Problem 4
Question
State what conclusion, if any, may be drawn from the Divergence Test. $$ \sum_{n=1}^{\infty} \frac{3^{n}}{3^{n}+4} $$
Step-by-Step Solution
Verified Answer
The series diverges by the Divergence Test.
1Step 1: Understand the Divergence Test
The Divergence Test states that for an infinite series \( \sum_{n=1}^{\infty} a_n \), if \( \lim_{n \to \infty} a_n eq 0 \), then the series diverges. However, if \( \lim_{n \to \infty} a_n = 0 \), the test is inconclusive and does not provide information about convergence.
2Step 2: Identify the Term of the Series
The given series is \( \sum_{n=1}^{\infty} \frac{3^{n}}{3^{n}+4} \). The term of the series is \( a_n = \frac{3^n}{3^n + 4} \). We will use this to apply the Divergence Test.
3Step 3: Compute the Limit of the Terms
Calculate \( \lim_{n \to \infty} a_n \).\[\lim_{n \to \infty} \frac{3^n}{3^n + 4} = \lim_{n \to \infty} \frac{3^n}{3^n (1 + \frac{4}{3^n})} = \lim_{n \to \infty} \frac{1}{1 + \frac{4}{3^n}} = \frac{1}{1 + 0} = 1\]
4Step 4: Apply the Divergence Test
Since \( \lim_{n \to \infty} a_n = 1 eq 0 \), according to the Divergence Test, the series \( \sum_{n=1}^{\infty} \frac{3^n}{3^n + 4} \) diverges.
Key Concepts
Infinite SeriesConvergence and DivergenceLimits in Calculus
Infinite Series
An infinite series is the sum of the terms of an infinite sequence. Think of it as adding up numbers forever. Mathematically, it is expressed as \( \sum_{n=1}^{\infty} a_n \). Here, \( \sum \) denotes a sum, and \( n \) starts from 1 and goes to infinity.
- Each individual term in the sequence is represented by \( a_n \).
- An infinite series may converge to a specific value or diverge, meaning it doesn't settle at any particular value.
Convergence and Divergence
Convergence and divergence are fundamental properties of an infinite series. When we talk about the convergence of a series, it means that as we add more and more terms, the sum approaches a certain finite value. If a series does not converge, it diverges. This means either the series grows indefinitely or oscillates without approaching a specific value.
- Convergent Series: The sum stabilizes to a finite number.
- Divergent Series: The sum keeps increasing or decreases without limit, or fluctuates endlessly.
Limits in Calculus
In calculus, the concept of a limit helps us understand the behavior of functions as they approach a specific point or infinity. It is a foundational idea that supports the definition of derivatives, integrals, and infinite series.When analyzing an infinite series, calculating the limit of its terms \( a_n \) as \( n \to \infty \) tells us something crucial:
- If the limit \( \lim_{n \to \infty} a_n \) equals zero, the series might still converge, but not necessarily.
- If this limit is not zero, the series definitely diverges, as supported by the Divergence Test.
Other exercises in this chapter
Problem 4
Use the Comparison Test for Convergence to show that the given series converges. State the series that you use for comparison and the reason for its convergence
View solution Problem 4
Evaluate \(\lim _{n \rightarrow \infty} a_{n}\) for the given sequence \(\left\\{a_{n}\right\\}\). $$ a_{n}=\frac{3^{2 n}+2}{9^{n+1}+1} $$
View solution Problem 5
Express the given function as a power series in \(x\) with base point \(0 .\) Calculate the radius of convergence \(R\). \(\frac{1}{4+x}\)
View solution Problem 5
Use the Ratio Test to determine the convergence or divergence of the given series. \(\sum_{n=1}^{\infty} \frac{n^{100}}{n !}\)
View solution