of the function, and graph one complete period. $$ y=3+2 \sin 3(x+1) $$
View solution Problem 40
Find the period and graph the function. $$ y=\csc 2\left(x+\frac{\pi}{2}\right) $$
View solution