Problem 4
Question
The center of a group \(G\) is the normal subgroup \(C\) of \(G\) consisting of all those elements of \(G\) which commute with every element of \(G\). Suppose the quotient group \(G / C\) is a cyclic group; say it is generated by the element \(C a\) of \(G / C\). Prove each of the following: Conclude that if \(G / C\) is cyclic, then \(G\) is abelian.
Step-by-Step Solution
Verified Answer
If \(G / C\) is cyclic, then every element in \(G\) commutes, making \(G\) abelian.
1Step 1: Understanding the Definitions
We are given that the center of a group \(G\) is the normal subgroup \(C\) of \(G\), consisting of all elements of \(G\) that commute with every element of \(G\). This means for any element \(c \in C\), \(cg = gc\) for all \(g \in G\). We also know \(G / C\) is a cyclic group generated by \(Ca\) for some \(a \in G\).
2Step 2: Expressing Elements of Quotient Group
Since \(G / C\) is generated by \(Ca\), every element of \(G / C\) can be written as \((Ca)^n\) for some integer \(n\). This implies each element of \(G\) is of the form \(a^n c\) where \(c \in C\).
3Step 3: Proving Commutativity
To prove \(G\) is abelian, we need to show that any two elements in \(G\) commute. Consider two arbitrary elements \(g = a^m c_1\) and \(h = a^n c_2\) of \(G\) where \(c_1, c_2 \in C\). Then, their product is \(gh = (a^m c_1)(a^n c_2) = a^m a^n c_1 c_2\).
4Step 4: Using Properties of the Center and Cyclic Group
Since elements of the center \(C\) commute with all elements of \(G\), \(c_1 a^n = a^n c_1\) and \(c_2 a^m = a^m c_2\). Thus, \(gh = a^{m+n} c_1 c_2 = a^{m+n} c_2 c_1\).
5Step 5: Concluding Commutativity of Elements
Similarly, we find \(hg = a^n a^m c_2 c_1 = a^{n+m} c_2 c_1\). Since \(m + n = n + m\) in integers, we have \(gh = hg\). Hence every pair of elements in \(G\) commute.
6Step 6: Final Conclusion
From the above arguments, since every pair of elements in \(G\) commute, \(G\) is an abelian group.
Key Concepts
Cyclic Quotient GroupNormal SubgroupAbelian GroupCommutative Property
Cyclic Quotient Group
In group theory, a quotient group (or factor group) is a mathematical concept that involves partitioning a group, denoted as \( G \), by a normal subgroup \( C \). When the quotient group \( G/C \) is cyclic, it means that there exists an element in \( G/C \), often expressed as \( Ca \), that can generate every other element in the group by powering, which is multiplying it by itself repeatedly. For instance, if \( G/C \) is cyclic and generated by \( Ca \), then every element in \( G/C \) can be written in the form \((Ca)^n\), with \( n \) being an integer. This characteristic implies a certain regular structure within the group, as all elements are derived from a single source or generator. Cyclic groups are fundamentally simple to understand as they are essentially just repeated applications of the group operation on the generator. This cyclic nature plays a crucial role in determining other structural properties of \( G \).
This generator concept simplifies the understanding of the group's structure, allowing the connection to be made that if \( G/C \) is cyclic, \( G \) may exhibit more straightforward behaviors, such as being an abelian group.
This generator concept simplifies the understanding of the group's structure, allowing the connection to be made that if \( G/C \) is cyclic, \( G \) may exhibit more straightforward behaviors, such as being an abelian group.
Normal Subgroup
A normal subgroup \( C \) of a group \( G \) is a subgroup where any element \( c \in C \) commutes with all elements of \( G \) if conjugated. That means for any \( g \in G \), the element \( g^{-1}cg \) will still lie within \( C \). The center of a group, \( C \), is a particular instance of a normal subgroup.
- It contains elements that commute with every element in \( G \).
- If you take any \( c \in C \) and any \( g \in G \), then you have \( cg = gc \).
Abelian Group
An abelian group is a group where every pair of elements commutes. This means for any two elements \( g \) and \( h \) in the group, their product is independent of the order they are multiplied in, i.e., \( gh = hg \). In our context, proving some
The primary understanding is that due to the regularity imposed by the cyclic nature and the central elements, every multiplication conforms to commutative laws. This sets \( G \) apart as abelian, as demonstrated through step-by-step verification of commutativity across any product of elements derived from \( a^n \) and a central element. Abelian groups offer simpler mathematical structures and are prevalent in various applications due to their ordered interaction.
- that if \( G/C \) is cyclic, then \( G \) is abelian.
- Elements of the form \( a^n c \) (for any \( c \in C \)) preserve commutative properties when multiplied.
The primary understanding is that due to the regularity imposed by the cyclic nature and the central elements, every multiplication conforms to commutative laws. This sets \( G \) apart as abelian, as demonstrated through step-by-step verification of commutativity across any product of elements derived from \( a^n \) and a central element. Abelian groups offer simpler mathematical structures and are prevalent in various applications due to their ordered interaction.
Commutative Property
The commutative property refers to the principle where the order of operations does not alter the result. In the context of group theory, it implies that for any elements \( g \) and \( h \) in a group \( G \), the equation \( gh = hg \) always holds true.
This fundamental property is pivotal when discussing abelian groups. If a group is abelian, by the definition, it satisfies the commutative property.
This fundamental property is pivotal when discussing abelian groups. If a group is abelian, by the definition, it satisfies the commutative property.
- This property simplifies the group operation, offering predictability and allowing for vast simplifications in proofs and applications.
- In the problem at hand, the commutativity of elements within \( G \) was established due to the underlying structure imposed by the cyclic quotient group \( G/C \).
Other exercises in this chapter
Problem 3
Let \(G\) be a group, and \(H\) a normal subgroup of \(G\). Prove the following: If \((G: H)=p\), where \(p\) is a prime, then the order of every element \(a \n
View solution Problem 3
There are some group properties which, if they are true in \(G / H\) and in \(H\), must be true in \(G .\) Here is a sampling. Let \(G\) be a group, and \(H\) a
View solution Problem 4
Let \(G\) be a group, and \(H\) a normal subgroup of \(G\). Prove the following: If \(G\) has a normal subgroup of index \(p\), where \(p\) is a prime, then \(G
View solution Problem 4
There are some group properties which, if they are true in \(G / H\) and in \(H\), must be true in \(G .\) Here is a sampling. Let \(G\) be a group, and \(H\) a
View solution