Problem 4
Question
Suppose (2,-3) is on the graph of \(y=f(x) .\) In Exercises \(1-18,\) use Theorem 1.7 to find a point on the graph of the given transformed function. $$ y=f(x-1) $$
Step-by-Step Solution
Verified Answer
The transformed point is (3, -3).
1Step 1: Understanding the Given Function
We start by noting that the original point (2, -3) lies on the graph of \(y=f(x)\). This means that when \(x=2\), the value of \(f(x)\) is -3, i.e., \(f(2)=-3\).
2Step 2: Identify the Transformation
The transformation given is \(y=f(x-1)\). This is a horizontal shift to the right by 1 unit. According to Theorem 1.7, this shift means we replace \(x\) with \(x-1\) in the function.
3Step 3: Apply Transformation to the Point
To find the new x-coordinate, add 1 to the original x-coordinate of the point (2, -3), because shifting right by 1 unit means we need to find \(x-1 = 2\). Solving gives \(x = 3\).
4Step 4: Determine the New Point
Since the transformation only affects the x-coordinate of the point, the new point will be \((3, -3)\). The y-coordinate remains unchanged as we are only shifting the point horizontally.
Key Concepts
Horizontal ShiftGraphing FunctionsTheorem 1.7
Horizontal Shift
When we talk about a horizontal shift in the context of function transformations, it refers to moving the entire graph of a function left or right along the x-axis. This happens without modifying the shape of the graph.
A horizontal shift can be recognized in a function as a change in the inside part of the function's argument. For example, in the function given in the problem, we have a horizontal shift:
A horizontal shift can be recognized in a function as a change in the inside part of the function's argument. For example, in the function given in the problem, we have a horizontal shift:
- In the function \(y = f(x-1)\), the graph shifts 1 unit to the right. This is because subtracting 1 from \(x\) means every x-value in the function has been increased by 1 to maintain the original output of the function.
- Conversely, if we had \(y = f(x+1)\), it would represent a shift to the left by 1 unit, essentially decreasing each x-value by 1.
Graphing Functions
Graphing functions is a fundamental skill in mathematics that allows us to visualize how a function behaves. By graphing, we transform a set of rules or equations into a visual plot that we can analyze.
When you graph a basic function like \(y = f(x)\), you plot points based on inputs \(x\) and their corresponding outputs \(y\).
To track changes in the function's graph, such as a horizontal shift:
When you graph a basic function like \(y = f(x)\), you plot points based on inputs \(x\) and their corresponding outputs \(y\).
To track changes in the function's graph, such as a horizontal shift:
- Start with the original function's points, like (2, -3) in the exercise.
- Apply any given transformations and calculate the new positions of the key points.
- Plot the new points using these adjusted coordinates. In our example, after shifting, the point becomes (3, -3).
Theorem 1.7
Theorem 1.7 provides a mathematical framework for applying transformations to functions, simplifying the understanding of how various components of a function change its graph.
In the context of the exercise problem, Theorem 1.7 helps us understand how to modify the point according to the transformation described by \(y = f(x-1)\). This theorem teaches us that:
In the context of the exercise problem, Theorem 1.7 helps us understand how to modify the point according to the transformation described by \(y = f(x-1)\). This theorem teaches us that:
- When a transformation replaces \(x\) with \(x-c\), the graph of the function shifts horizontally by \(c\) units.
- Specifically, if the penalty in the equation is subtraction, as with \(x-1\), the graph moves to the right.
- If it were \(x+c\), the shift would be to the left.
Other exercises in this chapter
Problem 3
Graph the given relation. $$ \\{(m, 2 m) \mid m=0,\pm 1,\pm 2\\} $$
View solution Problem 3
Find the indicated intersection or union and simplify if possible. Express your answers in interval notation. $$ (-1,1) \cup[0,6] $$
View solution Problem 4
In Exercises \(1-12\), sketch the graph of the given function. State the domain of the function, identify any intercepts and test for symmetry. $$ f(x)=4-x^{2}
View solution Problem 4
Use the pair of functions \(f\) and \(g\) to find the following values if they exist. $$ \begin{array}{lll} \bullet(f+g)(2) & \bullet(f-g)(-1) & \bullet(g-f)(1)
View solution