Problem 4
Question
The ordered software data (see also Table 15.3) are given in the following list. $$ \begin{array}{rrrrrrrrrr} 0 & 0 & 0 & 2 & 4 & 6 & 8 & 9 & 10 & 10 \\ 10 & 12 & 15 & 15 & 16 & 21 & 22 & 24 & 26 & 30 \\ 30 & 31 & 33 & 36 & 44 & 50 & 55 & 58 & 65 & 68 \\ 75 & 77 & 79 & 81 & 88 & 91 & 97 & 100 & 108 & 108 \\ 112 & 113 & 114 & 115 & 120 & 122 & 129 & 134 & 138 & 143 \\ 148 & 160 & 176 & 180 & 193 & 193 & 197 & 227 & 232 & 233 \\ 236 & 242 & 245 & 255 & 261 & 263 & 281 & 290 & 296 & 300 \\ 300 & 325 & 330 & 357 & 365 & 369 & 371 & 379 & 386 & 422 \\ 445 & 446 & 447 & 452 & 457 & 482 & 529 & 529 & 543 & 600 \\ 648 & 670 & 700 & 707 & 724 & 729 & 748 & 790 & 810 & 816 \\ 828 & 843 & 860 & 865 & 868 & 875 & 943 & 948 & 983 & 990 \\ 1011 & 1045 & 1064 & 1071 & 1082 & 1146 & 1160 & 1222 & 1247 & 1351 \\ 1435 & 1461 & 1755 & 1783 & 1800 & 1864 & 1897 & 2323 & 2930 & 3110 \\ 3321 & 4116 & 5485 & 5509 & 6150 & & & & & \end{array} $$ a. Compute the heights on each bin of the histogram with bins \([0,500]\), \((500,1000]\), and so on. b. Compute the value of the empirical distribution function in the endpoints of the bins. c. Check that the area under the histogram on bin \((1000,1500]\) is equal to the increase \(F_{n}(1500)-F_{n}(1000)\) of the empirical distribution function on this bin. Actually, this is true for each single bin (see Exercise 15.11).
Step-by-Step Solution
VerifiedKey Concepts
Histogram Analysis
Creating a histogram involves several steps:
- Choose suitable bin ranges: The range you select influences how your data distribution looks. For example, in our problem, bins such as \([0, 500]\) and \((500, 1000]\) are used.
- Count data points in each bin: For each bin, like \([0, 500]\), you count how many data points lie in this interval. This count represents how dense this specific interval is with respect to your entire data set.
- Calculate the height of the bars: Each bin's height is computed by dividing the count of data points in the bin by the total number of data points, giving a probability density expression.
Probability Density
When engaged with a histogram, each bar's height essentially represents a type of probability density for the data that fall within that bin. It informs us of how 'densely packed' the data is in that specific section.
- Formula Insight: The height of each histogram bar is determined by dividing the number of data points in a bin by the total count of the data. Therefore, the probability density function in each section is
\[ ext{Height} = \frac{\text{Number of Data Points in Bin}}{\text{Total Data Points}} \] - Integral of probabilities: Across an entire distribution, if you were to sum up or integrate these probabilities over all possible outcomes, it should equal 1. This allows histograms in probability density functions to provide insights into the continuous likelihoods across segments of data.
Empirical Cumulative Distribution Function (ECDF)
Here's how the ECDF translates within our context:
- Starting point: Begin with an initial probability of 0 for any value lower than the minimum data value.
- Cumulative calculation: Progressively add the probability mass from each new bin. So at any endpoint, the ECDF gives the total probability of data points falling within that range or less.
- Endpoint values: For certain bin thresholds such as 500, 1000, etc., the ECDF values represent cumulative probabilities, like the portion of data less than or equal to these thresholds had been accounted for.