Problem 4
Question
Solve each equation. \(\frac{-5 x}{4}=\frac{7}{2}\)
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{-14}{5}\).
1Step 1: Cross Multiply
To eliminate the fractions, cross multiply the terms: \((-5x) \times 2 = 7 \times 4\). This simplifies to \(-10x = 28\).
2Step 2: Isolate x
Divide both sides of the equation by -10 to solve for \(x\). \(x = \frac{28}{-10}\).
3Step 3: Simplify the Fraction
Simplify the fraction \(\frac{28}{-10}\) to its lowest terms. The greatest common divisor of 28 and 10 is 2, so divide both by 2: \(x = \frac{-14}{5}\).
Key Concepts
Cross MultiplicationFraction SimplificationIsolation of Variable
Cross Multiplication
Cross multiplication is a handy technique used to solve equations involving fractions. It helps to eliminate the fractions by multiplying across the equation. Here’s how it works in simple terms.First, identify the two fractions that need attention. In the original exercise, we have \[\frac{-5x}{4} = \frac{7}{2}\]To cross multiply these fractions, take the numerator of each fraction and multiply it by the denominator of the other fraction. Therefore, multiply \((-5x)\) by \(2\) and \(7\) by \(4\). This results in:\[(-5x) \times 2 = 7 \times 4\]Simplifying those products gives you a new equation without fractions:\[-10x = 28\]This eradicates the need to deal with separate fractions, making it easier to solve for the variable in the next steps.
Fraction Simplification
Simplifying fractions is an essential skill in mathematics, helping to reduce complexity in calculations and find the solution more easily. Let’s break this process down using the result from cross multiplication.After performing cross multiplication, you arrived at a fraction: \[x = \frac{28}{-10}\]To simplify a fraction, find the greatest common divisor (GCD) of the numerator and the denominator. The GCD is the largest number that divides both numbers without leaving a remainder.
- For 28 and 10, the GCD is 2.
- Numerator: \(28 \div 2 = 14\)
- Denominator: \(-10 \div 2 = -5\)
Isolation of Variable
The isolation of a variable is the process of solving for a specific variable within an equation. This technique makes an unknown variable stand alone on one side of the equation. In solving linear equations, it turns complex problems into simpler, manageable forms.In the original example, after obtaining the equation \[-10x = 28\], our goal is to solve for \(x\). To isolate \(x\), divide both sides of the equation by the coefficient attached to \(x\), which is \(-10\).This calculation looks like:\[x = \frac{28}{-10}\]By dividing, you effectively "cancel out" the \(-10\) from the left side, leaving \(x\) by itself:
- This operation is key for isolating \(x\) and reaching a solution.
Other exercises in this chapter
Problem 4
Solve \(i=P r t\) for \(t\), given that \(P=\$ 250, r=12 \%\), and \(i=\$ 120\).
View solution Problem 4
Solve each equation. \(0.07 y=0.42\)
View solution Problem 4
Solve each equation. \(7 x+4=-31\)
View solution Problem 5
Solve each inequality and graph the solutions. \(|x|>2\)
View solution