Problem 4
Question
Translate the following into algebraic equations. Twice some number is subtracted from 30 and the result is \(50 .\)
Step-by-Step Solution
Verified Answer
The algebraic equation is \(30 - 2x = 50\).
1Step 1: Identify the Unknown
Let's identify the unknown quantity that needs translation into an algebraic expression. In this case, "some number" is the unknown, and we will represent it with a variable, let's say \(x\).
2Step 2: Express "Twice Some Number"
Twice a number can be represented as \(2x\), which means multiplying the unknown by 2.
3Step 3: Formulate the Expression for 'Twice Some Number is Subtracted from 30'
Here we need to subtract \(2x\) from 30. This can be expressed algebraically as \(30 - 2x\).
4Step 4: Formulate the Entire Equation
The problem states that this result (\(30 - 2x\)) equals 50. Therefore, we set up the equation: \(30 - 2x = 50\).
Key Concepts
Variable RepresentationTranslating Word ProblemsSolving Linear Equations
Variable Representation
Variables are essential tools in algebra that help us represent unknown quantities or values. In real-world problems, these variables are often depicted by letters like \(x\), \(y\), or \(z\). Let's consider the statement, "Twice some number." Here, "some number" is unknown, which we can represent using a variable, such as \(x\). This translates our unknown quantity into a mathematical expression.
Choosing a variable carefully can simplify solving algebraic equations, especially in word problems. It provides clarity and helps you keep track of what each variable means.
To represent a variable:
Choosing a variable carefully can simplify solving algebraic equations, especially in word problems. It provides clarity and helps you keep track of what each variable means.
To represent a variable:
- Identify the unknown or the quantity you need to solve for.
- Assign it a letter, usually a lowercase letter, like \(x\).
- Use this variable consistently throughout your calculations or equations.
Translating Word Problems
Translating word problems into algebraic equations may initially seem challenging, but breaking it down step by step can make it manageable. Let’s illustrate this with the example from our exercise.
First, we identify keywords: "twice some number," "subtracted from 30," and "the result is 50." Each of these phrases corresponds to a specific mathematical operation.
Here's how you can translate these phrases:
First, we identify keywords: "twice some number," "subtracted from 30," and "the result is 50." Each of these phrases corresponds to a specific mathematical operation.
Here's how you can translate these phrases:
- "Twice some number": This means multiplying the unknown number by 2, resulting in \(2x\).
- "Subtracted from 30": This directs us to subtract the expression \(2x\) from 30, written as \(30 - 2x\).
- "The result is 50": This tells us that the operation equals 50, leading to the equation \(30 - 2x = 50\).
Solving Linear Equations
Once you've translated the word problem into an algebraic equation, the next step is to solve for the variable. We already formulated the equation as \(30 - 2x = 50\). Solving this involves isolating the variable \(x\) to find its value.
Let's break it down:
Let's break it down:
- Add \(2x\) to both sides of the equation to eliminate the \(x\) term on one side:
- \(30 = 50 + 2x\)
- Next, subtract 30 from both sides to isolate \(2x\):
- \(0 = 20 + 2x\) simplifies to \(-20 = 2x\)
- Finally, divide both sides by 2 to solve for \(x\):
- \(x = -10\)
Other exercises in this chapter
Problem 4
Graph all solutions on a number line and provide the corresponding interval notation. $$ x \leq 0 $$
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Express each ratio in reduced form. 240 miles4 hours
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Is the given value a solution to the linear equation? $$ -2 y=44 ; y=11 $$
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Evaluate. \(b_{2}-4 a c,\) where \(a=5, b=-2,\) and \(c=12\)
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