Problem 4
Question
The orbital speed of Jupiter is (A) greater than the orbital speed of earth. (B) lesser than the orbital speed of earth. (C) equal to the orbital speed of earth. (D) Zero.
Step-by-Step Solution
Verified Answer
The orbital speed of Jupiter is (B) lesser than the orbital speed of Earth.
1Step 1: Find the orbital speed formula
The orbital speed (v) of a celestial body can be determined using the following formula:
\(v = \sqrt{\frac{GM}{r}}\)
where:
- v = orbital speed
- G = gravitational constant (\(6.674 \times 10^{-11} Nm^2/kg^2\))
- M = mass of the central body (the Sun in our case)
- r = distance between the celestial body and the central body (orbital distance)
This formula will be useful for determining and comparing the orbital speeds of both Jupiter and Earth.
2Step 2: Find the orbital distances of Jupiter and Earth
The distance between the Sun and Jupiter is approximately 778 million kilometers, and the distance between the Sun and Earth is approximately 150 million kilometers. For the purpose of calculating orbital speeds, we will use these values:
- Jupiter's orbital distance (rJ) = \(778 \times 10^6 km\)
- Earth's orbital distance (rE) = \(150 \times 10^6 km\)
3Step 3: Calculate the orbital speeds
Using the orbital speed formula and the values of the orbital distances, we can calculate Jupiter's and Earth's orbital speeds:
- Jupiter's orbital speed: \(v_J = \sqrt{\frac{GM}{r_J}}\)
- Earth's orbital speed: \(v_E = \sqrt{\frac{GM}{r_E}}\)
Keep in mind that the mass of the Sun (M) and the gravitational constant (G) are the same for both celestial bodies.
4Step 4: Compare the orbital speeds
We don't need the exact values of orbital speeds for determining the answer. We can just compare the distances in the denominators of the formula. Since the orbital distance of Jupiter is greater than Earth's (rJ > rE), and they divide the same value (GM), the result will be smaller for the planet with a greater distance. Therefore:
- Jupiter's orbital speed: \(v_J < v_E\)
5Step 5: Choose the correct option
Based on our comparison, Jupiter's orbital speed is lesser than the Earth's orbital speed. Therefore, the correct option is:
(B) lesser than the orbital speed of Earth.
Other exercises in this chapter
Problem 1
The Fig. \(7.9\) shows a planet in elliptical orbit around the sun \(S\). Where is the kinetic energy of the planet maximum? (A) \(P_{1}\) (B) \(P_{2}\) (C) \(P
View solution Problem 2
The ratio of the radii of the planets \(P_{1}\) and \(P_{2}\) is \(k_{1}\). The ratio of the acceleration due to the gravity on them is \(k_{2}\). The ratio of
View solution Problem 5
The period of a satellite in a circular orbit of radius \(R\) is \(T\). The period of another satellite in a circular orbit of radius \(4 R\) is (A) \(4 T\) (B)
View solution Problem 6
The period of a satellite in a circular orbit around a planet is independent of, (A) the mass of the planet. (B) the radius of the planet. (C) the mass of the s
View solution