Problem 4
Question
Use a table of integrals with forms involving \(\sqrt{a^{2}-u^{2}}\) to find the indefinite integral. \(\int \frac{\sqrt{64-x^{4}}}{x} d x\)
Step-by-Step Solution
Verified Answer
The indefinite integral of \(\int \frac{\sqrt{64-x^{4}}}{x} dx\) is \(-32 \ln |\frac{x + \sqrt{64-x^{4}}}{x}| + C\).
1Step 1: Identify the form of integral
Identify the given integral \(\int \frac{\sqrt{64-x^{4}}}{x} dx\) as being similar to the form \(\int \frac{\sqrt{a^{2}-u^{2}}}{u} du\). This is done by observing that \(64-x^{4}\) can be rewritten as \(8^{2}-x^{2^{2}}\), which resembles \(a^{2}-u^{2}\), and noting the similarity in their forms.
2Step 2: Make the substitution
To transform the integral into the identified form, make a substitution: let \(u=x^{2}\), therefore \(du = 2x dx\) and \(x = \sqrt{u}\) . We can write our integral as \(\int \frac{\sqrt{64-u^{2}}}{\sqrt{u}} \frac{du}{2}\), which simplifies to \(\frac{1}{2}\int \frac{\sqrt{64-u^{2}}}{\sqrt{u}} du\). Now, the integral matches the identified form, where \(a = 8\) and \(u = x^{2}\).
3Step 3: Apply the integral formula
Applying the standard integral formula for this form \(\int \frac{\sqrt{a^{2}-u^{2}}}{\sqrt{u}} du = -\frac{a^{2}}{2} \ln |\frac{\sqrt{u} + \sqrt{a^{2}- u^{2}}}{\sqrt{u}}|\), substitute \(a = 8\) and \(u = x^{2}\) to obtain \(-8^{2}/2 \ln |\frac{\sqrt{x^{2}} + \sqrt{8^{2}- x^{2^{2}}}}{\sqrt{x^{2}}}\).
4Step 4: Simplify the expression
Simplify the expression to obtain \(-32 \ln |\frac{x + \sqrt{64-x^{4}}}{x}|\).
5Step 5: Write down the indefinite integral
The indefinite integral of \(\int \frac{\sqrt{64-x^{4}}}{x} dx\) is \(-32 \ln |\frac{x + \sqrt{64-x^{4}}}{x}| + C\), where C represents the constant of integration.
Key Concepts
Integration TechniquesTrigonometric SubstitutionIntegral Tables
Integration Techniques
Integration is a crucial tool in calculus, used to find areas, volumes, and other quantities that accumulate. An important aspect of integration is choosing the right technique to solve different types of integrals. Some common integration techniques include:
- Substitution: Replacing a variable with another expression to simplify the integral.
- Partial Fractions: Decomposing complex fractions to simpler ones that are easier to integrate.
- Integration by Parts: A method based on the product rule for derivatives.
- Trigonometric Substitution: Using trigonometric identities to simplify integrals involving square roots.
Trigonometric Substitution
Trigonometric substitution is employed when an integral involves square roots of expressions like \(a^2-u^2\), \(a^2+u^2\) or \(u^2-a^2\). This technique leverages trigonometric identities to simplify the integral. Here's how it works:
- For \(a^2-u^2\), use \(u = a\sin\theta\), transforming the expression under the square root into \(a^2\cos^2\theta\).
- For \(a^2+u^2\), use \(u = a\tan\theta\), simplifying to \(a^2\sec^2\theta\).
- For \(u^2-a^2\), use \(u = a\sec\theta\), resulting in \(a^2\tan^2\theta\).
Integral Tables
Integral tables are reference tools that list common integrals and their solutions. These tables are particularly useful when dealing with complex integrals or when quick solutions are needed. They provide formulas and solutions for:
- Basic integrals like \(\int x^n \, dx\).
- Trigonometric integrals including \(\int \sin x \, dx\) and \(\int \cos x \, dx\).
- Exponential integrals such as \(\int e^x \, dx\).
- Special forms like \(\int \frac{\sqrt{a^2-u^2}}{u} \, du\).
Other exercises in this chapter
Problem 4
Determining Whether an Integral Is Improper In Exercises \(1-8\) , decide whether the integral is improper. Explain your reasoning. $$ \int_{1}^{\infty} \ln \le
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Partial Fraction Decomposition In Exercises \(1-4,\) write the form of the partial fraction decomposition of the rational expression. Do not solve for the const
View solution Problem 4
Trigonometric Substitution In Exercises \(1-4,\) state the trigonometric substitution you would use to find the indefinite integral. Do not integrate. $$ \int x
View solution Problem 4
Finding an Indefinite Integral Involving Sine and cosine In Exercises \(1-12,\) find the indefinite integral. $$ \int \sin ^{3} 3 x d x $$
View solution