Problem 4
Question
Which of the points \((2,1),(3,0),(4,-1),\) or \((1 / 2,9 / 2)\) is farthest from the origin? Which is nearest to the origin? Which is farthest from (-5,6)\(?\) Which is nearest to (10,7)\(?\)
Step-by-Step Solution
Verified Answer
(4,-1) is farthest from the origin and (-5,6); nearest to the origin is (3,0); nearest to (10,7) are (2,1) and (4,-1).
1Step 1: Understand the Distance Formula
The distance of a point \((x, y)\) from another point \((x_0, y_0)\) is given by the formula: \[ d = \sqrt{(x - x_0)^2 + (y - y_0)^2} \] We will use this formula to find the distances of each given point separately from the origin \((0,0)\), from \((-5,6)\), and from \((10,7)\).
2Step 2: Calculate Distance from the Origin
For each point, calculate the distance to the origin using \[ d = \sqrt{x^2 + y^2} \]: - \((2, 1): d = \sqrt{2^2 + 1^2} = \sqrt{5}\) - \((3, 0): d = \sqrt{3^2 + 0^2} = 3\) - \((4, -1): d = \sqrt{4^2 + (-1)^2} = \sqrt{17}\) - \(\left(\frac{1}{2}, \frac{9}{2}\right): d = \sqrt{\left(\frac{1}{2}\right)^2 + \left(\frac{9}{2}\right)^2} = \frac{\sqrt{82}}{2}\)
3Step 3: Determine Farthest from the Origin
Compare the calculated distances: \(\sqrt{5}\), \(3\), \(\sqrt{17}\), and \(\frac{\sqrt{82}}{2}\). Since \(\sqrt{17} \approx 4.123\), it's the largest. Thus, \((4, -1)\) is the farthest from the origin.
4Step 4: Determine Nearest to the Origin
Compare again the calculated distances: - Smallest value is \(3\), which corresponds to the point \((3, 0)\). Thus, \((3, 0)\) is the nearest to the origin.
5Step 5: Calculate Distance from (-5,6)
Calculate using \[ d = \sqrt{(x + 5)^2 + (y - 6)^2} \]: - \((2, 1): d = \sqrt{7^2 + (-5)^2} = \sqrt{74}\) - \((3, 0): d = \sqrt{8^2 + (-6)^2} = 10\) - \((4, -1): d = \sqrt{9^2 + (-7)^2} = \sqrt{130}\) - \(\left(\frac{1}{2}, \frac{9}{2}\right): d = \sqrt{\left(-\frac{9}{2}\right)^2 + \left(\frac{3}{2}\right)^2} = \frac{\sqrt{90}}{2}\)
6Step 6: Determine Farthest from (-5,6)
Compare the calculated distances: - \(\sqrt{130}\) is the largest, which corresponds to \((4, -1)\). Thus, \((4, -1)\) is the farthest from \((-5, 6)\).
7Step 7: Calculate Distance from (10,7)
Calculate using \[ d = \sqrt{(x - 10)^2 + (y - 7)^2} \]: - \((2, 1): d = \sqrt{(-8)^2 + (-6)^2} = 10\) - \((3, 0): d = \sqrt{(-7)^2 + (-7)^2} = \sqrt{98}\) - \((4, -1): d = \sqrt{(-6)^2 + (-8)^2} = 10\) - \(\left(\frac{1}{2}, \frac{9}{2}\right): d = \sqrt{-\frac{19}{2}^2 + -\frac{5}{2}^2} = \frac{\sqrt{410}}{2}\)
8Step 8: Determine Nearest to (10,7)
Compare the calculated distances: - Smallest value is 10, which corresponds to both \((2, 1)\) and \((4, -1)\). Thus, \((2, 1)\) and \((4, -1)\) are both nearest to \((10, 7)\).
Key Concepts
Origin DistanceCoordinate GeometryPoint Comparison
Origin Distance
The distance of a point from the origin in a coordinate plane offers insight into its position relative to the center, which is located at \((0,0)\). To determine this distance for any point \((x, y)\), you apply the distance formula specifically tailored for the origin:
Applying it is manageable — just plug in the respective x and y values and solve.
For instance, if we have the point \((2, 1)\), we substitute and calculate \(\sqrt{2^2 + 1^2} = \sqrt{5}\).
The value represents the length from the origin to that point. In our solution, \((4, -1)\) came out farthest while \((3, 0)\) was closest.
By comparing these distances, we gain a clear picture of each point's proximity to the origin.
- \(d = \sqrt{x^2 + y^2}\)
Applying it is manageable — just plug in the respective x and y values and solve.
For instance, if we have the point \((2, 1)\), we substitute and calculate \(\sqrt{2^2 + 1^2} = \sqrt{5}\).
The value represents the length from the origin to that point. In our solution, \((4, -1)\) came out farthest while \((3, 0)\) was closest.
By comparing these distances, we gain a clear picture of each point's proximity to the origin.
Coordinate Geometry
Coordinate geometry allows for the visualization of geometric principles on a grid using algebra.
It brings to life geometric measurements through plotted points, lines, and figures using sets of numerical coordinates.
This system equips us to solve real-world geometric problems with efficiency. It is especially handy for calculating distances, angles, and slopes within a coordinate plane.
This system equips us to solve real-world geometric problems with efficiency. It is especially handy for calculating distances, angles, and slopes within a coordinate plane.
- The basic principle here deals with plotting points using x (horizontal) and y (vertical) coordinates.
- The Distance Formula is an algebraic approach that translates geometric properties into numerical calculations.
- This methodology enables identification of relationships between points without physical measurement.
Point Comparison
Point comparison is crucial for determining relative positions in coordinate geometry. Here, we compare given points based on their distances from specified points like the origin or certain coordinates such as \((-5,6)\) or \((10,7)\).
This comparison relies on calculated distances using the established formula.
This comparison relies on calculated distances using the established formula.
- From our exercise, comparing points required calculating distances to evaluate which points were nearest or farthest.
- Distance comparisons allow clear conclusions on proximity, informing decisions or validating spatial relationships.
Other exercises in this chapter
Problem 4
State the domain of the function defined by the given expression. $$ \sqrt{2-x^{2}} $$
View solution Problem 4
Sketch the line that passes through point (-2,5) and that rises 7 units for every 2 units of left-to-right motion.
View solution Problem 4
Convert the decimal to a rational fraction. (Ellipses are included in some exercises to indicate repetition.) \(2.222 \ldots\)
View solution Problem 5
Calculate the given expression without using a calculator. \(\sin (\pi / 3) \sin (\pi / 6)\)
View solution