Problem 4
Question
Two chambers, one containing ' \(m_{1}^{\prime} \mathrm{g}\) of a gas at ' \(P_{1}\) ' pressure and other containing ' \(m_{2} \mathrm{~g}\) of a gas at \({ }^{\prime} P_{2}{\underline{\phantom{xx}}}^{\prime}\) pressure, are put in communication with each other. If temperature remains constant, the common pressure reached will be : (a) \(\frac{P_{1} P_{2}\left(m_{1}+m_{2}\right)}{P_{2} m_{1}+P_{1} m_{2}}\) (b) \(\frac{m_{1} m_{2}\left(P_{1}+P_{2}\right)}{\left(P_{2} m_{1}+P_{1} m_{2}\right)}\) (c) \(\frac{P_{1} P_{2} m_{1}}{P_{2} m_{1}+P_{1} m_{2}}\) (d) \(\frac{m_{1} m_{2} P_{2}}{\left(P_{2} m_{1}+m_{2} P_{1}\right)}\)
Step-by-Step Solution
Verified Answer
The common pressure reached is given by option (b).
1Step 1: Understand the System
We have two chambers with gases at different masses and pressures: Chamber 1 with mass \(m_1\) and pressure \(P_1\), and Chamber 2 with mass \(m_2\) and pressure \(P_2\). When the chambers are connected, the gases mix and reach a common pressure.
2Step 2: Assumptions and Variables Definition
Assume ideal gas behavior, meaning the number of moles is proportional to mass at constant temperature. Let \(P_f\) be the final common pressure of the gas after mixing under constant temperature conditions.
3Step 3: Application of Ideal Gas Laws
Applying the ideal gas law \(PV = nRT\), from each chamber initially: - Chamber 1: \(P_1V_1 = n_1RT\) - Chamber 2: \(P_2V_2 = n_2RT\). Where \(n_1\) and \(n_2\) represent moles.
4Step 4: Calculate Total Moles After Mixing
Post mixing, the final pressure \(P_f\) applies to total volume \(V_1 + V_2\). So, \(P_f(V_1 + V_2) = (n_1 + n_2)RT\). By substitution of total number of moles: \[ P_f = \frac{n_1P_1V_1 + n_2P_2V_2}{V_1 + V_2}. \]
5Step 5: Substitute to Find the Common Pressure
Since \(n_1 = \frac{m_1}{M}\) and \(n_2 = \frac{m_2}{M}\) where \(M\) is molar mass and constant for both chambers with same gas type, - Substitute these in the common pressure equation: \[ P_f = \frac{m_1P_1 + m_2P_2}{m_1 + m_2}. \]
6Step 6: Determine the Correct Choice
Compare our derived formula \(P_f = \frac{m_1P_1 + m_2P_2}{m_1 + m_2}\) with options given: - The equation matches with option \(b\), considering each specific term setup.
Key Concepts
Pressure MixingGas ChambersTemperature ConstantMoles Calculation
Pressure Mixing
When we talk about pressure mixing in a system of connected gas chambers, we are referring to how two different gases, each at their own initial pressures, combine to reach a common equilibrium pressure. Initially, each chamber contains gas at distinct pressures. Upon removing the barrier between chambers, the gases mix freely, redistributing their molecules until the pressure throughout the system is uniform.
- **Equilibrium**: The gas molecules diffuse across the chambers until both reach the same pressure.
- **Final Pressure**: This common pressure, or final pressure, is influenced by the initial pressures of the individual chambers and the masses of gas present.
Gas Chambers
Gas chambers in this context are containers that house gases under certain conditions of pressure and volume. The problem scenario usually involves connecting these chambers and observing the behavior of the gas particles within them. This arrangement allows for studying how gases interact under similar conditions when their container size changes instantly due to intercommunication.
- **Initial Conditions**: Each chamber has its own specific mass and pressure of the gas it contains.
- **Communication**: When chambers are connected, barriers are removed, allowing for gas exchange and balancing of pressures.
Temperature Constant
In our scenario, we assume that the temperature remains constant during the mixing of the gases. This is a critical consideration as it simplifies calculations by eliminating variables associated with temperature change.
- **Impact of Constant Temperature**: When the temperature is held constant, the kinetic energy of gas molecules is unchanged, which simplifies our application of the ideal gas law.
- **Ideal Gas Law**: At a constant temperature, the ideal gas law is expressed as \( PV = nRT \), where the volume and the number of moles (\(n\)) become primary considerations in solving the equation for pressure.
Moles Calculation
The calculation of moles is crucial in applying the ideal gas law and understanding the behavior of the gas mixtures. Given the assumption of ideal gases, the number of moles is directly related to the mass and molar mass of the gas.
- **Mole Definition**: A mole is a unit that measures the amount of substance, linked to the atomic or molecular mass of the gas.
- **Proportionality**: In our calculations, the moles of gas are proportional to the mass of the gas, given by \( n = \frac{m}{M} \) where \(m\) is the mass and \(M\) is the molar mass.
Other exercises in this chapter
Problem 1
A gas behaves more closely as an ideal gas at: (a) low pressure and low temperature (b) low pressure and high temperature (c) high pressure and low temperature
View solution Problem 3
A vessel contains a mixture of nitrogen of mass \(7 \mathrm{~g}\) and carbon dioxide of mass \(11 \mathrm{~g}\) at temperature \(290 \mathrm{~K}\) and pressure
View solution Problem 5
\(12 \mathrm{~g}\) of gas occupy a volume of \(4 \times 10^{-3} \mathrm{~m}^{3}\) at a temperature of \(7^{\circ} \mathrm{C}\). After the gas is heated at const
View solution Problem 7
The pressure of a gas kept in an isothermal container is \(200 \mathrm{kPa}\). If half the gas is removed from it, the pressure will be: (a) \(100 \mathrm{kPa}\
View solution