Problem 4
Question
The following questions are about the rational function $$ r(x)=\frac{(x+1)(x-2)}{(x+2)(x-3)} $$ The function \(r\) has \(y\) -intercept __________.
Step-by-Step Solution
Verified Answer
The y-intercept is \( \frac{1}{3} \).
1Step 1: Find the y-intercept Formula
The y-intercept of a function is the y-value of the function when x is zero. For the function \( r(x) \), this means evaluating \( r(0) \).
2Step 2: Substitute x=0 into the Function
Substitute \( x = 0 \) into the function \( r(x) = \frac{(x+1)(x-2)}{(x+2)(x-3)} \). This results in evaluating \( r(0) = \frac{(0+1)(0-2)}{(0+2)(0-3)} \).
3Step 3: Simplify the Expression
Simplify the expression:- The numerator becomes \((1)(-2) = -2\).- The denominator becomes \((2)(-3) = -6\). Thus, \( r(0) = \frac{-2}{-6} \).
4Step 4: Simplify the Fraction
Simplify the fraction \( \frac{-2}{-6} \) by dividing the numerator and the denominator by their greatest common divisor, which is 2. This simplifies to \( \frac{1}{3} \).
5Step 5: Write the Final Answer
The y-intercept of the function \( r(x) = \frac{(x+1)(x-2)}{(x+2)(x-3)} \) is \( \frac{1}{3} \).
Key Concepts
y-interceptfunction evaluationsimplifying expressionsfractions
y-intercept
The y-intercept of a function is found where the graph crosses the y-axis. This happens when the value of x is zero. To find the y-intercept of a function like a rational one, we substitute x = 0 into the function and solve for y. In this instance, for the function \( r(x) = \frac{(x+1)(x-2)}{(x+2)(x-3)} \), substituting 0 for x, we get \( r(0) = \frac{(0+1)(0-2)}{(0+2)(0-3)} \). This substitution simplifies the function and lets us evaluate it at a specific point without needing complicated graph analysis.
function evaluation
Evaluating a function involves substituting a specific value for each variable in the function. For a rational function like \( r(x) = \frac{(x+1)(x-2)}{(x+2)(x-3)} \), evaluating r at x = 0 means replacing every instance of x with 0. Function evaluation allows us to find specific points on the graph of the function. In this case, it helps us to find the y-intercept by calculating \( r(0) = \frac{1 \cdot (-2)}{2 \cdot (-3)} \), which is \( \frac{-2}{-6} \). By plugging in the numbers, you get a numerical result that makes the problem-solving process straightforward.
simplifying expressions
Simplifying an expression means reducing it to its simplest form. This often involves combining like terms or reducing fractions. In our example, after substituting x = 0, we have the expression \( \frac{(-2)}{(-6)} \). Each term is multiplied or divided as needed to make the expression more manageable. In the expression \( 1 \cdot (-2) = -2 \) and \( 2 \cdot (-3) = -6 \), simplifying means ensuring that both the numerator and denominator are reduced as much as possible, which prepares the expression for further simplification.
fractions
Fractions combine a numerator and a denominator to represent a part of a whole. Simplifying a fraction like \( \frac{-2}{-6} \) involves identifying the greatest common divisor (GCD) of both numbers. In this case, the GCD is 2. To simplify the fraction, you divide both the top and bottom by this number: \( \frac{-2}{-6} = \frac{1}{3} \). The result is a fraction that represents the same quantity but in the simplest form, making it easier to understand and work with further. Learning to simplify fractions is a valuable skill that is frequently used in math.
Other exercises in this chapter
Problem 3
The graph of \(f(x)=2(x-3)^{2}+5\) is a parabola that opens _________ with its vertex at (_______ _____) and \(f(3)=\) ________ is the (minimum/maximum) _______
View solution Problem 3
If \(c\) is a zero of the polynomial \(P,\) which of the following statements must be true? (a) \(P(c)=0\) (b) \(P(0)=c\) (c) \(x-c\) is a factor of \(P(x)\) (d
View solution Problem 4
If the polynomial function \(P\) has real coefficients and if \(a+b i\) is a zero of \(P,\) then ____ is also a zero of \(P\).
View solution Problem 4
If \(3+4 i\) is a solution of a quadratic equation with real coefficients, then ______________is also a solution of the equation.
View solution