Problem 4
Question
Solve the differential equations in Exercises \(1-14\) $$y^{\prime}+(\tan x) y=\cos ^{2} x, \quad-\pi / 2 < x < \pi / 2$$
Step-by-Step Solution
Verified Answer
The solution is \( y = \sin x \cos x + C \cos x \).
1Step 1: Identify the Type of Differential Equation
The given differential equation is of the form \( y' + P(x)y = Q(x) \) with \( P(x) = \tan x \) and \( Q(x) = \cos^2 x \). This is a first-order linear differential equation.
2Step 2: Find the Integrating Factor
The integrating factor \( \mu(x) \) is given by \( e^{\int P(x) \, dx} = e^{\int \tan x \, dx} \). The integral of \( \tan x \) is \( -\ln |\cos x| \), so the integrating factor is \( \mu(x) = e^{\ln |\sec x|} = \sec x \).
3Step 3: Multiply through by the Integrating Factor
Multiply the entire differential equation by the integrating factor \( \sec x \): \[ \sec x y' + y \cdot \sec x \tan x = \cos x. \] This simplifies to \[ \frac{d}{dx}(y \cdot \sec x) = \cos x. \]
4Step 4: Integrate Both Sides
Integrate both sides of the equation: \[ \int \frac{d}{dx}(y \cdot \sec x) \, dx = \int \cos x \, dx. \] This gives \[ y \cdot \sec x = \sin x + C, \] where \( C \) is the integration constant.
5Step 5: Solve for y
Multiply both sides by \( \cos x \) to solve for \( y \): \[ y = \sin x \cos x + C \cos x. \]
Key Concepts
Integrating FactorDifferential EquationsSolutions of Differential EquationsTrigonometric Functions
Integrating Factor
In the world of differential equations, the integrating factor is a crucial tool for simplifying first-order linear differential equations. An integrating factor is essentially a function that, when multiplied by the original differential equation, makes it easier to solve. It transforms the equation into one where the left-hand side becomes the derivative of a product of functions. This allows for direct integration to find the solution.
To determine the integrating factor, we compute \[ \mu(x) = e^{\int P(x) \, dx} \]where \( P(x) \) is the coefficient of \( y \) in the equation \( y' + P(x) y = Q(x) \). In our example, \( P(x) = \tan x \). The integrating factor hence becomes \[ \mu(x) = e^{\int \tan x \, dx} = e^{-\ln |\cos x|} = \sec x. \]Applying the integrating factor transforms the differential equation into a form that can be easily integrated on both sides. This is why the integrating factor is such a powerful concept in solving linear differential equations.
To determine the integrating factor, we compute \[ \mu(x) = e^{\int P(x) \, dx} \]where \( P(x) \) is the coefficient of \( y \) in the equation \( y' + P(x) y = Q(x) \). In our example, \( P(x) = \tan x \). The integrating factor hence becomes \[ \mu(x) = e^{\int \tan x \, dx} = e^{-\ln |\cos x|} = \sec x. \]Applying the integrating factor transforms the differential equation into a form that can be easily integrated on both sides. This is why the integrating factor is such a powerful concept in solving linear differential equations.
Differential Equations
Differential equations are equations that relate a function with its derivatives. These can be used to model a wide array of real-world systems, such as physics dynamics, population growth, or electrical circuits. In essence, they are crucial for understanding how changing rates affect systems.
Our given differential equation \( y' + \tan x y = \cos^2 x \) is a first-order linear differential equation. This means that it involves the first derivative of \( y \), which is \( y' \), and the terms \( y \) and \( x \) themselves, but no higher derivatives or powers of \( y \).
Understanding these types of equations involves identifying their form, which can often be written as \( y' + P(x) y = Q(x) \). Solving these equations often requires techniques like finding the integrating factor, which helps to make them solvable by standard integration methods.
Our given differential equation \( y' + \tan x y = \cos^2 x \) is a first-order linear differential equation. This means that it involves the first derivative of \( y \), which is \( y' \), and the terms \( y \) and \( x \) themselves, but no higher derivatives or powers of \( y \).
Understanding these types of equations involves identifying their form, which can often be written as \( y' + P(x) y = Q(x) \). Solving these equations often requires techniques like finding the integrating factor, which helps to make them solvable by standard integration methods.
Solutions of Differential Equations
Once we've utilized techniques like determining the integrating factor, we can proceed to solve the differential equation. The solution process generally involves these steps:
Finally, to solve for \( y \), we isolate it by multiplying both sides by \( \cos x \), giving us the solution:
\[ y = \sin x \cos x + C \cos x \]
This represents a family of functions that solve the differential equation, each different \( C \) corresponding to a specific solution depending on initial conditions or further constraints.
- Identifying the type and structure of the differential equation.
- Finding and applying the integrating factor to transform the equation.
- Integrating both sides to find the general solution.
- Solving for the original function \( y \) if necessary.
Finally, to solve for \( y \), we isolate it by multiplying both sides by \( \cos x \), giving us the solution:
\[ y = \sin x \cos x + C \cos x \]
This represents a family of functions that solve the differential equation, each different \( C \) corresponding to a specific solution depending on initial conditions or further constraints.
Trigonometric Functions
Trigonometric functions play a significant role when working with differential equations, especially when the equations are defined over specific intervals involving angles. Functions like sine, cosine, and tangent frequently appear in problems due to their periodicity and relationships with angles in radians, which are crucial in physics and engineering.
In our differential equation, we encountered \( \tan x \) and \( \cos^2 x \) as key components. The tangent function is particularly interesting as its derivative has trigonometric relationships that can simplify through integration, as seen in the integrating factor's calculation: \( \int \tan x \, dx = -\ln |\cos x| \).
By understanding these functions and their derivatives, we can simplify and solve equations that might otherwise seem complex. Mastery of trigonometric identities and integration techniques is vital in addressing differential equations like these efficiently.
In our differential equation, we encountered \( \tan x \) and \( \cos^2 x \) as key components. The tangent function is particularly interesting as its derivative has trigonometric relationships that can simplify through integration, as seen in the integrating factor's calculation: \( \int \tan x \, dx = -\ln |\cos x| \).
By understanding these functions and their derivatives, we can simplify and solve equations that might otherwise seem complex. Mastery of trigonometric identities and integration techniques is vital in addressing differential equations like these efficiently.
Other exercises in this chapter
Problem 3
Solve the differential equations in Exercises \(1-14\) $$x y^{\prime}+3 y=\frac{\sin x}{x^{2}}, \quad x>0$$
View solution Problem 4
In Exercises \(1-8\) \begin{equation}\begin{array}{l}{\text { a. Identify the equilibrium values. Which are stable and which }} \\ {\text { are unstable? }} \\
View solution Problem 5
Consider another competitive-hunter model defined by $$ \begin{aligned} \frac{d x}{d t} &=a\left(1-\frac{x}{k_{1}}\right) x-b x y \\\ \frac{d y}{d t} &=m\left(1
View solution Problem 5
In Exercises \(1-8\) \begin{equation}\begin{array}{l}{\text { a. Identify the equilibrium values. Which are stable and which }} \\ {\text { are unstable? }} \\
View solution