Problem 4
Question
Solve each quadratic equation by using (a) the factoring method and (b) the method of completing the square. $$x^{2}-18 x=-72$$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 6\) and \(x = 12\).
1Step 1: Bring equation to standard form
The given equation is \(x^2 - 18x = -72\). First, move 72 to the left side to form a standard quadratic equation: \(x^2 - 18x + 72 = 0\).
2Step 2: Factoring the quadratic equation
To factor the equation \(x^2 - 18x + 72 = 0\), find two numbers that multiply to 72 and add to -18. The numbers -6 and -12 satisfy this condition: \((x - 6)(x - 12) = 0\).
3Step 3: Solve the factored equation
Set each factor equal to zero: \(x - 6 = 0\) and \(x - 12 = 0\). Solving these gives \(x = 6\) and \(x = 12\).
4Step 4: Completing the square—rearrange and halve the middle coefficient
Start with \(x^2 - 18x = -72\). To complete the square, rearrange to \(x^2 - 18x = c\). Calculate \((-18/2)^2 = 81\) and add it to both sides: \(x^2 - 18x + 81 = 9\).
5Step 5: Express as a perfect square trinomial
The left side becomes a perfect square: \((x - 9)^2 = 9\).
6Step 6: Solve by taking the square root
Take the square root of both sides: \(x - 9 = \pm 3\). This gives two equations: \(x - 9 = 3\) and \(x - 9 = -3\).
7Step 7: Solve for x
Solving the two equations: \(x = 12\) and \(x = 6\).
Key Concepts
Factoring MethodCompleting the SquareStandard Form of Quadratics
Factoring Method
The factoring method is a simple and efficient technique for solving quadratic equations. This method involves expressing the quadratic equation in the form of a product of two lininear binomials. For the original equation \(x^2 - 18x + 72 = 0\), the goal is to find two numbers that multiply to 72 (the constant term) and add to -18 (the coefficient of the linear term).
- Identify factors: Begin by listing pairs of numbers whose product is 72. For example, 1 and 72, 2 and 36, 3 and 24, and so on.
- Select suitable factors: Look for the pair that adds up to -18. The correct pair is -6 and -12, as they multiply to 72 and add to -18.
- Rewrite the quadratic: This allows us to rewrite the quadratic as \((x - 6)(x - 12) = 0\).
Completing the Square
Completing the square offers another way to solve quadratic equations. It transforms the quadratic into a perfect square form, which makes solving for \(x\) more manageable.
To complete the square for the quadratic equation \(x^2 - 18x = -72\), the first step is to take the coefficient of \(x\), divide it by two, and then square it:
To complete the square for the quadratic equation \(x^2 - 18x = -72\), the first step is to take the coefficient of \(x\), divide it by two, and then square it:
- Determine the number to add and subtract: Take \(-18\), halve it to get \(-9\), then square \(-9\) to get 81.
- Adjust the equation: Add 81 to both sides to keep the equation balanced: \(x^2 - 18x + 81 = 9\).
Standard Form of Quadratics
The standard form of a quadratic equation is \[ax^2 + bx + c = 0\]. This form is crucial as it sets the foundation for both the factoring method and completing the square. It organizes the terms in a way that is most useful for solving the equations. For our original problem, the equation \(x^2 - 18x = -72\) was first transformed to the standard form \(x^2 - 18x + 72 = 0\).
- General form: Every quadratic equation can be rearranged into the standard form.
- Consistency: The standard form ensures you're set up to use various solving methods efficiently.
- Identify coefficients: From \(x^2 - 18x + 72 = 0\), here \(a = 1\), \(b = -18\), and \(c = 72\).
Other exercises in this chapter
Problem 4
Solve each quadratic equation using the method that seems most appropriate to you. $$n^{2}+22 n+105=0$$
View solution Problem 4
First use the discriminant to determine whether the equation has two nonreal complex solutions, one real solution with a multiplicity of two, or two real soluti
View solution Problem 4
Solve each of the quadratic equations by factoring and applying the property, \(a b=0\) if and only if \(a=0\) or \(b=0\). If necessary, return to Chapter 3 and
View solution Problem 4
Label each statement true or false. Every complex number is a pure imaginary number.
View solution